Question Number 125851 by harckinwunmy last updated on 14/Dec/20 $$\mathrm{calculate}\:\mathrm{the}\:\mathrm{product}\:\mathrm{of}\:\mathrm{the}\:\mathrm{1st}\:\mathrm{and}\:\mathrm{4th}\:\mathrm{terms}\: \\ $$$$\mathrm{of}\:\mathrm{the}\:\mathrm{sequence}\:\mathrm{whose}\:\mathrm{mth}\:\mathrm{term}\:\mathrm{is}\:\mathrm{defined}\:\mathrm{as} \\ $$$$\psi_{\mathrm{m}+\mathrm{1}} =\left(\mathrm{3}^{\mathrm{m}} \right)\left(−\mathrm{2}\right)^{\mathrm{m}−\mathrm{1}} \\ $$ Answered by floor(10²Eta[1]) last updated on 14/Dec/20…
Question Number 125847 by zarminaawan last updated on 14/Dec/20 $${Discuss}\:{the}\:{continuity}\:{of}\:{functionf}\left({x}\right)={xtan}\left(\frac{\mathrm{1}}{{x}}\right)\:{at}\:{x}=\mathrm{0}\:{given}\:{tht}\:{x}\neq\mathrm{0}\:{and}\:{f}\left(\mathrm{0}\right)=\mathrm{0} \\ $$ Answered by mindispower last updated on 14/Dec/20 $${tan}\left({y}\right)>{y},\forall{y}\geqslant\mathrm{0}…? \\ $$$${we}\:{have} \\ $$$$\mathrm{1}+{tg}^{\mathrm{2}} \left({t}\right)\geqslant\mathrm{1}…
Question Number 125845 by joki last updated on 14/Dec/20 $${use}\:{subtitution}\:{x}={a}\:{sin}\theta\:{to}\:{find}\:\int\frac{\mathrm{1}}{\:\sqrt{\mathrm{9}−{x}^{\mathrm{2}} }} \\ $$ Answered by MJS_new last updated on 14/Dec/20 $$\int\frac{{dx}}{\:\sqrt{\mathrm{9}−{x}^{\mathrm{2}} }}= \\ $$$$\:\:\:\:\:\left[{x}=\mathrm{3sin}\:\theta\:\Leftrightarrow\:\theta=\mathrm{arcsin}\:\frac{{x}}{\mathrm{3}}\:\rightarrow\:{dx}=\sqrt{\mathrm{9}−{x}^{\mathrm{2}} }{d}\theta\right]…
Question Number 60304 by ANTARES VY last updated on 19/May/19 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 125837 by joki last updated on 14/Dec/20 $${prove}\:{that}\:: \\ $$$$\int\sqrt{{a}^{\mathrm{2}} −{x}^{\mathrm{2}} }{dx}=_{} \frac{{x}}{\mathrm{2}}\sqrt{{a}^{\mathrm{2}} −{x}^{\mathrm{2}} }+\frac{{a}^{\mathrm{2}} }{\mathrm{2}}{sin}^{−\mathrm{1}} \left(\frac{{x}}{{a}}\right)+{c} \\ $$ Answered by Dwaipayan Shikari…
Question Number 60287 by naka3546 last updated on 19/May/19 $${f}\left({x}\right)\:\:=\:\:{x}^{\mathrm{3}} \:+\:\mathrm{3}{x}\:−\:\mathrm{7} \\ $$$${f}\:^{−\mathrm{1}} \left({x}\right)\:\:=\:\:? \\ $$ Commented by mr W last updated on 19/May/19 $${f}^{−\mathrm{1}}…
Question Number 125821 by Tinku Tara last updated on 14/Dec/20 $${v}\mathrm{2}.\mathrm{240}\: \\ $$$$\bullet\:\mathrm{You}\:\mathrm{can}\:\mathrm{write}\:\mathrm{plain}\:\mathrm{text}\:\mathrm{using} \\ $$$$\:\:\:\:\mathrm{your}\:\mathrm{phones}\:\mathrm{keyboard}. \\ $$$$\:\:\:\:\mathrm{choose}\:\mathrm{insert}\:\mathrm{plain}\:\mathrm{text}\:\mathrm{from} \\ $$$$\:\:\:\:\mathrm{side}\:\mathrm{bar}.\:\mathrm{Plain}\:\mathrm{text}\:\mathrm{can}\:\mathrm{be} \\ $$$$\:\:\:\:\mathrm{written}\:\mathrm{in}\:\mathrm{any}\:\mathrm{language}. \\ $$$$\bullet\:\mathrm{An}\:\mathrm{additional}\:\mathrm{function}\:\mathrm{of}\:\mathrm{loading} \\ $$$$\:\:\:\:\mathrm{a}\:\mathrm{preview}\:\mathrm{image}\:\mathrm{is}\:\mathrm{available}\:\mathrm{in}…
Question Number 125790 by mohammad17 last updated on 13/Dec/20 Answered by liberty last updated on 13/Dec/20 $$\:\underset{{x}\rightarrow\mathrm{2}} {\mathrm{lim}}\:\frac{\left({x}+\mathrm{2}\right)\left({x}−\mathrm{2}\right)}{\mathrm{sin}\:\pi{x}}\:=\:\mathrm{4}×\underset{{x}\rightarrow\mathrm{2}} {\mathrm{lim}}\:\left[\:\frac{{x}−\mathrm{2}}{\mathrm{sin}\:\pi{x}}\:\right] \\ $$$$\:\left[\:{let}\:{x}=\mathrm{2}+{t}\:\wedge\:{t}\rightarrow\mathrm{0}\:\right]\: \\ $$$$=\:\mathrm{4}×\:\underset{{t}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{{t}}{\mathrm{sin}\:\pi\left({t}+\mathrm{2}\right)}\:=\:\mathrm{4}\:×\underset{{t}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{{t}}{\mathrm{sin}\:\left(\mathrm{2}\pi+\pi{t}\right)}…
Question Number 60240 by ANTARES VY last updated on 19/May/19 $$\underset{\mathrm{0}} {\overset{\mathrm{2}} {\int}}\frac{\boldsymbol{\mathrm{ln}}\left(\boldsymbol{\mathrm{x}}\right)}{\:\sqrt{\mathrm{4}−\boldsymbol{\mathrm{x}}^{\mathrm{2}} }}\boldsymbol{\mathrm{dx}} \\ $$ Commented by maxmathsup by imad last updated on 19/May/19…
Question Number 125758 by ZiYangLee last updated on 13/Dec/20 $$\Delta\mathrm{ABC}\:\mathrm{have}\:\mathrm{the}\:\mathrm{sides}\:\mathrm{of}\:\mathrm{length}\:\mathrm{10}\:\mathrm{13}\:\mathrm{13} \\ $$$$\mathrm{while}\:\Delta\mathrm{PQR}\:\mathrm{have}\:\mathrm{the}\:\mathrm{sides}\:\mathrm{of}\:\mathrm{length} \\ $$$$\mathrm{13}\:\mathrm{13}\:\mathrm{24}. \\ $$$$\mathrm{Find}\:\mathrm{the}\:\mathrm{ratio}\:\mathrm{of}\:\mathrm{Area}\:\mathrm{of}\:\Delta\mathrm{ABC}\::\:\mathrm{Area} \\ $$$$\mathrm{of}\:\Delta\mathrm{PQR}. \\ $$ Answered by mr W last…