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Solve-log-2x-2-log-3x-2-log-2-2-log-3-2-

Question Number 121899 by ZiYangLee last updated on 12/Nov/20 $$\mathrm{Solve}\:\left(\mathrm{log}\:\mathrm{2}{x}\right)^{\mathrm{2}} +\left(\mathrm{log}\:\mathrm{3}{x}\right)^{\mathrm{2}} =\left(\mathrm{log}\:\mathrm{2}\right)^{\mathrm{2}} +\left(\mathrm{log}\:\mathrm{3}\right)^{\mathrm{2}} \\ $$ Commented by Dwaipayan Shikari last updated on 12/Nov/20 $${x}=\mathrm{1} \\…

log-3-2y-1-2-log-3-6y-2-log-3-2y-

Question Number 56351 by otchereabdullai@gmail.com last updated on 15/Mar/19 $$\mathrm{log}_{\mathrm{3}} \left(\mathrm{2y}+\mathrm{1}\right)+\mathrm{2}=\mathrm{log}_{\mathrm{3}} \mathrm{6y}^{\mathrm{2}} −\mathrm{log}_{\mathrm{3}} \mathrm{2y} \\ $$ Answered by $@ty@m last updated on 15/Mar/19 $$\mathrm{log}_{\mathrm{3}} \left(\mathrm{2y}+\mathrm{1}\right)+\mathrm{log}_{\mathrm{3}}…

sec-2-x-1-tan-2-x-dx-

Question Number 187408 by MathsFan last updated on 17/Feb/23 $$\:\int\frac{\boldsymbol{\mathrm{sec}}^{\mathrm{2}} \boldsymbol{\mathrm{x}}}{\:\sqrt{\mathrm{1}−\boldsymbol{\mathrm{tan}}^{\mathrm{2}} \boldsymbol{\mathrm{x}}}}\boldsymbol{\mathrm{dx}} \\ $$ Answered by horsebrand11 last updated on 17/Feb/23 $$\:=\:\int\:\frac{{d}\left(\mathrm{tan}\:{x}\right)}{\:\sqrt{\mathrm{1}−\mathrm{tan}\:^{\mathrm{2}} {x}}}\:;\:{u}=\mathrm{tan}\:{x} \\ $$$$=\int\:\frac{{du}}{\:\sqrt{\mathrm{1}−{u}^{\mathrm{2}}…

make-r-the-subject-of-P-1-r-100-t-

Question Number 56336 by otchereabdullai@gmail.com last updated on 14/Mar/19 $$\mathrm{make}\:\:\mathrm{r}\:\:\mathrm{the}\:\mathrm{subject}\:\mathrm{of}\:\:\: \\ $$$$\mathrm{P}=\left(\mathrm{1}+\frac{\mathrm{r}}{\mathrm{100}}\right)^{\mathrm{t}} \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on 14/Mar/19 $${question}\:{not}\:{clear}…. \\ $$$${p}=\left(\mathrm{1}+\frac{{r}}{\mathrm{100}}\right)^{{t}} \\…

a-C-determinant-a-1-1-1-1-1-1-a-

Question Number 187401 by aba last updated on 16/Feb/23 $$\mathrm{a}\in\mathbb{C} \\ $$$$\begin{vmatrix}{\mathrm{a}\:\:\:\mathrm{1}\:\:\:\:\ldots\:\:\:\mathrm{1}}\\{\mathrm{1}\:\:\:\ddots\:\:\ddots\:\:\vdots}\\{\vdots\:\:\ddots\:\:\ddots\:\:\mathrm{1}}\\{\mathrm{1}\:\:\:\:\ldots\:\:\:\:\mathrm{1}\:\:\:\mathrm{a}}\end{vmatrix}=? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com

Question-121866

Question Number 121866 by danielasebhofoh last updated on 12/Nov/20 Answered by TANMAY PANACEA last updated on 12/Nov/20 $${y}={cos}\left({x}^{{x}^{{x}} } {lnx}\right) \\ $$$${y}={cosu}\rightarrow\frac{{dy}}{{du}}=−{sinu}=−{sin}\left({x}^{{x}^{{x}} } {lnx}\right) \\…

a-b-C-determinant-a-b-a-0-0-b-a-b-0-0-

Question Number 187400 by aba last updated on 16/Feb/23 $$\mathrm{a},\mathrm{b}\in\mathbb{C} \\ $$$$\:\begin{vmatrix}{\mathrm{a}+\mathrm{b}\:\:\:\:\:\:\:\:\:\mathrm{a}\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{0}\:\:\:\:\:\:\:\:\ldots\:\:\:\:\:\:\:\:\:\:\:\mathrm{0}}\\{\:\:\:\mathrm{b}\:\:\:\:\:\:\:\:\:\:\mathrm{a}+\mathrm{b}\:\:\:\:\:\:\ddots\:\:\:\:\:\:\ddots\:\:\:\:\:\:\:\:\:\:\:\:\vdots}\\{\:\:\:\mathrm{0}\:\:\:\:\:\:\:\:\:\:\:\:\ddots\:\:\:\:\:\:\:\:\ddots\:\:\:\:\:\:\:\ddots\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{0}}\\{\:\:\vdots\:\:\:\:\:\:\:\:\:\:\ddots\:\:\:\:\:\:\:\:\:\ddots\:\:\:\:\:\:\ddots\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{a}}\\{\:\:\:\mathrm{0}\:\:\:\:\:\:\:\:\:\:\:\ldots\:\:\:\:\:\:\:\:\:\mathrm{0}\:\:\:\:\:\:\:\:\:\:\mathrm{b}\:\:\:\:\:\:\:\:\:\:\:\mathrm{a}+\mathrm{b}}\end{vmatrix}=? \\ $$ Answered by aba last updated on 16/Feb/23 $$\mathrm{help}\:\mathrm{please}\upuparrows \\ $$ Terms…

8x-16-x-x-

Question Number 121850 by Khalmohmmad last updated on 12/Nov/20 $$\mathrm{8}{x}=\mathrm{16}^{{x}} \\ $$$${x}=? \\ $$ Answered by mr W last updated on 12/Nov/20 $$\mathrm{8}{x}={e}^{{x}\mathrm{ln}\:\mathrm{16}} \\ $$$$\mathrm{8}{x}×{e}^{−{x}\mathrm{ln}\:\mathrm{16}}…