Question Number 189363 by 073 last updated on 15/Mar/23 Answered by Rasheed.Sindhi last updated on 15/Mar/23 $$\frac{{x}}{{y}}=\mathrm{0}.\mathrm{2}\overline {\mathrm{4}} \\ $$$$\mathrm{100}\left(\frac{{x}}{{y}}\right)=\mathrm{24}.\overline {\mathrm{4}} \\ $$$$\mathrm{10}\left(\frac{{x}}{{y}}\right)=\mathrm{2}.\overline {\mathrm{4}} \\…
Question Number 189350 by 073 last updated on 15/Mar/23 Answered by Rasheed.Sindhi last updated on 15/Mar/23 $$\mathrm{0}.\mathrm{7}\overline {\mathrm{9}}={y}\:\left({say}\right) \\ $$$$\mathrm{100}{y}=\mathrm{79}.\overline {\mathrm{9}} \\ $$$$\:\:\:\mathrm{10}{y}=\mathrm{7}.\overline {\mathrm{9}} \\…
Question Number 189335 by Gbenga last updated on 14/Mar/23 $$\boldsymbol{\mathrm{determine}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{volume}}\:\boldsymbol{\mathrm{of}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{region}}\: \\ $$$$\boldsymbol{\mathrm{that}}\:\boldsymbol{\mathrm{is}}\:\boldsymbol{\mathrm{between}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{xy}}\:\boldsymbol{\mathrm{plane}} \\ $$$$\:\boldsymbol{\mathrm{and}}\:\boldsymbol{\mathrm{f}}\left(\boldsymbol{\mathrm{x}},\boldsymbol{\mathrm{y}}\right)=\mathrm{2}+\boldsymbol{\mathrm{cos}}\left(\boldsymbol{\mathrm{x}}^{\mathrm{2}} \right)\:\boldsymbol{\mathrm{and}}\:\boldsymbol{\mathrm{is}}\:\boldsymbol{\mathrm{above}} \\ $$$$\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{triangle}}\:\boldsymbol{\mathrm{with}}\:\boldsymbol{\mathrm{vertices}}\:\left(\mathrm{0},\mathrm{0}\right),\left(\mathrm{6},\mathrm{0}\right)\: \\ $$$${a}\boldsymbol{{nd}}\:\left(\mathrm{6},\mathrm{2}\right)\:\boldsymbol{{using}}\:\boldsymbol{{double}}\:\boldsymbol{{integral}} \\ $$ Terms of Service Privacy…
Question Number 123784 by help last updated on 28/Nov/20 Answered by mr W last updated on 28/Nov/20 Commented by mr W last updated on 28/Nov/20…
Question Number 123780 by Ruhiyyeheyret last updated on 28/Nov/20 $$\sqrt{\mathrm{56}+\mathrm{67}−\mathrm{6}+\frac{\mathrm{6}}{\mathrm{99}}} \\ $$ Answered by MJS_new last updated on 28/Nov/20 $$\mathrm{1}.\:\mathrm{reduce}\:\mathrm{the}\:\mathrm{fraction}\:\frac{{a}×{c}}{{b}×{c}}=\frac{{a}}{{b}} \\ $$$$\mathrm{2}.\:\mathrm{add}/\mathrm{substract}\:\mathrm{the}\:\mathrm{integers} \\ $$$$\mathrm{3}.\:\mathrm{add}\:\mathrm{the}\:\mathrm{integer}\:\mathrm{and}\:\mathrm{the}\:\mathrm{fraction}\:{a}+\frac{{b}}{{c}}=\frac{{ac}+{b}}{{c}} \\…
