Question Number 124591 by mohammad17 last updated on 04/Dec/20 Commented by mohammad17 last updated on 05/Dec/20 $${who}\:{is}\:{can}\:{solve}\:{this}\:? \\ $$ Answered by mindispower last updated on…
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Question Number 124534 by Novitasari last updated on 04/Dec/20 Commented by bemath last updated on 04/Dec/20 $$\mathrm{5}\sqrt{\mathrm{3}}+\mathrm{3}\sqrt{\mathrm{3}}−\mathrm{3}\sqrt{\mathrm{3}}\:=\:\mathrm{5}\sqrt{\mathrm{3}} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 190067 by DAVONG last updated on 26/Mar/23 Answered by mehdee42 last updated on 26/Mar/23 $${S}=\left[\sqrt{\mathrm{1}}\right]+\left[\sqrt{\mathrm{2}}\right]+…+\left[\sqrt{\mathrm{500}}\right] \\ $$$$\left[\sqrt{\mathrm{1}}\right]+\left[\sqrt{\mathrm{2}}\right]+\left[\sqrt{\mathrm{3}}\right]=\mathrm{3}×\mathrm{1} \\ $$$$\left[\sqrt{\mathrm{4}}\right]+\left[\sqrt{\mathrm{5}}\right]+\left[\mathrm{6}\right]+\left[\sqrt{\mathrm{7}}\right]+\left[\sqrt{\mathrm{8}}\right]=\mathrm{5}×\mathrm{2} \\ $$$$\vdots \\ $$$$\left[\sqrt{\mathrm{441}}\right]+\left[\sqrt{\mathrm{442}}\right]+…+\left[\sqrt{\mathrm{483}}\right]=\mathrm{43}×\mathrm{21}…
Question Number 190061 by sonukgindia last updated on 26/Mar/23 Answered by a.lgnaoui last updated on 29/Mar/23 $$\mathrm{2}\left({n}^{{n}+\mathrm{1}} −{n}!\right)=\mathrm{5}{n}^{\mathrm{2}} −\mathrm{3}{n}−\mathrm{2} \\ $$$$\frac{\mathrm{2}\left({n}^{{n}+\mathrm{1}} \right)}{{n}!}−\mathrm{1}=\frac{{a}}{{n}!}\left({a}=\right) \\ $$$$\frac{\mathrm{2}{n}×{n}^{{n}} }{{n}!}=\frac{\mathrm{5}\left({n}−\frac{\mathrm{3}}{\mathrm{2}}\right)^{\mathrm{2}}…
Question Number 190056 by mathocean1 last updated on 26/Mar/23 $${Solve}\:: \\ $$$$\begin{cases}{{y}'\left({t}\right)=\left[{tanh}\left({y}\left({t}\right)\right)\right]^{−\mathrm{1}} }\\{{y}\left(\mathrm{0}\right)=\mathrm{2}}\end{cases} \\ $$$$ \\ $$$${tanh}\:{is}\:{hyperbolic}\:{tangent}\:{function}. \\ $$ Answered by mehdee42 last updated on…
Question Number 124517 by help last updated on 03/Dec/20 Commented by help last updated on 03/Dec/20 $${find}\:{the}\:{value}\:{of}\:{r}\:{that}\:{satisfy}\:{the} \\ $$$${equation} \\ $$ Commented by help last…
Question Number 124513 by mathocean1 last updated on 03/Dec/20 $${an}\:{integer}\:{n}\:{has}\:\mathrm{15}\:{divisors}.\:{n}\:{is} \\ $$$${divisible}\:{by}\:\mathrm{6}\:{but}\:{not}\:{divisible}\:\:{by}\:\mathrm{8}. \\ $$$${determinate}\:{n}. \\ $$ Commented by mr W last updated on 03/Dec/20 $$\mathrm{324}?…