Question Number 122286 by ZiYangLee last updated on 15/Nov/20 $$\left(\mathrm{49}^{\mathrm{log}_{\mathrm{7}} \mathrm{6}} \right)^{\mathrm{log}_{\mathrm{3}} \mathrm{5}^{\mathrm{log}_{\mathrm{2}} \mathrm{3}^{\mathrm{log}_{\mathrm{5}} \mathrm{2}} } } =? \\ $$ Answered by TANMAY PANACEA last…
Question Number 187818 by 073 last updated on 22/Feb/23 $$\mathrm{1}.\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\sqrt{\mathrm{x}}=? \\ $$$$\mathrm{2}.\:\underset{{x}\rightarrow\mathrm{2}} {\mathrm{lim}}\sqrt{\mathrm{x}−\mathrm{2}}=? \\ $$$$\mathrm{solution}\:\mathrm{please} \\ $$ Answered by Frix last updated on 22/Feb/23…
Question Number 56732 by kelly33 last updated on 22/Mar/19 Commented by kelly33 last updated on 22/Mar/19 $${find}\:{all}\:{parameter}\:{values}\:{a} \\ $$$${with}\:{presentation}\:{equation} \\ $$$${has}\:{a}\:{solution}. \\ $$$$ \\ $$$$…
Question Number 56719 by naka3546 last updated on 22/Mar/19 $${The}\:\:{possible}\:\:{value}\:\:{of}\:\:{x}\:\:{that}\:\:{satisfy}\:\:: \\ $$$$\:\:\:\:\:\:\:\:{x}^{\mathrm{2}} \:+\:\lfloor{x}^{\mathrm{2}} \:−\:\mathrm{2}{x}\rfloor\:+\:\lceil{x}^{\mathrm{2}} \:+\:\mathrm{2}{x}\:+\:\mathrm{1}\rceil\:\:=\:\:\mathrm{2017}\:\:,\:\:{x}\:\in\:\:\mathbb{R}^{+} \\ $$$${and}\:\:\:\lfloor{x}^{\mathrm{2}} \rfloor\:−\:\lceil\mathrm{2}{x}\rceil\:\:=\:\:… \\ $$ Commented by tanmay.chaudhury50@gmail.com last updated…
Question Number 122244 by Olaf last updated on 15/Nov/20 $$\mathrm{Did}\:\mathrm{you}\:\mathrm{say}\:\mathrm{no}\:? \\ $$$$\mathrm{1}\:−\mathrm{Yes}. \\ $$$$\mathrm{2}\:−\:\mathrm{No}. \\ $$ Commented by Dwaipayan Shikari last updated on 15/Nov/20 $${I}\:{am}\:{in}\:{a}\:\boldsymbol{{Superposition}},\:\boldsymbol{{of}}\:\boldsymbol{{nothing}}…
Question Number 187760 by pascal889 last updated on 21/Feb/23 Commented by Frix last updated on 21/Feb/23 $$\mathrm{You}\:\mathrm{posted}\:\mathrm{this}\:\mathrm{before}\:\mathrm{in}\:\mathrm{question}\:\mathrm{186750} \\ $$ Commented by pascal889 last updated on…
Question Number 56694 by otchereabdullai@gmail.com last updated on 21/Mar/19 $$\mathrm{A}\:\mathrm{tv}\:\mathrm{set}\:\mathrm{was}\:\mathrm{marked}\:\mathrm{for}\:\mathrm{sale}\:\mathrm{at}\:\mathrm{760}.\mathrm{00} \\ $$$$\mathrm{cedis}\:\mathrm{in}\:\mathrm{order}\:\mathrm{to}\:\mathrm{make}\:\mathrm{a}\:\mathrm{profit}\:\mathrm{of}\:\mathrm{20\%}. \\ $$$$\mathrm{The}\:\mathrm{tv}\:\mathrm{was}\:\mathrm{actually}\:\mathrm{sold}\:\mathrm{at}\:\mathrm{a}\:\mathrm{discount}\: \\ $$$$\mathrm{of}\:\mathrm{5\%}.\:\mathrm{Calculate}\:\mathrm{to}\:\mathrm{2}\:\mathrm{s}.\mathrm{f}\:\mathrm{the}\:\mathrm{actual}\: \\ $$$$\mathrm{percentage}\:\mathrm{profit} \\ $$ Answered by mr W last…
Question Number 122216 by help last updated on 14/Nov/20 Answered by liberty last updated on 14/Nov/20 $$\:\ell\mathrm{n}\:\mathrm{f}\left(\mathrm{x}\right)\:=\:\mathrm{arc}\:\mathrm{sin}\:\mathrm{4x}\: \\ $$$$\:\frac{\mathrm{f}\:'\left(\mathrm{x}\right)}{\mathrm{f}\left(\mathrm{x}\right)}\:=\:\frac{\mathrm{4}}{\:\sqrt{\mathrm{1}+\mathrm{16x}^{\mathrm{2}} }}\:\Rightarrow\:\mathrm{f}\:'\left(\mathrm{x}\right)=\:\frac{\mathrm{4e}^{\mathrm{arc}\:\mathrm{sin}\:\mathrm{4x}} }{\:\sqrt{\mathrm{1}+\mathrm{16x}^{\mathrm{2}} }} \\ $$$$\:\mathrm{f}\:'\left(\frac{\mathrm{1}}{\mathrm{8}}\right)\:=\:\frac{\mathrm{4e}^{\frac{\pi}{\mathrm{6}}} }{\:\sqrt{\mathrm{1}+\frac{\mathrm{1}}{\mathrm{4}}}}\:=\:\frac{\mathrm{8e}^{\frac{\pi}{\mathrm{6}}}…
Question Number 187754 by 073 last updated on 21/Feb/23 Answered by horsebrand11 last updated on 21/Feb/23 $$\:{let}\:{f}\left({x}\right)={ax}+{b} \\ $$$$\:{f}\left(\mathrm{3}{x}+\mathrm{1}\right)=\mathrm{3}{ax}+{a}+{b} \\ $$$$\:{f}\left({x}−\mathrm{2}\right)={ax}−\mathrm{2}{a}+{b} \\ $$$$\:{f}\left(\mathrm{3}{x}+\mathrm{1}\right)+{f}\left({x}−\mathrm{2}\right)=\mathrm{4}{ax}−{a}+\mathrm{2}{b}=\mathrm{10}{x} \\ $$$$\:\begin{cases}{\mathrm{4}{a}=\mathrm{10}\Rightarrow{a}=\frac{\mathrm{5}}{\mathrm{2}}}\\{−{a}+\mathrm{2}{b}=\mathrm{0}\Rightarrow{b}=\frac{\mathrm{5}}{\mathrm{4}}}\end{cases}…
Question Number 122208 by harckinwunmy last updated on 14/Nov/20 $$\mathrm{how}\:\mathrm{do}\:\mathrm{i}\:\mathrm{expand}\: \\ $$$$\left(\mathrm{p}+\mathrm{q}+\mathrm{r}\right)^{\mathrm{3}} ? \\ $$$$\mathrm{i}\:\mathrm{need}\:\mathrm{general}\:\mathrm{principle}.\: \\ $$ Commented by liberty last updated on 14/Nov/20 $$\Rightarrow\left(\mathrm{p}+\mathrm{q}+\mathrm{r}\right)^{\mathrm{3}}…