Question Number 187613 by mustafazaheen last updated on 19/Feb/23 $${how}\:{is}\:{solution} \\ $$$$\left(\sqrt{\mathrm{2}}−\mathrm{1}\right)^{\mathrm{13}} =\mathrm{x}\:\:\:\:\:\:\:\:\:\:\left(\sqrt{\mathrm{2}}+\mathrm{1}\right)^{\mathrm{221}} =? \\ $$$$\left.\mathrm{1}\left.\right)\left.\mathrm{x}^{−\mathrm{16}} \left.\:\:\:\:\:\:\:\:\:\:\mathrm{2}\right)\mathrm{x}^{−\mathrm{17}} \:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{3}\right)\mathrm{x}^{\mathrm{221}} \:\:\:\:\:\:\:\:\:\:\:\:\mathrm{4}\right)\mathrm{x}^{\mathrm{21}} \\ $$ Commented by a.lgnaoui last…
Question Number 56540 by Gulay last updated on 18/Mar/19 Commented by Gulay last updated on 18/Mar/19 $$\mathrm{sir}\:\mathrm{plz}\:\mathrm{plz}\:\mathrm{help}\:\mathrm{me} \\ $$ Answered by MJS last updated on…
Question Number 187609 by otchereabdullai last updated on 19/Feb/23 $$\:{where}\:{is} \\ $$$${f}\left({x},{y}\right)=\frac{\mathrm{2}{x}−{y}}{{x}^{\mathrm{2}} +{y}^{\mathrm{2}} }\:\:{continious} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 187611 by otchereabdullai last updated on 19/Feb/23 $$\:{Use}\:{polar}\:{coordinate}\:{to}\:{find} \\ $$$${lim}\left({x},{y}\right)\rightarrow\left(\mathrm{0},\mathrm{0}\right)\:\frac{{y}^{\mathrm{2}} }{{x}^{\mathrm{2}} +{y}^{\mathrm{2}} } \\ $$ Answered by mahdipoor last updated on 19/Feb/23 $${not}\:{exist}\:…
Question Number 56534 by Gulay last updated on 18/Mar/19 Commented by Gulay last updated on 18/Mar/19 $$\mathrm{sir}\:\mathrm{could}\:\mathrm{you}\:\mathrm{help}\:\mathrm{me} \\ $$ Answered by MJS last updated on…
Question Number 187605 by otchereabdullai last updated on 19/Feb/23 $$\:{what}\:{is}\:{the}\:{name}\:{of}\:{the}\:{shape}\:{whose} \\ $$$${graph}\:{is}: \\ $$$$\left({a}\right)\:{f}\left({x},{y}\right)=\sqrt{{x}^{\mathrm{2}} +{y}^{\mathrm{2}} } \\ $$$$\: \\ $$$$\:\left({b}\right)\:{f}\left({x},{y}\right)={x}^{\mathrm{2}} +{y}^{\mathrm{2}} \\ $$$$\: \\ $$$$\:\:\left({c}\right)\:{f}\left({x},{y}\right)=\sqrt{\mathrm{1}−{x}^{\mathrm{2}}…
Question Number 187606 by otchereabdullai last updated on 19/Feb/23 $$\:{Use}\:{polar}\:{coordinate}\:{to}\:{find}\: \\ $$$${lim}\left({x},{y}\right)\rightarrow\left(\mathrm{0},\mathrm{0}\right)\:\frac{{x}^{\mathrm{2}} −{xy}^{\mathrm{2}} }{{x}^{\mathrm{2}} +{y}^{\mathrm{2}} } \\ $$ Answered by a.lgnaoui last updated on 19/Feb/23…
Question Number 122047 by help last updated on 13/Nov/20 Answered by TANMAY PANACEA last updated on 13/Nov/20 $$\mathrm{5}{x}+\mathrm{4}{y}=\mathrm{12} \\ $$$$\frac{{x}}{\mathrm{2}.\mathrm{4}}+\frac{{y}}{\mathrm{3}}=\mathrm{1} \\ $$$${line}\:{l}\:{and}\:{m}\:{intersect}\:{at}\:{point}\:{m}\left(\mathrm{2},\frac{\mathrm{1}}{\mathrm{2}}\right) \\ $$$${eqn}\:{of}\:{line}\:{m}\:\left({y}−\mathrm{0}.\mathrm{5}\right)=\left({tan}\theta\right)\left({x}−\mathrm{2}\right) \\…
Question Number 56503 by otchereabdullai@gmail.com last updated on 17/Mar/19 $$\mathrm{A}\:\mathrm{boat}\:\mathrm{travels}\:\mathrm{30km}\:\mathrm{upstream}\:\mathrm{and}\: \\ $$$$\mathrm{44km}\:\mathrm{downstream}\:\mathrm{in}\:\mathrm{10}\:\mathrm{hours}.\: \\ $$$$\mathrm{in}\:\mathrm{13}\:\mathrm{hours}\:\mathrm{it}\:\mathrm{can}\:\mathrm{travel}\:\mathrm{40km}\:\mathrm{upstream} \\ $$$$\mathrm{and}\:\mathrm{55km}\:\mathrm{downstream}.\:\mathrm{Determine}\:\mathrm{the} \\ $$$$\mathrm{speed}\:\mathrm{of}\:\mathrm{the}\:\mathrm{stream}\:\:\mathrm{and}\:\mathrm{that}\:\mathrm{of}\:\mathrm{the}\: \\ $$$$\mathrm{boat}\:\mathrm{in}\:\mathrm{still}\:\mathrm{water}.\:\left(\mathrm{in}\:\mathrm{km}/\mathrm{hr}\right) \\ $$ Answered by MJS…
Question Number 122045 by mohammad17 last updated on 13/Nov/20 $${prove}\:{that}\:\Gamma{s}\:\Gamma\mathrm{1}−{s}=\frac{\pi}{{sins}\pi} \\ $$ Commented by Dwaipayan Shikari last updated on 14/Nov/20 $$\Gamma\left({s}\right)=\frac{{e}^{−\gamma{s}} }{{s}}\overset{\infty} {\prod}{e}^{\frac{{s}}{{n}}} \left(\mathrm{1}+\frac{{s}}{{n}}\right)^{−\mathrm{1}} \\…