Question Number 190563 by Best1 last updated on 06/Apr/23 Answered by a.lgnaoui last updated on 06/Apr/23 $$\left.\bullet\mathrm{1}{a}\right)\measuredangle{x}\:{et}\:\measuredangle\mathrm{72}\:\:{interceptent}\:{le} \\ $$$$\:\:\:\:{meme}\:{arc}\:\:;\:{alors} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\left[\boldsymbol{{x}}=\mathrm{72}\right] \\ $$$$\bullet\mathrm{1}{b}\:\:{x}=\mathrm{2}{y}=\mathrm{2}×\mathrm{33} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\left[\:\boldsymbol{{x}}=\mathrm{66}\right]…
Question Number 125006 by Mammadli last updated on 07/Dec/20 $$\boldsymbol{{prove}}\:\boldsymbol{{that}}: \\ $$$$\frac{\mathrm{1}}{\mathrm{3}}+\frac{\mathrm{1}}{\mathrm{4}}+…+\frac{\mathrm{1}}{\mathrm{127}}+\frac{\mathrm{1}}{\mathrm{128}}>\mathrm{1} \\ $$ Commented by mr W last updated on 07/Dec/20 $${that}'{s}\:{too}\:{easy}. \\ $$$${try}\:{to}\:{prove}…
Question Number 190537 by Skabetix last updated on 05/Apr/23 Answered by Peace last updated on 05/Apr/23 $${e}^{{u}} =\mathrm{1}+{u}+\frac{{u}^{\mathrm{2}} }{\mathrm{2}}+{o}\left({u}^{\mathrm{2}} \right) \\ $$$${a}\left({u}\right)=\mid\mathrm{1}+\frac{{u}}{\mathrm{2}}−\mathrm{1}+{o}\left({u}\right)\mid\Rightarrow\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}{u}\left({x}\right)=\mathrm{0} \\ $$$$\Rightarrow\forall\epsilon>\mathrm{0}\:\:\exists\eta\geqslant\mathrm{0},\forall\mid{u}\mid<\eta\:\:\:\Rightarrow\mid\alpha\left({u}\right)\mid<\epsilon\:…
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Question Number 190532 by MathsFan last updated on 05/Apr/23 $$\mathrm{10x}^{\mathrm{2}} −\mathrm{9xy}+\mathrm{2y}^{\mathrm{2}} =\mathrm{10} \\ $$$$\:\mathrm{please}\:\mathrm{how}\:\mathrm{do}\:\mathrm{I}\:\mathrm{find}\:\mathrm{the}\:\mathrm{ratio}\:\mathrm{of} \\ $$$$\:\mathrm{x}:\mathrm{y} \\ $$ Answered by Frix last updated on 05/Apr/23…
Question Number 124978 by rydasss last updated on 07/Dec/20 Answered by talminator2856791 last updated on 07/Dec/20 $$\:\:\mathrm{1000}{a}\:+\:\mathrm{100}{b}\:+\:\mathrm{10}{c}\:+\:{d}+\:{a}\:+\:{b}\:+\:{c}\:+\:{d}\:+\:{x}\:=\:\mathrm{2013},\:\: \\ $$$$\:{x}\:=\:{S}\left({S}\left(\mathrm{1000}{a}\:+\:\mathrm{100}{b}\:+\:\mathrm{10}{c}\:+\:{d}\right)\right) \\ $$$$\:\mathrm{1001}{a}\:+\:\mathrm{101}{b}\:+\:\mathrm{11}{c}\:+\:\mathrm{2}{d}\:+\:{x}\:=\:\mathrm{2013} \\ $$$$\:{a}\:=\:\mathrm{1} \\ $$$$\:\mathrm{101}{b}\:+\:\mathrm{11}{c}\:+\:\mathrm{2}{d}\:+\:{x}\:=\:\mathrm{1012}…
Question Number 190512 by 073 last updated on 04/Apr/23 Answered by som(math1967) last updated on 04/Apr/23 $$\:^{\mathrm{3}} \sqrt{\sqrt{\mathrm{15}}+\frac{\mathrm{196}}{\mathrm{54}}} \\ $$$$=\:^{\mathrm{3}} \sqrt{\sqrt{\mathrm{15}}+\frac{\mathrm{98}}{\mathrm{27}}} \\ $$$$=^{\mathrm{3}} \sqrt{\frac{\mathrm{27}\sqrt{\mathrm{15}}+\mathrm{98}}{\mathrm{27}}} \\…
Question Number 190508 by 073 last updated on 04/Apr/23 Answered by Frix last updated on 04/Apr/23 $${t}=\mathrm{tan}\:{x} \\ $$$$\frac{{t}+\mathrm{1}}{\:\sqrt{{t}^{\mathrm{2}} +\mathrm{1}}}=\frac{\mathrm{1}}{\mathrm{2}} \\ $$$$\mathrm{4}\left({t}+\mathrm{1}\right)^{\mathrm{2}} ={t}^{\mathrm{2}} +\mathrm{1} \\…
Question Number 124967 by mohammad17 last updated on 07/Dec/20 Commented by mohammad17 last updated on 07/Dec/20 $${please}\:{help}\:{me} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 190501 by 073 last updated on 04/Apr/23 $$\underset{{x}\rightarrow\infty} {\mathrm{lim}}\frac{\mathrm{3}^{\mathrm{x}} }{\mathrm{x}!}=? \\ $$$$\mathrm{solution}? \\ $$ Answered by Frix last updated on 04/Apr/23 $$\mathrm{0} \\…