Question Number 190928 by TUN last updated on 14/Apr/23 $${Solve}\:{the}\:{equation}\:: \\ $$$$\mathrm{2}+{x}^{\mathrm{2}} \left({x}^{\mathrm{4}} +\mathrm{1}\right)=\frac{\sqrt{\mathrm{2}}{x}^{\mathrm{3}} \left({x}^{\mathrm{4}} −\mathrm{1}\right)}{\:\sqrt{{x}^{\mathrm{4}} +\mathrm{1}}} \\ $$$$ \\ $$ Commented by Frix last…
Question Number 190925 by sonukgindia last updated on 14/Apr/23 Commented by Frix last updated on 14/Apr/23 $${x}=\frac{\mathrm{1}+\sqrt{\mathrm{5}}}{\mathrm{2}} \\ $$ Answered by ibrahimabdullayev last updated on…
Question Number 59832 by aliesam last updated on 15/May/19 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 59829 by ANTARES VY last updated on 15/May/19 Commented by ANTARES VY last updated on 15/May/19 $$\boldsymbol{\mathrm{Find}}\:\:\boldsymbol{\mathrm{the}}\:\:\boldsymbol{\mathrm{painted}}\:\:\boldsymbol{\mathrm{area}} \\ $$ Commented by MJS last…
Question Number 125359 by weltr last updated on 10/Dec/20 $$\begin{cases}{{x}\:+\:{y}\:=\:\frac{\mathrm{5}\pi}{\mathrm{3}}}\\{{sin}\:{x}\:=\:\mathrm{2}{sin}\:{y}}\end{cases} \\ $$ Answered by Ar Brandon last updated on 10/Dec/20 $$\begin{cases}{\mathrm{x}+\mathrm{y}=\frac{\mathrm{5}\pi}{\mathrm{3}}}&{…\left(\mathrm{i}\right)}\\{\mathrm{sinx}=\mathrm{2siny}}&{…\left(\mathrm{ii}\right)}\end{cases} \\ $$$$\mathrm{From}\:\left(\mathrm{i}\right),\:\mathrm{x}+\mathrm{y}=\frac{\mathrm{5}\pi}{\mathrm{3}}\:\Rightarrow\:\mathrm{y}=\frac{\mathrm{5}\pi}{\mathrm{3}}−\mathrm{x} \\ $$$$\mathrm{substituting}\:\mathrm{the}\:\mathrm{above}\:\mathrm{result}\:\mathrm{in}\:\left(\mathrm{ii}\right)\:\mathrm{we}\:\mathrm{have}\:;…
Question Number 59814 by ANTARES VY last updated on 15/May/19 Commented by ANTARES VY last updated on 15/May/19 $$\boldsymbol{\mathrm{F}}\mathrm{ind}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{painted}}\:\:\boldsymbol{\mathrm{area}} \\ $$ Answered by mr W…
Question Number 59812 by ANTARES VY last updated on 15/May/19 $$\frac{\mathrm{6}}{\mathrm{3}+\sqrt[{\mathrm{3}}]{\mathrm{3}}+\sqrt[{\mathrm{3}}]{\mathrm{9}}}\:\:\:\boldsymbol{\mathrm{simplify}}. \\ $$ Commented by Kunal12588 last updated on 15/May/19 $${let}\:\sqrt[{\mathrm{3}}]{\mathrm{3}}={a} \\ $$$$\Rightarrow\sqrt[{\mathrm{3}}]{\mathrm{9}}={a}^{\mathrm{2}} \\ $$$$\Rightarrow\mathrm{3}={a}^{\mathrm{3}}…
Question Number 59811 by ANTARES VY last updated on 15/May/19 $$\left(\frac{\boldsymbol{\mathrm{tg}}^{\mathrm{2}} \left(\mathrm{590}°\right)}{\boldsymbol{\mathrm{cos}}^{\mathrm{2}} \left(\mathrm{320}°\right)}+\frac{\boldsymbol{\mathrm{sin}}\left(\mathrm{111}°\right)}{\boldsymbol{\mathrm{cos}}\left(\mathrm{159}°\right)}\right)\left(\frac{\boldsymbol{\mathrm{cos}}\left(\mathrm{279}°\right)}{\boldsymbol{\mathrm{sin}}\left(\mathrm{549}°\right)}+\frac{\boldsymbol{\mathrm{ctg}}\left(\mathrm{950}°\right)}{\boldsymbol{\mathrm{sin}}^{\mathrm{2}} \left(\mathrm{400}°\right)}\right) \\ $$$$\boldsymbol{\mathrm{simplify}}. \\ $$ Commented by Kunal12588 last updated on 15/May/19…
Question Number 190877 by 073 last updated on 13/Apr/23 Commented by 073 last updated on 13/Apr/23 $$\mathrm{solution}\:\mathrm{please}? \\ $$ Commented by Frix last updated on…
Question Number 190878 by 073 last updated on 13/Apr/23 Answered by HeferH last updated on 13/Apr/23 $$\frac{\mathrm{a}}{\mathrm{b}}\:=\:\frac{\mathrm{c}}{\mathrm{d}}\:=\:\frac{\mathrm{e}}{\mathrm{f}}=\mathrm{k} \\ $$$$\:\mathrm{a}\:=\:\mathrm{bk} \\ $$$$\:\mathrm{e}\:=\:\mathrm{fk} \\ $$$$\:\mathrm{c}\:=\:\mathrm{dk} \\ $$$$\:\frac{\mathrm{bfk}^{\mathrm{2}}…