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Question-123922

Question Number 123922 by help last updated on 29/Nov/20 Answered by liberty last updated on 29/Nov/20 $${y}={p}\left({x}−\mathrm{3}\right)^{\mathrm{2}} +\mathrm{1}\:=\:{px}^{\mathrm{2}} −\mathrm{6}{px}+\mathrm{9}{p}+\mathrm{1} \\ $$$$\begin{cases}{{p}=−{a}}\\{{b}=−\mathrm{6}{p}\:}\\{{c}=\mathrm{9}{p}+\mathrm{1}}\end{cases} \\ $$ Commented by…

Question-58387

Question Number 58387 by azizullah last updated on 22/Apr/19 Answered by mr W last updated on 22/Apr/19 $${x}=\mathrm{1}\:{is}\:{a}\:{solution}, \\ $$$$\Rightarrow{a}+\mathrm{5}=\mathrm{3} \\ $$$$\Rightarrow{a}=−\mathrm{2} \\ $$$$−\mathrm{2}{x}^{\mathrm{2}} +\mathrm{5}{x}−\mathrm{3}=\mathrm{0}…

Question-58377

Question Number 58377 by naka3546 last updated on 22/Apr/19 Answered by MJS last updated on 22/Apr/19 $$\mathrm{rectangular}\:\mathrm{triangle}\:\mathrm{with}\:\mathrm{diagonal}\:\mathrm{of}\:\mathrm{rectangle} \\ $$$$\left(\mathrm{6}−{h}\right)^{\mathrm{2}} +\mathrm{6}^{\mathrm{2}} =\left(\mathrm{2}{r}\right)^{\mathrm{2}} \\ $$$$\mathrm{short}\:\mathrm{side}\:\mathrm{of}\:\mathrm{rectangle}\:=\:\mathrm{2}{r}−\mathrm{2}{h}\:\Rightarrow \\ $$$$\mathrm{2}{r}=\mathrm{6}+{h}…

Question-58374

Question Number 58374 by azizullah last updated on 22/Apr/19 Answered by mr W last updated on 22/Apr/19 $$\left({y}+\mathrm{13}\right)\left({y}+{a}\right)={y}^{\mathrm{2}} +\left(\mathrm{13}+{a}\right){y}+\mathrm{13}{a} \\ $$$$\mathrm{13}+{a}=\mathrm{0} \\ $$$$\Rightarrow{a}=−\mathrm{13} \\ $$…