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Question-126304

Question Number 126304 by mohammad17 last updated on 19/Dec/20 Answered by liberty last updated on 19/Dec/20 $$\left(\mathrm{1}\right)\mathrm{2}!×\mathrm{4}! \\ $$$$\left(\mathrm{3}\right)\mathrm{5}!−\mathrm{2}!×\mathrm{4}!=\mathrm{4}!×\mathrm{3} \\ $$ Answered by mr W…

3-2-5-3-7-5-3-9-8-2-83-5-

Question Number 126293 by talminator2856791 last updated on 19/Dec/20 $$\: \\ $$$$\: \\ $$$$\:\frac{\mathrm{3}}{\frac{\mathrm{2}_{} }{}\mathrm{5}} \\ $$$$\:\frac{\mathrm{3}}{\frac{\mathrm{7}}{\mathrm{5}}} \\ $$$$\:\frac{\mathrm{3}}{\frac{\mathrm{9}}{\mathrm{8}}} \\ $$$$\:\frac{\mathrm{2}}{\frac{\mathrm{83}}{\mathrm{5}}} \\ $$ Commented by…

z-0-and-z-is-complex-z-x-iy-with-x-y-R-Given-these-points-with-theirs-affix-0-0-0i-N-z-2-1-and-P-1-z-2-1-1-Show-that-1-z-2-1-z-2-1-z-2-1-2-1-2-2-What-is-the-nat

Question Number 126267 by mathocean1 last updated on 19/Dec/20 $${z}\neq\mathrm{0}\:{and}\:{z}\:{is}\:{complex}; \\ $$$${z}={x}+{iy}\:{with}\:{x};{y}\:\in\:\mathbb{R}^{\ast} . \\ $$$${Given}\:{these}\:{points}\:{with}\:{theirs} \\ $$$${affix}: \\ $$$$\mathrm{0}\left(\mathrm{0}+\mathrm{0}{i}\right);\:{N}\left({z}^{\mathrm{2}} −\mathrm{1}\right)\:{and}\:{P}\left(\frac{\mathrm{1}}{\mathrm{z}^{\mathrm{2}} }−\mathrm{1}\right) \\ $$$$\mathrm{1}.\:{Show}\:{that} \\ $$$$\left(\frac{\mathrm{1}}{{z}^{\mathrm{2}}…

x-0-i-j-2019-j-2019-i-j-

Question Number 60725 by naka3546 last updated on 25/May/19 $${x}\:\:=\:\:\underset{\mathrm{0}\leqslant{i}\leqslant{j}\leqslant\mathrm{2019}} {\sum}\:\left(\:_{\:\:\:\:{j}} ^{\mathrm{2019}} \:\right)\left(\:\:_{{i}} ^{{j}} \:\:\right)\: \\ $$ Commented by naka3546 last updated on 25/May/19 $${x}\:\:=\:\:?…

Question-126253

Question Number 126253 by mohammad17 last updated on 18/Dec/20 Answered by physicstutes last updated on 18/Dec/20 $$\mathrm{Exactly} \\ $$$$\:{a}\:+\:{ar}\:+\:{ar}^{\mathrm{2}} \:+…+{ar}^{{n}−\mathrm{1}} \:=\:\underset{{r}=\mathrm{1}} {\overset{{n}} {\sum}}{ar}^{{n}−\mathrm{1}} \:=\:\frac{{a}\left(\mathrm{1}−{r}^{{n}} \right)}{\mathrm{1}−{r}}…