Question Number 126304 by mohammad17 last updated on 19/Dec/20 Answered by liberty last updated on 19/Dec/20 $$\left(\mathrm{1}\right)\mathrm{2}!×\mathrm{4}! \\ $$$$\left(\mathrm{3}\right)\mathrm{5}!−\mathrm{2}!×\mathrm{4}!=\mathrm{4}!×\mathrm{3} \\ $$ Answered by mr W…
Question Number 126305 by mohammad17 last updated on 19/Dec/20 Answered by liberty last updated on 19/Dec/20 $$\mathrm{2}×\mathrm{5}!×\mathrm{5}!\: \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 126293 by talminator2856791 last updated on 19/Dec/20 $$\: \\ $$$$\: \\ $$$$\:\frac{\mathrm{3}}{\frac{\mathrm{2}_{} }{}\mathrm{5}} \\ $$$$\:\frac{\mathrm{3}}{\frac{\mathrm{7}}{\mathrm{5}}} \\ $$$$\:\frac{\mathrm{3}}{\frac{\mathrm{9}}{\mathrm{8}}} \\ $$$$\:\frac{\mathrm{2}}{\frac{\mathrm{83}}{\mathrm{5}}} \\ $$ Commented by…
Question Number 126289 by mr W last updated on 19/Dec/20 $${To}\:{Tinku}\:{Tara}\:{developers}: \\ $$$${the}\:{latest}\:{version}\:{seems}\:{to}\:{have}\:{a} \\ $$$${bug}:\:{i}\:{can}\:{not}\:{write}\:{the}\:{red}\:{part}\:{in} \\ $$$${following}\:{expression}: \\ $$ Commented by mr W last updated…
Question Number 126267 by mathocean1 last updated on 19/Dec/20 $${z}\neq\mathrm{0}\:{and}\:{z}\:{is}\:{complex}; \\ $$$${z}={x}+{iy}\:{with}\:{x};{y}\:\in\:\mathbb{R}^{\ast} . \\ $$$${Given}\:{these}\:{points}\:{with}\:{theirs} \\ $$$${affix}: \\ $$$$\mathrm{0}\left(\mathrm{0}+\mathrm{0}{i}\right);\:{N}\left({z}^{\mathrm{2}} −\mathrm{1}\right)\:{and}\:{P}\left(\frac{\mathrm{1}}{\mathrm{z}^{\mathrm{2}} }−\mathrm{1}\right) \\ $$$$\mathrm{1}.\:{Show}\:{that} \\ $$$$\left(\frac{\mathrm{1}}{{z}^{\mathrm{2}}…
Question Number 60725 by naka3546 last updated on 25/May/19 $${x}\:\:=\:\:\underset{\mathrm{0}\leqslant{i}\leqslant{j}\leqslant\mathrm{2019}} {\sum}\:\left(\:_{\:\:\:\:{j}} ^{\mathrm{2019}} \:\right)\left(\:\:_{{i}} ^{{j}} \:\:\right)\: \\ $$ Commented by naka3546 last updated on 25/May/19 $${x}\:\:=\:\:?…
Question Number 126252 by mohammad17 last updated on 18/Dec/20 Commented by mohammad17 last updated on 18/Dec/20 $${help}\:{me}\:{sir}\:{please}? \\ $$ Commented by mohammad17 last updated on…
Question Number 191795 by 073 last updated on 30/Apr/23 $$\mathrm{3}^{\mathrm{x}} −\mathrm{2}^{\mathrm{x}} =\mathrm{19} \\ $$$$\mathrm{x}=?? \\ $$ Commented by mr W last updated on 30/Apr/23 $${we}\:{know}\:\mathrm{27}−\mathrm{8}=\mathrm{19},…
Question Number 126253 by mohammad17 last updated on 18/Dec/20 Answered by physicstutes last updated on 18/Dec/20 $$\mathrm{Exactly} \\ $$$$\:{a}\:+\:{ar}\:+\:{ar}^{\mathrm{2}} \:+…+{ar}^{{n}−\mathrm{1}} \:=\:\underset{{r}=\mathrm{1}} {\overset{{n}} {\sum}}{ar}^{{n}−\mathrm{1}} \:=\:\frac{{a}\left(\mathrm{1}−{r}^{{n}} \right)}{\mathrm{1}−{r}}…
Question Number 126250 by mohammad17 last updated on 18/Dec/20 Terms of Service Privacy Policy Contact: info@tinkutara.com