Question Number 121422 by faysal last updated on 08/Nov/20 $${a}\:{rectangle}'{s}\:{a}\:{side}'{s}\:{terminal} \\ $$$${points}\:{coordinate}\:{are}\:\left(\mathrm{2},−\mathrm{1}\right),\:\left(\mathrm{6},\mathrm{5}\right)\:{and}\:{the} \\ $$$${length}\:{of}\:{the}\:{diagonal}\:{is}\:\mathrm{8}\:{unit}. \\ $$$${what}\:{are}\:{coordinate}\:{of}\:{terminal}\:{point} \\ $$$${of}\:{paralel}\:{side}\:{that}\:{side} \\ $$ Commented by mr W last…
Question Number 121418 by faysal last updated on 08/Nov/20 $${a}\:{changeable}\:{straight}\:{line}\:{going}\:{the}\:{point}\:\left({a},{b}\right) \\ $$$${creates}\:{a}\:{triangle}\:{with}\:{axes}.\:{what}\:{is}\: \\ $$$${the}\:{equation}\:{of}\:{locus}\:{of}\:{centroid}\:{of} \\ $$$${the}\:{triangle} \\ $$ Answered by TANMAY PANACEA last updated on…
Question Number 186958 by Beginner last updated on 12/Feb/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 186951 by Humble last updated on 12/Feb/23 Answered by integralmagic last updated on 12/Feb/23 $$ \\ $$$$={ln}\mathrm{2} \\ $$ Answered by SEKRET last…
Question Number 186952 by Humble last updated on 12/Feb/23 Answered by horsebrand11 last updated on 12/Feb/23 $${let}\:\mathrm{3}{x}+\mathrm{2}{y}+{c}\:=\:\mathrm{0}\:{is}\:{tangent}\:{to} \\ $$$${hypebola}\:.\:{we}\:{have}\:\frac{\mathrm{1}}{\mathrm{12}}{x}−\frac{\mathrm{1}}{\mathrm{9}}{y}.{y}'=\mathrm{0} \\ $$$$\Rightarrow{y}'=\frac{\frac{\mathrm{3}}{\mathrm{36}}{x}}{\frac{\mathrm{4}}{\mathrm{36}}{y}}\:=\:\frac{\mathrm{3}{x}}{\mathrm{4}{y}}\:=\:−\frac{\mathrm{3}}{\mathrm{2}} \\ $$$$\Rightarrow{x}=−\mathrm{2}{y}\:{and}\:\frac{\mathrm{4}{y}^{\mathrm{2}} }{\mathrm{24}}−\frac{{y}^{\mathrm{2}} }{\mathrm{18}}\:=\mathrm{1}…
Question Number 186950 by 073 last updated on 12/Feb/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 121392 by help last updated on 07/Nov/20 Commented by Dwaipayan Shikari last updated on 07/Nov/20 $${At}\:{which}\:{velocity}\:{at}\:{the}\:{sea}\:{level}\:? \\ $$ Terms of Service Privacy Policy…
Question Number 121393 by faysal last updated on 07/Nov/20 $${a}\:{square}'{s}\:{one}\:{diagonal}'{s}\:{terminal}\:{points}\:{are} \\ $$$$\left(\mathrm{5},\mathrm{0}\right),\:\left(\mathrm{9},\mathrm{4}\right)\:{what}\:{are}\:{the}\:{coordinate}\:{of} \\ $$$${other}\:{diagonal}'{s}\:{terminal}\:{points} \\ $$ Answered by TANMAY PANACEA last updated on 07/Nov/20 $${Disgonal}\:{eqn}\:\:\frac{{y}−\mathrm{0}}{\mathrm{0}−\mathrm{4}}=\frac{{x}−\mathrm{5}}{\mathrm{5}−\mathrm{9}}\rightarrow{x}−{y}−\mathrm{5}=\mathrm{0}…
Question Number 186925 by Humble last updated on 12/Feb/23 Commented by Humble last updated on 12/Feb/23 $${help}\:\:{with}\:{the}\:{solution}\:{please} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 186923 by Humble last updated on 12/Feb/23 Terms of Service Privacy Policy Contact: info@tinkutara.com