Question Number 60045 by Kunal12588 last updated on 17/May/19 Commented by Kunal12588 last updated on 17/May/19 $${Ans}\::\:\mathrm{177}\frac{\mathrm{1}}{\mathrm{4}}\pi\:\:\left({given}\:{in}\:{book}\right) \\ $$ Commented by mr W last updated…
Question Number 60043 by Kunal12588 last updated on 17/May/19 $${Show}\:{that}\:{in}\:{a}\:\mathrm{30}°−\mathrm{60}°−\mathrm{90}°\:{triangle}\:{the}\: \\ $$$${altitude}\:{on}\:{the}\:{hypotaneuse}\:{divides}\:{the}\: \\ $$$${hypotaneuse}\:{into}\:{segments}\:{whose}\:{length} \\ $$$${has}\:{the}\:{ratio}\:\mathrm{1}/\mathrm{3}. \\ $$$${without}\:{using}\:{trigonometry}. \\ $$ Answered by tanmay last updated…
Question Number 125575 by ZiYangLee last updated on 12/Dec/20 $$\mathrm{If}\:\underset{{x}\rightarrow{a}} {\mathrm{lim}}\frac{{x}^{\mathrm{2}} −{bx}+\mathrm{4}{b}}{{x}−{a}}=−\mathrm{6},\:\mathrm{find}\:{a}\:\mathrm{and}\:{b}. \\ $$ Answered by ajfour last updated on 12/Dec/20 $${a}^{\mathrm{2}} −{ab}+\mathrm{4}{b}=\mathrm{0} \\ $$$$\mathrm{2}{a}−{b}=−\mathrm{6}…
Question Number 60016 by otchereabdullai@gmail.com last updated on 17/May/19 $$\mathrm{A}\:\mathrm{car}\:\mathrm{dealar}\:\mathrm{made}\:\mathrm{a}\:\mathrm{profit}\:\mathrm{of}\:\mathrm{22}.\mathrm{5\%} \\ $$$$\mathrm{by}\:\mathrm{selling}\:\mathrm{a}\:\mathrm{car}\:\mathrm{for}\:\mathrm{58000}\:\mathrm{cedis}.\:\mathrm{Find}\: \\ $$$$\mathrm{correct}\:\mathrm{to}\:\mathrm{two}\:\mathrm{decimal}\:\mathrm{places}\:\mathrm{the}\: \\ $$$$\mathrm{percentage}\:\mathrm{profit}\:\mathrm{if}\:\mathrm{the}\:\mathrm{car}\:\mathrm{had}\:\mathrm{been}\: \\ $$$$\mathrm{sold}\:\mathrm{for}\:\mathrm{61},\mathrm{200}\:\mathrm{cedis}.\: \\ $$ Answered by MJS last updated…
Question Number 191091 by otchereabdullai last updated on 18/Apr/23 $${The}\:{front}\:{of}\:{a}\:{train}\:\mathrm{80}{m}\:{long}\:{passes} \\ $$$${a}\:{signal}\:{at}\:{a}\:{speed}\:{of}\:\mathrm{72}{km}/{h}.\:{If}\:{the} \\ $$$${rear}\:{of}\:{the}\:{train}\:{passes}\:{the}\:{signal}\: \\ $$$$\mathrm{5}{seconds}\:{later},\:{find}\: \\ $$$$\left({a}\right)\:{the}\:{acceleration}\:{of}\:{the}\:{train} \\ $$$$\left({b}\right)\:{the}\:{speed}\:{at}\:{which}\:{the}\:{rear}\:{of}\:{the} \\ $$$${train}\:{passes}\:{the}\:{signal}. \\ $$ Answered…
Question Number 60010 by naka3546 last updated on 17/May/19 Commented by naka3546 last updated on 17/May/19 $${FOE}\:\:\:{collinear}\:\:? \\ $$ Answered by tanmay last updated on…
Question Number 191078 by sciencestudentW last updated on 17/Apr/23 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{{x}−{sinx}}{{x}^{\mathrm{3}} }=? \\ $$$${solve}\:{without}\:{hopital}\:{and}\:{any}\:{series}. \\ $$ Answered by mehdee42 last updated on 17/Apr/23 $${if}\:{x}\rightarrow\mathrm{0}\:\:\Rightarrow{x}−{sinx}\:\sim\:\frac{\mathrm{1}}{\mathrm{6}}{x}^{\mathrm{3}} \\…
Question Number 125538 by Mammadli last updated on 11/Dec/20 $$\sqrt{−\boldsymbol{{z}}}\:=\:\boldsymbol{{z}}\:+\:\mathrm{6}\:;\:\left(\boldsymbol{{z}}=?\right) \\ $$ Answered by mr W last updated on 12/Dec/20 $${let}\:{x}=\sqrt{−{z}}>\mathrm{0} \\ $$$$\Rightarrow{z}=−{x}^{\mathrm{2}} \\ $$$$\Rightarrow{x}=−{x}^{\mathrm{2}}…
Question Number 59997 by aliesam last updated on 16/May/19 $${find}\:\left({a},{b},{c}\right)\:{in}\:{R}\: \\ $$$${cos}\left({a}\right)+{cos}\left({b}\right)+{cos}\left({c}\right)=\mathrm{0} \\ $$$${sin}\left({a}\right)+{sin}\left({b}\right)+{sin}\left({c}\right)=\mathrm{0} \\ $$ Answered by MJS last updated on 17/May/19 $$\mathrm{we}\:\mathrm{have}\:\mathrm{only}\:\mathrm{2}\:\mathrm{equations}\:\mathrm{in}\:\mathrm{3}\:\mathrm{variables}\:\Rightarrow \\…
Question Number 125526 by ka7th last updated on 11/Dec/20 Answered by Dwaipayan Shikari last updated on 11/Dec/20 $$\underset{{n}=\mathrm{1}} {\overset{{n}} {\sum}}{n}^{{m}} =\frac{\mathrm{1}}{{m}+\mathrm{1}}\left({n}^{{m}+\mathrm{1}} \begin{pmatrix}{{m}+\mathrm{1}}\\{\mathrm{0}}\end{pmatrix}\beta_{\mathrm{0}} +{n}^{{m}} \begin{pmatrix}{{m}+\mathrm{1}}\\{\mathrm{1}}\end{pmatrix}\beta_{\mathrm{1}} +{n}^{{m}−\mathrm{1}}…