Question Number 57390 by naka3546 last updated on 03/Apr/19 $${a}^{\mathrm{2}} \:+\:{d}^{\mathrm{2}} \:−\:{ad}\:\:=\:\:{b}^{\mathrm{2}} \:+\:{c}^{\mathrm{2}} \:+\:{bc} \\ $$$${a}^{\mathrm{2}} \:+\:{b}^{\mathrm{2}} \:\:=\:\:{c}^{\mathrm{2}} \:+\:{d}^{\mathrm{2}} \\ $$$$\frac{{ab}\:+\:{cd}}{{ad}\:+\:{bc}}\:\:=\:\:? \\ $$ Terms of…
Question Number 188441 by 073 last updated on 01/Mar/23 Answered by cortano12 last updated on 01/Mar/23 $$\mathrm{P}\left(\mathrm{x}−\mathrm{2}\right)=\left(\mathrm{x}−\mathrm{2}\right)^{\mathrm{2}} +\mathrm{4}\left(\mathrm{x}−\mathrm{2}\right)+\mathrm{1} \\ $$$$\mathrm{P}\left(\mathrm{x}−\mathrm{2}\right)=\mathrm{x}^{\mathrm{2}} −\mathrm{4x}+\mathrm{4}+\mathrm{4x}−\mathrm{8}+\mathrm{1} \\ $$$$\mathrm{P}\left(\mathrm{x}−\mathrm{2}\right)=\mathrm{x}^{\mathrm{2}} −\mathrm{3}\: \\…
Question Number 122904 by Khalmohmmad last updated on 20/Nov/20 $$\left(\mathrm{1}+{i}\right)^{\mathrm{9}} =? \\ $$ Answered by Bird last updated on 20/Nov/20 $$\mathrm{1}+{i}=\sqrt{\mathrm{2}}{e}^{\frac{{i}\pi}{\mathrm{4}}} \:\Rightarrow\left(\mathrm{1}+{i}\right)^{\mathrm{9}} \:=\left(\sqrt{\mathrm{2}}\right)^{\mathrm{9}} \:{e}^{\frac{{k}\mathrm{9}\pi}{\mathrm{4}}{i}} \\…
Question Number 57368 by problem solverd last updated on 03/Apr/19 $$\mathrm{5}^{\mathrm{3}{x}−\mathrm{3}} −\mathrm{5}^{\mathrm{3}{x}} −\mathrm{5}=\mathrm{615} \\ $$$$\mathrm{solve}\:\mathrm{for}\:{x} \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on 03/Apr/19 $$\mathrm{5}^{\mathrm{3}{x}}…
Question Number 122903 by Khalmohmmad last updated on 20/Nov/20 $$\left(\frac{\mathrm{1}+{i}}{\mathrm{1}−{i}}\right)^{\mathrm{50}} =? \\ $$ Answered by Dwaipayan Shikari last updated on 20/Nov/20 $$\left(\frac{\mathrm{1}+{i}}{\mathrm{1}−{i}}\right)^{\mathrm{50}} =\left(\frac{\left(\mathrm{1}+{i}\right)^{\mathrm{2}} }{\left(\mathrm{1}−{i}\right)^{\mathrm{2}} }\right)^{\mathrm{25}}…
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Question Number 57357 by ANTARES VY last updated on 03/Apr/19 $$\mathrm{1}−\mathrm{2}\boldsymbol{\mathrm{sin}}\left(\mathrm{4}\boldsymbol{\mathrm{x}}\right)<\boldsymbol{\mathrm{cos}}^{\mathrm{2}} \left(\mathrm{4}\boldsymbol{\mathrm{x}}\right) \\ $$$$\boldsymbol{\mathrm{solve}}. \\ $$ Commented by bshahid010@gmail.com last updated on 03/Apr/19 $$\mathrm{1}−\mathrm{2sin}\left(\mathrm{4x}\right)<\mathrm{cos}^{\mathrm{2}} \left(\mathrm{4x}\right)…
Question Number 57356 by ANTARES VY last updated on 03/Apr/19 $$\boldsymbol{\mathrm{S}}=\frac{\boldsymbol{\pi\mathrm{R}}^{\mathrm{2}} }{\mathrm{360}°}×\boldsymbol{\alpha}° \\ $$$$\boldsymbol{\mathrm{prove}}. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 188417 by 073 last updated on 01/Mar/23 Commented by SEKRET last updated on 01/Mar/23 $$\:\boldsymbol{\mathrm{D}} \\ $$ Answered by SEKRET last updated on…
Question Number 188416 by 073 last updated on 01/Mar/23 Answered by manxsol last updated on 01/Mar/23 $$\Sigma=\frac{\mathrm{1}}{\mathrm{3}^{\mathrm{2}} }+\frac{\mathrm{1}}{\mathrm{3}^{\mathrm{3}} }+……. \\ $$$$\Sigma=\frac{\mathrm{1}}{\mathrm{3}}\left[\frac{\mathrm{1}}{\mathrm{3}}+\frac{\mathrm{1}}{\mathrm{3}^{\mathrm{2}} }…….\right] \\ $$$$\mathrm{3}\Sigma=\frac{\mathrm{1}}{\mathrm{3}}+\Sigma \\…