Question Number 121154 by zakirullah last updated on 05/Nov/20 Answered by Bird last updated on 05/Nov/20 $${let}\:{f}\left({n}\right)={u}_{{n}} \:\Rightarrow{u}_{{n}} =\mathrm{6}{u}_{{m}−\mathrm{1}} −\mathrm{9}{u}_{{n}−\mathrm{2}} \\ $$$${u}_{\mathrm{0}} =\mathrm{1}\:\:{and}\:{u}_{\mathrm{2}} =\mathrm{2} \\…
Question Number 186689 by SANOGO last updated on 08/Feb/23 $$\underset{{n}={o}} {\overset{+{oo}} {\sum}}\:\frac{{x}^{\mathrm{3}{n}} }{\left(\mathrm{2}{n}\right)!}\:\:=\:\:\:? \\ $$ Commented by mr W last updated on 08/Feb/23 $${why}\:{not}\:\infty\:{instead}\:{of}\:{oo}? \\…
Question Number 186688 by norboyev last updated on 08/Feb/23 $${a}_{\mathrm{1}} =\mathrm{0} \\ $$$${a}_{\mathrm{2}} =\mathrm{1} \\ $$$${a}_{{n}+\mathrm{2}} ={a}_{{n}+\mathrm{1}} −{a}_{{n}} \\ $$$${a}_{\mathrm{885}} =? \\ $$ Commented by…
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Question Number 186691 by 073 last updated on 08/Feb/23 Answered by Ar Brandon last updated on 08/Feb/23 $$\mathrm{tan}^{−\mathrm{1}} \left(\mathrm{cot}{x}\right)=\frac{\pi}{\mathrm{2}}−\mathrm{tan}^{−\mathrm{1}} \left(\mathrm{tan}{x}\right)=\frac{\pi}{\mathrm{2}}−{x} \\ $$$$\int\mathrm{tan}^{−\mathrm{1}} \left(\mathrm{cot}{x}\right){dx}=\int\left(\frac{\pi}{\mathrm{2}}−{x}\right){dx} \\ $$…
Question Number 186685 by norboyev last updated on 08/Feb/23 $$\left(\mathrm{sin}{x}\right)^{\mathrm{2}} −\frac{\mathrm{1}}{\mathrm{2}}\mathrm{sin2}{x}−\mathrm{2}\left(\mathrm{cos}{x}\right)^{\mathrm{2}} \geq\mathrm{0} \\ $$$${x}\in\left[\mathrm{0};\mathrm{2}\pi\right] \\ $$ Answered by Ar Brandon last updated on 08/Feb/23 $$\mathrm{sin}^{\mathrm{2}}…
Question Number 186680 by mathocean1 last updated on 08/Feb/23 $${study}\:{the}\:{convergence}\:{of}: \\ $$$$\underset{{n}=\mathrm{1}} {\overset{+\infty} {\sum}}\underset{{k}=\mathrm{1}} {\overset{{n}} {\prod}}\left(\mathrm{1}−{e}^{\left(\frac{\mathrm{1}}{{k}}\right)} \right) \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 186681 by mathocean1 last updated on 08/Feb/23 $${Etudier}\:{la}\:{convergence}\:{uniforme} \\ $$$$\underset{{n}=\mathrm{0}} {\overset{+\infty} {\sum}}\left(−\right)^{{n}} \frac{{e}^{−{nx}^{\mathrm{2}} } }{\left(\mathrm{1}+{n}\right)^{\mathrm{3}} }\:;\:{n}\:\in\:\mathbb{N}. \\ $$ Terms of Service Privacy Policy…
Question Number 186675 by pascal889 last updated on 08/Feb/23 Answered by ARUNG_Brandon_MBU last updated on 08/Feb/23 $$\ast\mathrm{The}\:\mathrm{ratio}\:\mathrm{of}\:\mathrm{girls}\:\mathrm{to}\:\mathrm{boys}\:\mathrm{is}\:\mathrm{5}:\mathrm{6} \\ $$$$\Rightarrow\:\frac{{G}}{{B}}=\frac{\mathrm{5}}{\mathrm{6}}\:\Rightarrow{G}=\frac{\mathrm{5}}{\mathrm{6}}{B}\:…\mathrm{eqn}\left({i}\right) \\ $$$$\ast\mathrm{On}\:\mathrm{a}\:\mathrm{rainy}\:\mathrm{day}: \\ $$$$\:\frac{\mathrm{1}}{\mathrm{6}}{G}\:\mathrm{were}\:\mathrm{absent}\:\Rightarrow\frac{\mathrm{5}}{\mathrm{6}}{G}\:\mathrm{were}\:\mathrm{present}. \\ $$$$\frac{\mathrm{1}}{\mathrm{4}}{B}\:\mathrm{were}\:\mathrm{absent}\:\Rightarrow\frac{\mathrm{3}}{\mathrm{4}}{B}\:\mathrm{were}\:\mathrm{present}.…
Question Number 186666 by aba last updated on 08/Feb/23 $$\mathrm{a},\mathrm{b}>\mathrm{0}\:,\:\mathrm{a}+\mathrm{b}=\mathrm{2} \\ $$$$\mathrm{Prove}\:\mathrm{that}\:\mathrm{a}^{\mathrm{2b}} +\mathrm{b}^{\mathrm{2a}} +\left(\frac{\mathrm{a}−\mathrm{b}}{\mathrm{2}}\right)^{\mathrm{2}} \leqslant\mathrm{2} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com