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App-Updates-v2-232-adds-ability-to-export-to-latex-While-in-editor-select-Get-Latex-Provide-a-file-name-Generate-file-is-latex-and-can-be-opened-in-any-text-editor-You-can-pick-selected-lines-and

Question Number 125312 by Tinku Tara last updated on 10/Dec/20 $$\boldsymbol{\mathrm{App}}\:\boldsymbol{\mathrm{Updates}}: \\ $$$$\mathrm{v2}.\mathrm{232}\:\mathrm{adds}\:\mathrm{ability}\:\mathrm{to}\:\mathrm{export}\:\mathrm{to} \\ $$$$\mathrm{latex}.\:\mathrm{While}\:\mathrm{in}\:\mathrm{editor}\:\mathrm{select} \\ $$$$\mathrm{Get}\:\mathrm{Latex}.\:\mathrm{Provide}\:\mathrm{a}\:\mathrm{file}\:\mathrm{name}. \\ $$$$\mathrm{Generate}\:\mathrm{file}\:\mathrm{is}\:\mathrm{latex}\:\mathrm{and}\:\mathrm{can}\:\mathrm{be} \\ $$$$\mathrm{opened}\:\mathrm{in}\:\mathrm{any}\:\mathrm{text}\:\mathrm{editor}.\:\mathrm{You} \\ $$$$\mathrm{can}\:\mathrm{pick}\:\mathrm{selected}\:\mathrm{lines}\:\mathrm{and}\:\mathrm{copy} \\ $$$$\mathrm{to}\:\mathrm{another}\:\mathrm{latex}.…

Question-59777

Question Number 59777 by Kunal12588 last updated on 14/May/19 Commented by Kunal12588 last updated on 14/May/19 $${I}\:{made}\:{aformula}\:{you}\:{can}\:{use}\:{it}\:{like}\:{this} \\ $$$$\sqrt{\mathrm{2}+\sqrt{\mathrm{3}}} \\ $$$$\mathrm{1}.\:{find}\:{k} \\ $$$${k}={a}−\sqrt{{a}^{\mathrm{2}} −{b}}\:\:\:\:\left[\sqrt{\mathrm{2}+\sqrt{\mathrm{3}}}\right] \\…

2-3-2-2-3-2-3-2-2-3-simplify-

Question Number 59764 by ANTARES VY last updated on 14/May/19 $$\frac{\mathrm{2}+\sqrt{\mathrm{3}}}{\:\sqrt{\mathrm{2}}+\sqrt{\mathrm{2}+\sqrt{\mathrm{3}}}}+\frac{\mathrm{2}−\sqrt{\mathrm{3}}}{\:\sqrt{\mathrm{2}}−\sqrt{\mathrm{2}−\sqrt{\mathrm{3}}}}. \\ $$$$\boldsymbol{\mathrm{simplify}}. \\ $$ Answered by Kunal12588 last updated on 14/May/19 $$\frac{\mathrm{2}+\sqrt{\mathrm{3}}}{\:\sqrt{\mathrm{2}}+\sqrt{\mathrm{2}+\sqrt{\mathrm{3}}}}+\frac{\mathrm{2}−\sqrt{\mathrm{3}}}{\:\sqrt{\mathrm{2}}−\sqrt{\mathrm{2}−\sqrt{\mathrm{3}}}} \\ $$$$=\frac{\sqrt{\mathrm{2}}\left(\mathrm{2}+\sqrt{\mathrm{3}}\right)}{\mathrm{3}+\sqrt{\mathrm{3}}}+\frac{\sqrt{\mathrm{2}}\left(\mathrm{2}−\sqrt{\mathrm{3}}\right)}{\mathrm{3}−\sqrt{\mathrm{3}}}…

If-the-angle-between-the-vectors-c-ai-2j-and-d-3i-j-is-45-find-the-two-possible-values-of-a-

Question Number 190811 by otchereabdullai last updated on 12/Apr/23 $$\:{If}\:{the}\:{angle}\:{between}\:{the}\:{vectors} \\ $$$$\:{c}\:={ai}+\mathrm{2}{j}\:{and}\:\:{d}=\mathrm{3}{i}+{j}\:{is}\:\mathrm{45}°\:,\:{find} \\ $$$$\:{the}\:{two}\:{possible}\:{values}\:{of}\:{a} \\ $$ Answered by safojontoshtemirov last updated on 12/Apr/23 $${c}=\left({a};\mathrm{2}\right)\:{d}=\left(\mathrm{3};\mathrm{1}\right) \\…

If-y-x-find-approximate-value-of-101-

Question Number 59733 by otchereabdullai@gmail.com last updated on 14/May/19 $$\mathrm{If}\:\mathrm{y}=\sqrt{\mathrm{x}}\:\:,\mathrm{find}\:\mathrm{approximate}\:\mathrm{value}\:\mathrm{of}\: \\ $$$$\:\sqrt{\mathrm{101}} \\ $$ Commented by prakash jain last updated on 14/May/19 $$\left(\mathrm{101}\right)^{\mathrm{1}/\mathrm{2}} =\mathrm{100}^{\mathrm{1}/\mathrm{2}} \left(\mathrm{1}+\frac{\mathrm{1}}{\mathrm{100}}\right)^{\mathrm{1}/\mathrm{2}}…

Let-S-n-1-11-111-1111-11111-to-n-terms-Show-that-S-n-10-n-1-10-9n-81-

Question Number 125266 by ZiYangLee last updated on 09/Dec/20 $$\mathrm{Let}\:{S}_{{n}} =\mathrm{1}+\mathrm{11}+\mathrm{111}+\mathrm{1111}+\mathrm{11111}+\ldots\:\mathrm{to}\:{n}\:\mathrm{terms} \\ $$$$\mathrm{Show}\:\mathrm{that}\:{S}_{{n}} =\frac{\mathrm{10}^{{n}+\mathrm{1}} −\mathrm{10}−\mathrm{9}{n}}{\mathrm{81}} \\ $$ Answered by Dwaipayan Shikari last updated on 09/Dec/20…

5-2x-1-25-x-1-100-find-value-of-3-3-x-

Question Number 59730 by muneshkumar last updated on 14/May/19 $$\mathrm{5}^{\mathrm{2}{x}−\mathrm{1}\:} =\mathrm{25}^{{x}−\mathrm{1}} +\mathrm{100}\:{find}\:{value}\:{of}\:\mathrm{3}^{\mathrm{3}−{x}} \\ $$ Answered by tanmay last updated on 14/May/19 $$\frac{\mathrm{5}^{\mathrm{2}{x}} }{\mathrm{5}}=\left(\mathrm{5}^{\mathrm{2}} \right)^{{x}−\mathrm{1}} +\mathrm{100}…

d-n-da-n-a-1-

Question Number 190800 by 07049753053 last updated on 12/Apr/23 $$\frac{\boldsymbol{\mathrm{d}}^{\boldsymbol{\mathrm{n}}} }{\boldsymbol{\mathrm{da}}^{\boldsymbol{\mathrm{n}}} }\boldsymbol{\Gamma}\left(\boldsymbol{{a}}+\mathrm{1}\right)=? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com