Question Number 189140 by 073 last updated on 12/Mar/23 Answered by Ar Brandon last updated on 12/Mar/23 $${x}>\mathrm{0}\:\wedge\:{x}\geqslant\mathrm{1}\:\Rightarrow{x}\geqslant\mathrm{1} \\ $$$$\mathrm{4}−\mathrm{ln}{x}\geqslant\mathrm{3}\sqrt{\mathrm{ln}{x}}\:,\:{t}^{\mathrm{2}} =\mathrm{ln}{x} \\ $$$$\mathrm{4}−{t}^{\mathrm{2}} \geqslant\mathrm{3}{t}\:\Rightarrow\:{t}^{\mathrm{2}} +\mathrm{3}{t}−\mathrm{4}\:\leqslant\:\mathrm{0}…
Question Number 123608 by malwan last updated on 26/Nov/20 $${sir}\:{TINKUTARA} \\ $$$${what}\:{is}\:{the}\:{problem}\:{with}\:{brackets} \\ $$$${in}\:{red}\:{color}\:? \\ $$$$\left.\mathrm{1}\right)\:\:\left(\frac{\mathrm{1}}{\mathrm{2}}\right)^{\mathrm{5}{x}} \:\: \\ $$$$\left(\frac{\mathrm{1}}{\mathrm{2}}\right)^{\mathrm{5}{x}} \\ $$ Commented by JDamian last…
Question Number 123607 by mohammad17 last updated on 26/Nov/20 $${if}\:{a}=\frac{\mathrm{1}+{i}}{\:\sqrt{\mathrm{2}}}\:\:{find}\:{a}^{\mathrm{1943}} \:\:\:\:? \\ $$ Answered by Dwaipayan Shikari last updated on 26/Nov/20 $${a}\:=\frac{\mathrm{1}+{i}}{\:\sqrt{\mathrm{2}}}\:=\sqrt{{i}} \\ $$$${a}^{\mathrm{1943}} =\left({i}\right)^{\frac{\mathrm{1943}}{\mathrm{2}}}…
Question Number 58069 by Kunal12588 last updated on 17/Apr/19 $${Between}\:\mathrm{100}\:{and}\:\mathrm{600},\:{how}\:{many}\:{number} \\ $$$${are}\:{such}\:{which}\:{are}\:{totally}\:{divisible}\:{by}\:\mathrm{11}\:{or}\:\mathrm{17}. \\ $$ Commented by Kunal12588 last updated on 17/Apr/19 Commented by Kunal12588 last…
Question Number 123600 by aurpeyz last updated on 26/Nov/20 $$\underset{\mathrm{0}} {\overset{\mathrm{2}} {\int}}\sqrt{\frac{{x}}{\mathrm{4}−{x}}}{dx} \\ $$ Answered by Dwaipayan Shikari last updated on 26/Nov/20 $$\int_{\mathrm{0}} ^{\mathrm{2}} \sqrt{\frac{{x}}{\mathrm{4}−{x}}}\:{dx}…
Question Number 123601 by aurpeyz last updated on 26/Nov/20 Commented by aurpeyz last updated on 26/Nov/20 $${pls}\:{explain}\:{to}\:{me}\:{if}\:{i}\:{still}\:{need}\:{to} \\ $$$${find}\:{the}\:{class}\:{boundary}\:{since}\:{the}\: \\ $$$${class}\:{interval}\:{is}\:{already}\:{continous}. \\ $$$${thank}\:{you} \\ $$…
Question Number 123598 by aurpeyz last updated on 26/Nov/20 $${prove}\:{that}\:\underset{\mathrm{0}} {\overset{{a}} {\int}}\sqrt{{a}^{\mathrm{2}} −{x}^{\mathrm{2}} }{dx}=\frac{\pi{a}^{\mathrm{2}} }{\mathrm{4}} \\ $$ Answered by Dwaipayan Shikari last updated on 26/Nov/20…
Question Number 123599 by aurpeyz last updated on 26/Nov/20 $$\int{tan}^{\mathrm{5}} {xdx} \\ $$ Answered by Dwaipayan Shikari last updated on 26/Nov/20 $$\int{tan}^{\mathrm{2}} {x}\:{tan}^{\mathrm{3}} {x}\:{dx} \\…
Question Number 123597 by aurpeyz last updated on 26/Nov/20 $${pls}\:{what}\:{is}\:{the}\:{formula}\:{for}\:{skewness} \\ $$$${and}\:{kurtosis}? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 58060 by Kunal12588 last updated on 17/Apr/19 $${Having}\:{given}\:\mathrm{log}\:\mathrm{2}\:=\:\mathrm{0}.\mathrm{30103},\:{find}\:{the}\:{position} \\ $$$${of}\:{the}\:{first}\:{significant}\:{figure}\:{in}\:\mathrm{2}^{−\mathrm{37}} . \\ $$ Commented by Rasheed.Sindhi last updated on 17/Apr/19 $$−\mathrm{11}.\mathrm{13811}\neq\overline {\mathrm{11}}.\mathrm{13811} \\…