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Question-189701

Question Number 189701 by DAVONG last updated on 20/Mar/23 Commented by Rasheed.Sindhi last updated on 23/Mar/23 $$\left.\mathrm{16}\right)\:\mathrm{59}\:{rectangles}\left({including}\:{squares}\right)\: \\ $$$$\:{having}\:{sum}\:{multiple}\:{of}\:\mathrm{5}. \\ $$$${I}\:{will}\:{write}\:{detailed}\:{solution}\:{if}\:{you} \\ $$$${give}\:{some}\:{response}. \\ $$…

Question-58618

Question Number 58618 by azizullah last updated on 26/Apr/19 Answered by mr W last updated on 26/Apr/19 $${roots}:\:\alpha,\beta \\ $$$$\alpha+\beta=\mathrm{7} \\ $$$$\alpha\beta=−\mathrm{9} \\ $$$$\left(\alpha−\beta\right)^{\mathrm{2}} =\left(\alpha+\beta\right)^{\mathrm{2}}…

Question-124151

Question Number 124151 by mohammad17 last updated on 01/Dec/20 Answered by MJS_new last updated on 01/Dec/20 $$\left[{ax}+{b}\right]=\left[{ax}\right]+{b} \\ $$$$\left(\mathrm{ii}\right)\:\left[{x}+\mathrm{3}+\left[\mathrm{1}+{x}+\left[{x}−\mathrm{2}\right]\right]\right]= \\ $$$$\:\:\:\:\:\:\:\:=\left[{x}+\mathrm{3}+\left[\mathrm{1}+{x}+\left[{x}\right]−\mathrm{2}\right]\right]= \\ $$$$\:\:\:\:\:\:\:\:=\left[{x}+\mathrm{3}+\left[{x}+\left[{x}\right]−\mathrm{1}\right]\right]= \\ $$$$\:\:\:\:\:\:\:\:=\left[{x}+\mathrm{3}+\left[{x}\right]+\left[{x}\right]−\mathrm{1}\right]=…

P-x-is-a-monic-fifth-degree-polynomial-that-satisfy-P-1-1-P-2-4-P-3-9-P-4-16-P-5-25-P-6-

Question Number 58612 by naka3546 last updated on 26/Apr/19 $${P}\left({x}\right)\:\:{is}\:\:{a}\:\:{monic}−{fifth}\:\:{degree}\:\:{polynomial}\:\:{that}\:{satisfy} \\ $$$$\:\:\:\:{P}\left(\mathrm{1}\right)\:\:=\:\:\mathrm{1} \\ $$$$\:\:\:\:{P}\left(\mathrm{2}\right)\:\:=\:\:\mathrm{4} \\ $$$$\:\:\:\:{P}\left(\mathrm{3}\right)\:\:=\:\:\mathrm{9} \\ $$$$\:\:\:\:{P}\left(\mathrm{4}\right)\:\:=\:\:\mathrm{16} \\ $$$$\:\:\:\:{P}\left(\mathrm{5}\right)\:\:=\:\:\mathrm{25} \\ $$$$\:\:\:\:{P}\left(\mathrm{6}\right)\:\:=\:\:? \\ $$$$ \\…

Question-58609

Question Number 58609 by azizullah last updated on 26/Apr/19 Answered by Prithwish sen last updated on 26/Apr/19 $$\frac{\mathrm{M}.\mathrm{P}}{\mathrm{S}.\mathrm{P}}=\frac{\mathrm{100}}{\mathrm{100}−\mathrm{20}}=\frac{\mathrm{100}}{\mathrm{80}} \\ $$$$\therefore\mathrm{S}.\mathrm{P}=\mathrm{Rs}.\mathrm{1600} \\ $$$$\mathrm{Again}, \\ $$$$\frac{\mathrm{C}.\mathrm{P}}{\mathrm{S}.\mathrm{P}}=\frac{\mathrm{100}}{\mathrm{100}+\mathrm{25}}=\frac{\mathrm{100}}{\mathrm{125}} \\…