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x-3-3x-4-6-6-dx-

Question Number 123145 by aurpeyz last updated on 23/Nov/20 $$\int\frac{{x}^{\mathrm{3}} }{\left(\mathrm{3}{x}^{\mathrm{4}} −\mathrm{6}\right)^{\mathrm{6}} }{dx} \\ $$ Commented by benjo_mathlover last updated on 23/Nov/20 $$\delta\left({x}\right)=\frac{\mathrm{1}}{\mathrm{12}}\int\:\frac{{d}\left(\mathrm{3}{x}^{\mathrm{4}} −\mathrm{6}\right)}{\left(\mathrm{3}{x}^{\mathrm{4}} −\mathrm{6}\right)^{\mathrm{6}}…

write-ax-2-bx-c-as-a-sum-or-difference-of-two-squares-

Question Number 123143 by aurpeyz last updated on 23/Nov/20 $${write}\:{ax}^{\mathrm{2}} +{bx}+{c}\:{as}\:{a}\:{sum}\:{or}\:{difference}\: \\ $$$${of}\:{two}\:{squares} \\ $$ Commented by mr W last updated on 23/Nov/20 $$=\left(\sqrt{{a}}{x}\right)^{\mathrm{2}} +\mathrm{2}\left(\frac{{b}}{\:\mathrm{2}\sqrt{{a}}}×\sqrt{{a}}\right){x}+\left(\frac{{b}}{\mathrm{2}\sqrt{{a}}}\right)^{\mathrm{2}}…

ABCD-is-four-digits-integers-How-many-ABCD-that-suitable-with-A-B-C-D-25-

Question Number 57594 by naka3546 last updated on 08/Apr/19 $${ABCD}\:\:{is}\:\:{four}\:\:{digits}\:\:{integers}\:. \\ $$$${How}\:\:{many}\:\:{ABCD}\:\:{that}\:\:{suitable}\:\:{with}\:\:{A}+{B}+{C}+{D}\:\:=\:\:\mathrm{25}\:? \\ $$ Answered by mr W last updated on 08/Apr/19 $${A}:\:\mathrm{1},\mathrm{2},..,\mathrm{9} \\ $$$${B},{C},{D}:\:\mathrm{0},\mathrm{1},\mathrm{2},..,\mathrm{9}…

Question-188621

Question Number 188621 by 073 last updated on 03/Mar/23 Answered by HeferH last updated on 04/Mar/23 $$\frac{{a}}{{b}}\:=\:\frac{\mathrm{2}}{\mathrm{3}}\:=\:\frac{\mathrm{2}{k}}{\mathrm{3}{k}} \\ $$$$\:{a}^{{b}} \:=\:{b}^{{a}} \\ $$$$\:\left(\mathrm{2}{k}\right)^{\mathrm{3}{k}} \:=\:\left(\mathrm{3}{k}\right)^{\mathrm{2}{k}} \\ $$$$\:\mathrm{2}^{\mathrm{3}{k}}…

y-1-x-2-x-1-y-2-0-find-dy-dx-

Question Number 123086 by aurpeyz last updated on 22/Nov/20 $${y}\sqrt{\mathrm{1}−{x}^{\mathrm{2}} }+{x}\sqrt{\mathrm{1}−{y}^{\mathrm{2}} }=\mathrm{0}\:{find}\:{dy}/{dx} \\ $$ Commented by liberty last updated on 23/Nov/20 $$\:\:\:\:\:\:\:{y}\sqrt{\mathrm{1}−{x}^{\mathrm{2}} }\:=\:−{x}\sqrt{\mathrm{1}−{y}^{\mathrm{2}} }\: \\…