Question Number 123777 by 676597498 last updated on 28/Nov/20 Commented by MJS_new last updated on 28/Nov/20 $$\mathrm{we}\:\mathrm{can}\:\mathrm{find}\:\mathrm{a}\:\mathrm{function}\:\mathrm{for}\:\mathrm{any}\:\mathrm{result} \\ $$ Answered by Olaf last updated on…
Question Number 189257 by Gbenga last updated on 14/Mar/23 $$\boldsymbol{\mathrm{determine}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{surface}}\:\boldsymbol{\mathrm{area}}\: \\ $$$$\boldsymbol{\mathrm{of}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{portion}}\:\boldsymbol{\mathrm{of}}\:\boldsymbol{\mathrm{z}}=\mathrm{13}−\mathrm{4}\boldsymbol{\mathrm{x}}^{\mathrm{2}} −\mathrm{4}\boldsymbol{\mathrm{y}}^{\mathrm{2}} \: \\ $$$$\boldsymbol{\mathrm{that}}\:\boldsymbol{\mathrm{is}}\:\boldsymbol{\mathrm{above}}\:\boldsymbol{\mathrm{z}}=\mathrm{1}\:\boldsymbol{\mathrm{with}}\:\boldsymbol{\mathrm{x}}\leq\mathrm{0}\:\boldsymbol{\mathrm{and}}\:\boldsymbol{\mathrm{y}}\geq\mathrm{0} \\ $$ Answered by Ar Brandon last updated on…
Question Number 189263 by Gbenga last updated on 14/Mar/23 $$\boldsymbol{{evaluate}}\:\int\int_{\boldsymbol{\mathrm{E}}} \int\mathrm{15}{Zdv},\:{where}\:{E} \\ $$$$\:{is}\:{the}\:{region}\:{between}\:\mathrm{2}{x}+{y}+{z}=\mathrm{4} \\ $$$$\:{and}\:\mathrm{4}{x}+\mathrm{4}{y}+\mathrm{2}{z}=\mathrm{20}\:{which}\:{is}\:{in}\: \\ $$$${front}\:{of}\:{the}\:{region}\:{in}\:{the}\:{yz}\:{plane}\: \\ $$$${bounded}\:{by}\:{z}=\mathrm{2}{y}^{\mathrm{2}} \:{and}\:{z}=\sqrt{\mathrm{4}{y}} \\ $$ Commented by Gbenga…
Question Number 189254 by yaslm last updated on 13/Mar/23 Answered by manxsol last updated on 14/Mar/23 $$\begin{vmatrix}{{a}}&{\mathrm{1}}&{\mathrm{1}}&{\mathrm{1}}&{\mathrm{1}}&{\mathrm{1}}&{\mathrm{1}}\\{\mathrm{1}}&{{a}}&{\mathrm{1}}&{\mathrm{1}}&{\mathrm{1}}&{\mathrm{1}}&{\mathrm{1}}\\{}&{}&{{a}}&{}&{}&{}&{\mathrm{1}}\\{}&{}&{}&{.}&{}&{}&{}\\{\mathrm{1}}&{\mathrm{1}}&{\mathrm{1}}&{\mathrm{1}}&{{a}}&{\mathrm{1}}&{\mathrm{1}}\\{\mathrm{1}}&{\mathrm{1}}&{\mathrm{1}}&{\mathrm{1}}&{\mathrm{1}}&{{a}}&{\mathrm{1}}\\{\mathrm{1}}&{\mathrm{1}}&{\mathrm{1}}&{\mathrm{1}}&{\mathrm{1}}&{\mathrm{1}}&{{a}}\end{vmatrix} \\ $$$$−{fn}+{f}_{{n}−\mathrm{1}} \\ $$$$−{fn}+{f}_{{n}−\mathrm{2}} \\ $$$$. \\ $$$$−{f}_{{n}}…
Question Number 189248 by 073 last updated on 13/Mar/23 Answered by mr W last updated on 13/Mar/23 $$\underset{{n}=\mathrm{1}} {\overset{\mathrm{1012}} {\sum}}\left[\left(\mathrm{2}{n}−\mathrm{1}\right)^{\mathrm{3}} −\left(\mathrm{2}{n}\right)^{\mathrm{3}} \right] \\ $$$$=\underset{{n}=\mathrm{1}} {\overset{\mathrm{1012}}…