Question Number 125739 by ZiYangLee last updated on 13/Dec/20 $$\mathrm{Given}\:\mathrm{that}\:{x}^{{x}^{\mathrm{4}} } =\mathrm{4},\: \\ $$$$\mathrm{find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:{x}^{{x}^{\mathrm{2}} } +{x}^{{x}^{\mathrm{8}} } . \\ $$ Commented by Dwaipayan Shikari last…
Question Number 191254 by anr0h3 last updated on 21/Apr/23 $$ \\ $$$${a}=\frac{{x}−{a}}{{x}−{b}}\:{solve}\:{for}\:{x} \\ $$$$\mathrm{did}\:\mathrm{i}\:\mathrm{make}\:\mathrm{anything}\:\mathrm{wrong}\:\mathrm{in}\:\mathrm{the}\:\mathrm{following}? \\ $$$$ \\ $$$$\mathrm{starpoint}: \\ $$$${ln}\mid{a}\mid={ln}\mid\frac{{x}−{a}}{{x}−{b}}\mid \\ $$$${ln}\mid{a}\mid={ln}\mid{x}−{a}\mid−{ln}\mid{x}−{b}\mid \\ $$$${ln}\mid{a}\mid={ln}\mid\frac{{x}}{{a}}\mid−{ln}\mid\frac{{x}}{{b}}\mid \\…
Question Number 191243 by sonukgindia last updated on 21/Apr/23 Commented by mr W last updated on 21/Apr/23 $${at}\:{x}=\mathrm{1}\:? \\ $$ Answered by PandaMa last updated…
Question Number 125697 by aurpeyz last updated on 13/Dec/20 $${what}\:{is}\:{the}\:{largest}\:{coefficient}\:{of}\: \\ $$$$\left(\mathrm{4}+\mathrm{3}{x}\right)^{−\mathrm{5}} ? \\ $$ Answered by mr W last updated on 13/Dec/20 $$\left(\mathrm{4}+\mathrm{3}{x}\right)^{−\mathrm{5}} \\…
Question Number 60152 by Kunal12588 last updated on 18/May/19 $${Join}\:{Telegram}\:{group} \\ $$$$@{booksforjee} \\ $$$${To}\:{get}\:{evry}\:{books}\:{pdfs} \\ $$$${related}\:{to}\:{NEET},\:{JEE}\left({MAIN}\:{ADVANCED}\right) \\ $$$${and}\:{all}\:{engineering}\:{entrance}\:{exam}\:{books} \\ $$$${Also} \\ $$$${Books}\:{for}\:{class}\:{XII},{XI},{X},{IX} \\ $$ Commented…
Question Number 191220 by anr0h3 last updated on 21/Apr/23 $${x}^{\mathrm{6}} −{x}^{\mathrm{3}} =\mathrm{2}\:{solve}\:{for}\:{x} \\ $$$$ \\ $$$${m}={x}^{\mathrm{3}} \\ $$$${m}^{\mathrm{2}} =\left({x}^{\mathrm{3}} \right)^{\mathrm{2}} \\ $$$${m}^{\mathrm{2}} −{m}=\mathrm{2} \\ $$$${m}^{\mathrm{2}}…
Question Number 125685 by Hassen_Timol last updated on 12/Dec/20 $$ \\ $$$$\mathrm{Solve}\:\mathrm{this}\:\mathrm{differential}\:\mathrm{equation} \\ $$$$ \\ $$$$\:\:\:\:\:{q}_{\left({t}\right)} ''\:\:+\:\:\frac{\mathrm{1}}{\mathrm{LC}}\:{q}_{\left({t}\right)} \:\:=\:\:\frac{{V}}{{L}} \\ $$$$ \\ $$$$\mathrm{with}\:\left(\mathrm{L},\mathrm{C},\mathrm{V}\right)\:\in\:\mathbb{R}^{\mathrm{3}} \\ $$$$ \\…
Question Number 191210 by TUN last updated on 20/Apr/23 $$\mathrm{2}^{{x}} +\mathrm{2}^{{x}+\mathrm{1}} >\mathrm{3}^{{x}} +\mathrm{3}^{{x}+\mathrm{1}} \\ $$ Answered by ARUNG_Brandon_MBU last updated on 20/Apr/23 $$\mathrm{2}^{{x}} +\mathrm{2}^{{x}+\mathrm{1}} >\mathrm{3}^{{x}}…
Question Number 125673 by aurpeyz last updated on 12/Dec/20 Answered by bramlexs22 last updated on 13/Dec/20 $$\left(\mathrm{1}\right){a}+{ar}+{ar}^{\mathrm{2}} \:=\:{p}\:;{a}\left(\mathrm{1}+{r}+{r}^{\mathrm{2}} \right)={p} \\ $$$$\left(\mathrm{2}\right){a}^{\mathrm{2}} +{a}^{\mathrm{2}} {r}^{\mathrm{2}} +{a}^{\mathrm{2}} {r}^{\mathrm{4}}…
Question Number 60132 by Kunal12588 last updated on 18/May/19 Commented by Kunal12588 last updated on 18/May/19 $${is}\:{this}\:{question}\:{correct} \\ $$$${pls}\:{solve} \\ $$ Terms of Service Privacy…