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show-thatfor-z-C-z-1-2-2-z-2-z-1-2-2-This-formula-can-be-used-z-2-z-z-

Question Number 126553 by mathocean1 last updated on 21/Dec/20 $${show}\:{thatfor}\:{z}\in\mathbb{C}\: \\ $$$$\mid{z}+\mathrm{1}\mid^{\mathrm{2}} =\mathrm{2}\mid{z}\mid^{\mathrm{2}\:} \Leftrightarrow\mid{z}−\mathrm{1}\mid^{\mathrm{2}} =\mathrm{2}. \\ $$$${This}\:{formula}\:{can}\:{be}\:{used}: \\ $$$$\mid{z}\mid^{\mathrm{2}} ={z}×\overset{−} {{z}} \\ $$ Answered by…

f-x-x-f-x-x-2-1-f-2-

Question Number 192084 by sciencestudentW last updated on 07/May/23 $${f}\left({x}\right)+{x}\centerdot{f}\left(−{x}\right)={x}^{\mathrm{2}} +\mathrm{1} \\ $$$${f}\left(\sqrt{\mathrm{2}}\right)=? \\ $$ Answered by AST last updated on 07/May/23 $${x}^{\mathrm{2}} +\mathrm{1}=−\left(\mathrm{1}−{x}\right)\left(\mathrm{1}+{x}\right)+\mathrm{2}=−\left(\mathrm{1}+{x}−{x}\left(\mathrm{1}+{x}\right)\right)+\mathrm{2} \\…

f-x-x-2-6x-f-1-x-

Question Number 192076 by sciencestudentW last updated on 07/May/23 $${f}\left({x}\right)={x}^{\mathrm{2}} +\mathrm{6}{x}\:\:\:\:{f}^{−\mathrm{1}} \left({x}\right)=? \\ $$ Answered by AST last updated on 07/May/23 $${y}={f}\left({x}\right)={x}^{\mathrm{2}} +\mathrm{6}{x}=\left({x}+\mathrm{3}\right)^{\mathrm{2}} −\mathrm{9} \\…