Question Number 189873 by mathocean1 last updated on 23/Mar/23 $$\int_{\mathrm{0}} ^{\:\mathrm{2}} \frac{{x}−\mathrm{1}}{{x}^{\mathrm{2}} +{x}+\mathrm{1}}{dx}=\:? \\ $$ Answered by Ar Brandon last updated on 23/Mar/23 $${I}=\int_{\mathrm{0}} ^{\mathrm{2}}…
Question Number 189874 by mathocean1 last updated on 23/Mar/23 $$\int_{\mathrm{0}} ^{\:\mathrm{2}} \:\:\:\frac{{sin}\left({x}\right)}{{sin}\left({x}\right)+{cos}\left({x}\right)}{dx}=\:? \\ $$ Answered by ARUNG_Brandon_MBU last updated on 23/Mar/23 $${I}=\int_{\mathrm{0}} ^{\mathrm{2}} \frac{\mathrm{sin}{x}}{\mathrm{sin}{x}+\mathrm{cos}{x}}{dx}=\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}}\int_{\mathrm{0}} ^{\mathrm{2}}…
Question Number 58800 by naka3546 last updated on 30/Apr/19 Commented by MJS last updated on 30/Apr/19 $$\mathrm{it}\:\mathrm{seems}\:{x}=\frac{\mathrm{11}}{\mathrm{890}}\:\mathrm{but}\:\mathrm{I}\:\mathrm{can}'\mathrm{t}\:\mathrm{prove}\:\mathrm{it} \\ $$ Commented by tanmay last updated on…
Question Number 124332 by ZiYangLee last updated on 02/Dec/20 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{sum}\:\mathrm{of}\:\mathrm{the}\:\mathrm{all}\:\mathrm{positive}\:\mathrm{integers} \\ $$$$\mathrm{of}\:\mathrm{all}\:\mathrm{positive}\:\mathrm{factorsof}\:\mathrm{12} \\ $$ Answered by mr W last updated on 02/Dec/20 $$\mathrm{12}=\mathrm{2}^{\mathrm{2}} ×\mathrm{3} \\…
Question Number 58785 by naka3546 last updated on 30/Apr/19 $${Find}\:\:{the}\:\:{general}\:\:{solution}\:\:{of}\:\:\:{differential}\:\:{equation}\:\:{below}\:\:: \\ $$$$\left(\mathrm{cos}\:{x}\:\mathrm{cos}\:{y}\:+\:\mathrm{sin}^{\mathrm{2}} {x}\right)\:{dx}\:\:−\:\left(\mathrm{sin}\:{x}\:\mathrm{sin}\:{y}\:+\:\mathrm{cos}^{\mathrm{2}} {y}\right)\:{dy}\:\:=\:\:\mathrm{0} \\ $$ Answered by tanmay last updated on 30/Apr/19 $${cosxcosydx}−{sinxsinydy}+{sin}^{\mathrm{2}} {xdx}−{cos}^{\mathrm{2}}…
Question Number 189848 by sonukgindia last updated on 22/Mar/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 58754 by azizullah last updated on 29/Apr/19 Answered by Rasheed.Sindhi last updated on 29/Apr/19 $$−{x}^{\mathrm{3}} +{x}^{\mathrm{2}} −\mathrm{2}{x}^{\mathrm{2}} +\mathrm{2}=\mathrm{0} \\ $$$$−{x}^{\mathrm{2}} \left({x}−\mathrm{1}\right)−\mathrm{2}\left({x}^{\mathrm{2}} −\mathrm{1}\right)=\mathrm{0} \\…
Question Number 189815 by sonukgindia last updated on 22/Mar/23 Answered by Frix last updated on 22/Mar/23 $${z}=\mathrm{e}^{\mathrm{i}\theta} =\mathrm{cos}\:\theta\:+\mathrm{i}\:\mathrm{sin}\:\theta\:={c}+{s}\mathrm{i}\:\left[\mathrm{for}\:\mathrm{typing}\:\mathrm{less}\right] \\ $$$${z}^{{z}} =\left(\mathrm{e}^{\mathrm{i}\theta} \right)^{{c}+{s}\mathrm{i}} =\mathrm{e}^{−\theta{s}+\mathrm{i}\theta{c}} =\frac{\mathrm{1}}{\mathrm{e}^{\theta{s}} }\mathrm{e}^{\mathrm{i}\theta{c}}…
Question Number 124277 by SOMEDAVONG last updated on 02/Dec/20 $$\mathrm{I}.\int\frac{\mathrm{4x}^{\mathrm{2}} \mathrm{lnx}}{\mathrm{1}+\mathrm{x}^{\mathrm{4}} }\mathrm{dx}=?? \\ $$ Commented by MJS_new last updated on 02/Dec/20 $$\frac{\mathrm{4}{x}^{\mathrm{2}} }{{x}^{\mathrm{4}} +\mathrm{1}}=\frac{\frac{\sqrt{\mathrm{2}}}{\mathrm{2}}\left(\mathrm{1}−\mathrm{i}\right)}{{x}−\frac{\sqrt{\mathrm{2}}}{\mathrm{2}}\left(\mathrm{1}+\mathrm{i}\right)}+\frac{\frac{\sqrt{\mathrm{2}}}{\mathrm{2}}\left(\mathrm{1}+\mathrm{i}\right)}{{x}−\frac{\sqrt{\mathrm{2}}}{\mathrm{2}}\left(\mathrm{1}−\mathrm{i}\right)}−\frac{\frac{\sqrt{\mathrm{2}}}{\mathrm{2}}\left(\mathrm{1}+\mathrm{i}\right)}{{x}+\frac{\sqrt{\mathrm{2}}}{\mathrm{2}}\left(\mathrm{1}−\mathrm{i}\right)}−\frac{\frac{\sqrt{\mathrm{2}}}{\mathrm{2}}\left(\mathrm{1}−\mathrm{i}\right)}{{x}+\frac{\sqrt{\mathrm{2}}}{\mathrm{2}}\left(\mathrm{1}+\mathrm{i}\right)} \\…
Question Number 124264 by joki last updated on 02/Dec/20 Commented by bramlexs22 last updated on 02/Dec/20 $$=−\int\:\frac{{d}\left(\mathrm{cos}\:{x}\right)}{\mathrm{cos}\:{x}}\:=\:−\ell{n}\mid\mathrm{cos}\:{x}\:\mid\:+\:{c} \\ $$$$\:=\:\ell{n}\:\mid\:\mathrm{sec}\:{x}\:\mid\:+\:{c}\: \\ $$ Commented by joki last…