Question Number 189683 by yaslm last updated on 20/Mar/23 Answered by mr W last updated on 20/Mar/23 $${y}\geqslant\mathrm{0} \\ $$$${x}+\sqrt{{y}}\geqslant\mathrm{0} \\ $$ Commented by mr…
Question Number 58609 by azizullah last updated on 26/Apr/19 Answered by Prithwish sen last updated on 26/Apr/19 $$\frac{\mathrm{M}.\mathrm{P}}{\mathrm{S}.\mathrm{P}}=\frac{\mathrm{100}}{\mathrm{100}−\mathrm{20}}=\frac{\mathrm{100}}{\mathrm{80}} \\ $$$$\therefore\mathrm{S}.\mathrm{P}=\mathrm{Rs}.\mathrm{1600} \\ $$$$\mathrm{Again}, \\ $$$$\frac{\mathrm{C}.\mathrm{P}}{\mathrm{S}.\mathrm{P}}=\frac{\mathrm{100}}{\mathrm{100}+\mathrm{25}}=\frac{\mathrm{100}}{\mathrm{125}} \\…
Question Number 58600 by naka3546 last updated on 26/Apr/19 $${x}\:\:\in\:\:\mathbb{R}^{+} \:\left({positive}\:\:{real}\:\:{numbers}\right) \\ $$$${Prove}\:\:{that}\:\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:{x}^{\mathrm{2}} \:+\:\frac{\mathrm{2}}{{x}}\:\:\geqslant\:\:\mathrm{3} \\ $$ Answered by tanmay last updated on 26/Apr/19…
Question Number 58587 by naka3546 last updated on 25/Apr/19 $${For}\:\:\:{x}\:>\:\mathrm{0}\:\:,\:\:\:{y}\:\:<\:\:\mathrm{1}\:. \\ $$$${Prove}\:\:{that}\:\:\:\:{x}^{{y}} \:+\:{y}^{{x}} \:\:>\:\:\mathrm{1} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
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Question Number 189643 by 073 last updated on 19/Mar/23 $$\mathrm{f}\left(\mathrm{x}\right)=\frac{\mathrm{sinx}+\mathrm{cosx}}{\mathrm{3}} \\ $$$$\mathrm{R}_{\mathrm{f}\left(\mathrm{x}\right)} =? \\ $$ Answered by mehdee42 last updated on 19/Mar/23 $${f}\left({x}\right)=\frac{\sqrt{\mathrm{2}}}{\mathrm{3}}{Sin}\left({x}+\frac{\pi}{\mathrm{4}}\right)\Rightarrow{R}_{{f}} =\left[−\frac{\sqrt{\mathrm{2}}}{\mathrm{3}},\frac{\sqrt{\mathrm{2}}}{\mathrm{3}}\right] \\…
Question Number 124099 by aurpeyz last updated on 30/Nov/20 Answered by liberty last updated on 30/Nov/20 $$\Rightarrow\mathrm{5}\underset{\mathrm{0}} {\overset{{a}} {\int}}\:\left({x}^{\mathrm{4}} −{x}^{\mathrm{2}} \right){dx}\:=\:\mathrm{3}\underset{\mathrm{0}} {\overset{{a}} {\int}}\left({x}^{\mathrm{2}} −{x}^{\mathrm{3}} \right){dx}…
Question Number 58558 by naka3546 last updated on 25/Apr/19 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\:\:\frac{\sqrt{\mathrm{2}{x}^{\mathrm{2}} \:−\:\mathrm{2}{ax}\:+\:{b}\:−\:\mathrm{3}}}{{x}\:\:\sqrt[{\mathrm{3}}]{{x}^{\mathrm{5}} \:+\:\mathrm{8}}}\:\:=\:\:\frac{\mathrm{2}}{\mathrm{3}} \\ $$$${Value}\:\:{of}\:\:\:{ab}\:\:{is}\:\:… \\ $$ Answered by mr W last updated on 25/Apr/19…
Question Number 189630 by mathocean1 last updated on 19/Mar/23 $$\mathrm{16}^{{x}} +\mathrm{20}^{{x}} =\mathrm{25}^{{x}} \\ $$$${x}\:\left(\in\:\mathbb{R}\right)\:=? \\ $$ Answered by Rasheed.Sindhi last updated on 19/Mar/23 $$\mathrm{16}^{{x}} +\mathrm{20}^{{x}}…