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if-f-x-3-x-find-f-2-1-

Question Number 123267 by mohammad17 last updated on 24/Nov/20 $${if}\:{f}\left({x}\right)=\mid\mathrm{3}−{x}\mid\:{find}\:\left({f}^{\:\mathrm{2}} \right)^{'} \left(\mathrm{1}\right)\:\:? \\ $$ Commented by MJS_new last updated on 24/Nov/20 $$\mathrm{if}\:\mathrm{you}\:\mathrm{mean}\:\left(\left({f}\left({x}\right)\right)^{\mathrm{2}} \right)' \\ $$$$\left({f}\left({x}\right)\right)^{\mathrm{2}}…

A-patient-get-a-test-for-a-disease-that-indicates-positive-in-95-of-cases-when-the-patient-has-the-disease-and-10-when-the-patient-isn-t-sick-What-is-the-probability-he-s-not-sick-knowing-that-th

Question Number 123254 by Maclaurin Stickker last updated on 24/Nov/20 $${A}\:{patient}\:{get}\:{a}\:{test}\:{for}\:{a}\:{disease}\:{that}\: \\ $$$${indicates}\:{positive}\:{in}\:\mathrm{95\%}\:{of}\:{cases}\:{when} \\ $$$${the}\:{patient}\:{has}\:{the}\:{disease}\:{and}\:\mathrm{10\%} \\ $$$${when}\:{the}\:{patient}\:{isn}'{t}\:{sick}.\:{What}\:{is} \\ $$$${the}\:{probability}\:{he}'{s}\:{not}\:{sick},\:{knowing} \\ $$$${that}\:{the}\:{test}\:{is}\:{positive}? \\ $$ Terms of…

3-1-2-3-4-2-3-4-5-3-4-5-100-98-99-100-

Question Number 123256 by ZiYangLee last updated on 24/Nov/20 $$\frac{\mathrm{3}}{\mathrm{1}!+\mathrm{2}!+\mathrm{3}!}+\frac{\mathrm{4}}{\mathrm{2}!+\mathrm{3}!+\mathrm{4}!}+\frac{\mathrm{5}}{\mathrm{3}!+\mathrm{4}!+\mathrm{5}!}+\ldots+\frac{\mathrm{100}}{\mathrm{98}!+\mathrm{99}!+\mathrm{100}!}=? \\ $$ Commented by ZiYangLee last updated on 24/Nov/20 $${answer}\:{given}:\:\frac{\mathrm{1}}{\mathrm{2}!}−\frac{\mathrm{1}}{\mathrm{100}!} \\ $$ Commented by zarminaawan…

R-1-cos-0-5-Rsin-4-R-

Question Number 57700 by Nameed last updated on 10/Apr/19 $$\mathrm{R}\left(\mathrm{1}\:−\:\mathrm{cos}\theta\right)\:=\:\mathrm{0}.\mathrm{5} \\ $$$$\mathrm{Rsin}\theta\:=\:\mathrm{4} \\ $$$$\mathrm{R}\:=\:? \\ $$$$\theta\:=\:? \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on 10/Apr/19…

prove-that-cot5x-1-10tan-2-x-5tan-4-x-tan-5-x-10tan-3-x-5tanx-

Question Number 123232 by mohammad17 last updated on 24/Nov/20 $${prove}\:{that}\:{cot}\mathrm{5}{x}=\frac{\mathrm{1}−\mathrm{10}{tan}^{\mathrm{2}} {x}+\mathrm{5}{tan}^{\mathrm{4}} {x}}{{tan}^{\mathrm{5}} {x}−\mathrm{10}{tan}^{\mathrm{3}} {x}+\mathrm{5}{tanx}}\:? \\ $$ Answered by $@y@m last updated on 24/Nov/20 $$\mathrm{tan}\:\left(\mathrm{2}{x}+\mathrm{3}{x}\right)=\frac{\mathrm{tan}\:\mathrm{2}{x}+\mathrm{tan}\:\mathrm{3}{x}}{\mathrm{1}−\mathrm{tan}\:\mathrm{2}{x}.\mathrm{tan}\:\mathrm{3}{x}} \\…