Question Number 227198 by Hanuda354 last updated on 05/Jan/26 Commented by Hanuda354 last updated on 05/Jan/26 $$\mathrm{Given}\:\mathrm{a}\:\mathrm{square}\:\mathrm{with}\:\mathrm{four}\:\mathrm{semicircles}\:\mathrm{and}\:\mathrm{a}\:\mathrm{quarter}\:\mathrm{circle},\:\mathrm{where}\:\mathrm{the}\:\mathrm{blue} \\ $$$$\mathrm{point}\:\mathrm{is}\:\mathrm{on}\:\mathrm{the}\:\mathrm{top}\:\mathrm{of}\:\mathrm{the}\:\mathrm{smaller}\:\mathrm{semicircle}\:\mathrm{on}\:\mathrm{bottom}\:\mathrm{right}. \\ $$$$\mathrm{Determine}\:\mathrm{the}\:\mathrm{area}\:\mathrm{of}\:\mathrm{the}\:\mathrm{shaded}\:\mathrm{region}\:\left(\mathrm{purple}\:\mathrm{area}\right).\: \\ $$ Answered by…
Question Number 227111 by fantastic2 last updated on 31/Dec/25 $${Happy}\:{new}\:{year}\:{guys}! \\ $$$$ \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 227063 by fantastic2 last updated on 29/Dec/25 $${is}\:\left(−{e}\right)^{\pi} \:\:{real}\:{number}? \\ $$ Answered by Frix last updated on 29/Dec/25 $$\left.\begin{matrix}{\mathrm{abs}\:\left(−\mathrm{e}\right)\:=\mathrm{e}}\\{\mathrm{arg}\:\left(−\mathrm{e}\right)\:=\pi}\end{matrix}\right\}\:\Rightarrow\:−\mathrm{e}=\mathrm{e}^{\mathrm{i}\pi} \mathrm{e} \\ $$$$\left(−\mathrm{e}\right)^{\pi} =\mathrm{e}^{\mathrm{i}\pi^{\mathrm{2}}…
Question Number 227011 by fantastic2 last updated on 25/Dec/25 $${in}\:{a}\:{cup}\:{filled}\:{with}\:{a}\:{liquid}\:{of}\:{density}\:\rho,{a} \\ $$$${bubble}\:{rests}\:{in}\:{the}\:{liquid}\:{in}\:{h}\:{deepness}. \\ $$$${radius}\:{initial}\:{of}\:{the}\:{bubble}={r}_{{i}} \\ $$$$\:{initial}\:{density}\:{of}\:{the}\:{bubble}=\sigma_{{i}} \\ $$$$\left(\:{mass\&temparature}\:{is}\:{constant}\right) \\ $$$${a}\:{small}\:{jerk}\:{is}\:{given}\:{to}\:{the}\:{cup}\:{and}\:{the} \\ $$$${bubble}\:{starts}\:{to}\:{go}\:{upwards}. \\ $$$${find}: \\…
Question Number 227002 by fantastic2 last updated on 24/Dec/25 $${merry}\:{christmas}\:{to}\:{all}\:{of}\:{you}\:{guys}! \\ $$ Commented by AgniMath last updated on 25/Dec/25 $${merry}\:{christmas} \\ $$ Commented by Kassista…
Question Number 226962 by MDYeaminJr last updated on 22/Dec/25 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 226907 by fantastic2 last updated on 18/Dec/25 $${two}\:{small}\:{balls}\:{are}\:{hung}\:{from}\:{a}\:{point} \\ $$$$\left({same}\:{mass},\:{same}\:{charge}\:{and}\:{rope}\:{length}\:{are}\:{same}\right) \\ $$$${the}\:{two}\:{strings}\:{make}\:{an}\:{angle}\:\mathrm{30}^{\mathrm{0}} \\ $$$${when}\:{immersed}\:{in}\:{a}\:{liquid}\:{of}\:\rho=\mathrm{0}.\mathrm{8}{g}/{cc} \\ $$$${the}\:{angle}\:{remains}\:{same}.\rho_{{ball}} =\mathrm{1}.\mathrm{6}{g}/{cc} \\ $$$${what}\:{is}\:{the}\:{value}\:{of}\:\kappa\left({dielectric}\:{const}.\right){of} \\ $$$${the}\:{liquid} \\ $$…
Question Number 226855 by Kassista last updated on 17/Dec/25 Answered by mehdee7396 last updated on 17/Dec/25 $${x}^{\mathrm{2}} +\mathrm{4}{x}^{\mathrm{2}} −\mathrm{4}{x}+\mathrm{4}=\mathrm{4}\Rightarrow{x}=\mathrm{0},\frac{\mathrm{8}}{\mathrm{5}} \\ $$$$\Rightarrow{P}\left(\mathrm{0},,\mathrm{2}\right)\:\&\:\:{Q}\left(\frac{\mathrm{8}}{\mathrm{5}},−\frac{\mathrm{6}}{\mathrm{5}}\right)\Rightarrow{m}_{{PQ}} =−\frac{\mathrm{3}}{\mathrm{4}} \\ $$$$\Rightarrow{tan}\alpha=\frac{\mathrm{3}}{\mathrm{4}}\backsimeq\mathrm{36}^{\mathrm{0}} \Rightarrow\angle{POQ}\backsimeq\mathrm{126}^{\mathrm{0}}…
Question Number 226828 by fantastic2 last updated on 16/Dec/25 $$\frac{{d}^{\pi} }{{dx}^{\pi} }\left({x}^{\pi} \right)=? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 226809 by fantastic2 last updated on 15/Dec/25 $$\phi_{{E}} =\oint_{{S}} \frac{{q}}{\mathrm{4}\pi\epsilon}\:{d}\omega \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com