Question Number 123067 by Khalmohmmad last updated on 22/Nov/20 $$\underset{{n}=\mathrm{2}} {\overset{\infty} {\sum}}\:\frac{\mathrm{2}}{{n}^{\mathrm{2}} −\mathrm{1}}=? \\ $$ Answered by Dwaipayan Shikari last updated on 22/Nov/20 $$\mathrm{2}\underset{{n}=\mathrm{2}} {\overset{\infty}…
Question Number 123075 by nico last updated on 22/Nov/20 Answered by Olaf last updated on 23/Nov/20 $$\frac{\mathrm{2}{n}+\mathrm{2}{i}+\mathrm{1}}{\mathrm{2}\left({n}+{i}\right)^{\mathrm{2}} }\:=\:\frac{\mathrm{1}}{{n}+{i}}+\frac{\mathrm{1}}{\mathrm{2}\left({n}+{i}\right)^{\mathrm{2}} } \\ $$$$\underset{{i}=\mathrm{1}} {\overset{{n}} {\sum}}\frac{\mathrm{1}}{{n}+{i}}\:=\:\psi\left(\mathrm{2}{n}+\mathrm{1}\right)−\psi\left({n}+\mathrm{1}\right) \\ $$$$\underset{{i}=\mathrm{1}}…
Question Number 188591 by 073 last updated on 03/Mar/23 Commented by manxsol last updated on 03/Mar/23 $${x}=−\mathrm{2} \\ $$$${f}\left(−\mathrm{2}\right)={f}\left(−\mathrm{2}\right)−\mathrm{5}\left(−\mathrm{2}\right)+\mathrm{3}{m} \\ $$$$\frac{−\mathrm{10}}{\mathrm{3}}={m}\:\:\:\:??? \\ $$ Commented by…
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Question Number 188590 by 073 last updated on 03/Mar/23 Answered by CElcedricjunior last updated on 03/Mar/23 $$\frac{\boldsymbol{{f}}\left(\mathrm{3}\boldsymbol{{x}}\right)}{\boldsymbol{{g}}\left(\boldsymbol{{x}}−\mathrm{2}\right)}=\boldsymbol{{x}}^{\mathrm{3}} \:;\boldsymbol{{f}}'\left(\mathrm{3}\right)=\mathrm{5};\boldsymbol{{g}}\left(−\mathrm{1}\right)=\mathrm{2} \\ $$$$=>\boldsymbol{{g}}'\left(−\mathrm{1}\right)+\boldsymbol{{f}}\left(\mathrm{3}\right)=\boldsymbol{{k}}\:\boldsymbol{{trouvons}}\:\boldsymbol{{k}} \\ $$$$\left(\frac{\boldsymbol{{f}}\left(\mathrm{3}\boldsymbol{{x}}\right)}{\boldsymbol{{g}}\left(\boldsymbol{{x}}−\mathrm{2}\right)}\right)'=\frac{\mathrm{3}\boldsymbol{{f}}'\left(\mathrm{3}\boldsymbol{{x}}\right)\boldsymbol{{g}}\left(\boldsymbol{{x}}−\mathrm{2}\right)−\boldsymbol{{g}}'\left(\boldsymbol{{x}}−\mathrm{2}\right)\boldsymbol{{f}}\left(\mathrm{3}\boldsymbol{{x}}\right)}{\left[\boldsymbol{{g}}\left(\boldsymbol{{x}}−\mathrm{2}\right)\right]^{\mathrm{2}} }=\mathrm{3}\boldsymbol{{x}}^{\mathrm{2}} \\ $$$$=>\frac{\mathrm{3}\boldsymbol{{f}}'\left(\mathrm{3}\right)\boldsymbol{{g}}\left(−\mathrm{1}\right)−\boldsymbol{{g}}'\left(−\mathrm{1}\right)\boldsymbol{{f}}\left(\mathrm{3}\right)}{\left(\boldsymbol{{g}}\left(−\mathrm{1}\right)\right)^{\mathrm{2}}…
Question Number 57515 by Hassen_Timol last updated on 06/Apr/19 Commented by Hassen_Timol last updated on 06/Apr/19 $${Excuse}\:{me},\:{what}\:{does}\:{it}\:{mean}? \\ $$$${Can}\:{you}\:{give}\:{some}\:{examples}\:{for}\:\mathrm{n}? \\ $$ Commented by maxmathsup by…
Question Number 123048 by mohammad17 last updated on 22/Nov/20 Commented by mohammad17 last updated on 22/Nov/20 $${how}\:{can}\:{Solve}\:{it}\:? \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 123047 by mohammad17 last updated on 22/Nov/20 Commented by mohammad17 last updated on 22/Nov/20 $${how}\:{can}\:{Solve}\:{it}\:{please}\:? \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 188569 by 073 last updated on 03/Mar/23 Answered by JDamian last updated on 03/Mar/23 $$\mathrm{16}? \\ $$ Commented by 073 last updated on…
Question Number 188568 by 073 last updated on 03/Mar/23 Answered by floor(10²Eta[1]) last updated on 03/Mar/23 $$\mathrm{f}\left(\mathrm{h}\left(−\mathrm{4}\right)\right) \\ $$$$\mathrm{3}^{−\mathrm{x}} +\mathrm{3}^{\mathrm{x}} =−\mathrm{4}\Rightarrow\mathrm{1}+\mathrm{3}^{\mathrm{2x}} =−\mathrm{4}.\mathrm{3}^{\mathrm{x}} \\ $$$$\Rightarrow\mathrm{3}^{\mathrm{2x}} +\mathrm{4}.\mathrm{3}^{\mathrm{x}}…