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Question Number 59366 by tanmay last updated on 09/May/19 $${I}_{{n}} =\int_{\mathrm{0}} ^{\pi} {sin}^{{n}} \left({x}\right){dx} \\ $$$${find}\:\underset{{n}=\mathrm{2}} {\overset{\infty} {\sum}}\:\:\:\frac{{I}_{{n}} }{{n}−\mathrm{1}} \\ $$ Answered by tanmay last…
Question Number 124893 by Mammadli last updated on 06/Dec/20 $$\boldsymbol{{Solve}}\:\boldsymbol{{the}}\:\boldsymbol{{equation}}: \\ $$$$\mathrm{2}\sqrt[{\mathrm{3}}]{\mathrm{2}\boldsymbol{{x}}+\mathrm{1}}=\boldsymbol{{x}}^{\mathrm{3}} −\mathrm{1} \\ $$ Commented by Mammadli last updated on 06/Dec/20 Thank you very much dear ser Commented by…
Question Number 190425 by 073 last updated on 02/Apr/23 Answered by mahdipoor last updated on 02/Apr/23 $${F}\left({x}\right)={sin}^{−\mathrm{1}} \left({ln}\left({log}\left({x}\right)\right)\right)\Rightarrow−\mathrm{1}\leqslant{ln}\left({log}\left({x}\right)\right)\leqslant\mathrm{1} \\ $$$$\Rightarrow{e}^{−\mathrm{1}} \leqslant{log}\left({x}\right)\leqslant{e}^{\mathrm{1}} \Rightarrow\mathrm{10}^{{e}^{−\mathrm{1}} } \leqslant{x}\leqslant\mathrm{10}^{{e}^{\mathrm{1}} }…
Question Number 59342 by naka3546 last updated on 08/May/19 Answered by mr W last updated on 08/May/19 Commented by mr W last updated on 08/May/19…
Question Number 59338 by Hassen_Timol last updated on 08/May/19 Commented by Hassen_Timol last updated on 08/May/19 $$\mathrm{170cm}\:\:\:\:\:\:\mathrm{and}\:\:\:\:\:\:\:\:\:\mathrm{130cm} \\ $$ Answered by MJS last updated on…
Question Number 124870 by Algoritm last updated on 06/Dec/20 Answered by mindispower last updated on 06/Dec/20 $${ln}\left({x}_{{n}+\mathrm{1}} \right)=\frac{\mathrm{1}}{\mathrm{4}}{ln}\left(\mathrm{81}\right)−\frac{\mathrm{1}}{\mathrm{4}}{ln}\left({x}_{{n}} \right) \\ $$$${W}_{{n}} ={ln}\left({x}_{{n}} \right) \\ $$$${W}_{{n}+\mathrm{1}}…
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Question Number 190401 by pete last updated on 17/Apr/23 $$\mathrm{Determine}\:\mathrm{the}\:\mathrm{validity}\:\mathrm{of}\:\mathrm{the}\:\mathrm{following}\:\mathrm{argument}. \\ $$$$\mathrm{Having}\:\mathrm{nasal}\:\mathrm{congestion}\:\mathrm{is}\:\mathrm{not}\:\mathrm{sufficient}\:\mathrm{to}\:\mathrm{be} \\ $$$$\mathrm{diagnosed}\:\mathrm{of}\:\mathrm{Covid}−\mathrm{19}\:\mathrm{disease}. \\ $$$$\mathrm{Being}\:\mathrm{accinated}\:\mathrm{against}\:\mathrm{covid}−\mathrm{19}\:\mathrm{is}\: \\ $$$$\mathrm{necessary}\:\mathrm{for}\:\mathrm{not}\:\mathrm{being}\:\mathrm{diagnosed} \\ $$$$\mathrm{of}\:\mathrm{covid}−\mathrm{19}.\:\mathrm{Therefore},\mathrm{if}\:\mathrm{i}'\mathrm{m}\:\mathrm{diagnosed} \\ $$$$\mathrm{of}\:\mathrm{covid}−\mathrm{19}\:\mathrm{then}\:\:\mathrm{it}\:\mathrm{is}\:\mathrm{not}\:\mathrm{the}\:\mathrm{case}\:\mathrm{that} \\ $$$$\mathrm{either}\:\mathrm{I}\:\mathrm{have}\:\mathrm{not}\:\mathrm{vaccinated}\:\mathrm{against}\:\mathrm{covid}−\mathrm{19} \\…