Question Number 122995 by danielasebhofoh last updated on 21/Nov/20 Commented by MJS_new last updated on 22/Nov/20 $$\mathrm{there}'\mathrm{s}\:\mathrm{no}\:\mathrm{solution}\:\mathrm{for}\:\mathrm{the}\:\mathrm{simultaneous} \\ $$$$\mathrm{equations} \\ $$ Answered by mohammad17 last…
Question Number 122983 by Khalmohmmad last updated on 21/Nov/20 $$\int\mathrm{ln}\left(\mathrm{sin}{x}\right){dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 188512 by vishal1234 last updated on 02/Mar/23 $${x}^{\mathrm{3}} +\boldsymbol{{y}}^{\mathrm{3}} +\boldsymbol{{z}}^{\mathrm{3}} −\mathrm{3}\boldsymbol{{xyz}}= \\ $$$$\left(\boldsymbol{{x}}+\boldsymbol{{y}}+\boldsymbol{{z}}\right)\:\left(\boldsymbol{{x}}^{\mathrm{2}} +\boldsymbol{{y}}^{\mathrm{2}} +\boldsymbol{{z}}^{\mathrm{2}} −\boldsymbol{{xy}}−\boldsymbol{{yz}}−\boldsymbol{{zx}}\right) \\ $$$$\boldsymbol{{if}}\:\boldsymbol{{x}}+\boldsymbol{{y}}+\boldsymbol{{z}}\:=\:\mathrm{0},\:{then} \\ $$$${x}^{\mathrm{3}} +\boldsymbol{{y}}^{\mathrm{3}} +\boldsymbol{{z}}^{\mathrm{3}} −\mathrm{3}\boldsymbol{{xyz}}…
Question Number 57439 by naka3546 last updated on 04/Apr/19 $${Find}\:\:{all}\:\:{solutions}\:\:{of}\:\:{x},\:{y},\:{z}\:\:\:{integers}\:\:{that}\:\:{satisfy} \\ $$$$\:\:\:\:\:\:\:{x}^{\mathrm{3}} \:+\:{y}^{\mathrm{3}} \:+\:{z}^{\mathrm{3}} \:\:=\:\:\mathrm{33} \\ $$ Commented by Senior Sun last updated on 05/Apr/19…
Question Number 57433 by naka3546 last updated on 04/Apr/19 Answered by tanmay.chaudhury50@gmail.com last updated on 04/Apr/19 $$\int\frac{{x}^{\mathrm{4}} +\mathrm{1}}{{x}^{\mathrm{2}} \sqrt{{x}^{\mathrm{2}} \left({x}^{\mathrm{2}} −\frac{\mathrm{1}}{{x}^{\mathrm{2}} }\right)}}{dx} \\ $$$$\int\frac{{x}+\frac{\mathrm{1}}{{x}^{\mathrm{3}} }}{\:\sqrt{{x}^{\mathrm{2}}…
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Question Number 188492 by 073 last updated on 02/Mar/23 Commented by Rasheed.Sindhi last updated on 05/Mar/23 $${Is}\:'{der}'\:{means}\:{derivative}? \\ $$ Commented by 073 last updated on…
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Question Number 57390 by naka3546 last updated on 03/Apr/19 $${a}^{\mathrm{2}} \:+\:{d}^{\mathrm{2}} \:−\:{ad}\:\:=\:\:{b}^{\mathrm{2}} \:+\:{c}^{\mathrm{2}} \:+\:{bc} \\ $$$${a}^{\mathrm{2}} \:+\:{b}^{\mathrm{2}} \:\:=\:\:{c}^{\mathrm{2}} \:+\:{d}^{\mathrm{2}} \\ $$$$\frac{{ab}\:+\:{cd}}{{ad}\:+\:{bc}}\:\:=\:\:? \\ $$ Terms of…
Question Number 188441 by 073 last updated on 01/Mar/23 Answered by cortano12 last updated on 01/Mar/23 $$\mathrm{P}\left(\mathrm{x}−\mathrm{2}\right)=\left(\mathrm{x}−\mathrm{2}\right)^{\mathrm{2}} +\mathrm{4}\left(\mathrm{x}−\mathrm{2}\right)+\mathrm{1} \\ $$$$\mathrm{P}\left(\mathrm{x}−\mathrm{2}\right)=\mathrm{x}^{\mathrm{2}} −\mathrm{4x}+\mathrm{4}+\mathrm{4x}−\mathrm{8}+\mathrm{1} \\ $$$$\mathrm{P}\left(\mathrm{x}−\mathrm{2}\right)=\mathrm{x}^{\mathrm{2}} −\mathrm{3}\: \\…