Question Number 187072 by Humble last updated on 13/Feb/23 $${let}\:{x}\:{be}\:{the}\:{Discrete}\:{random}\:{variable}\:{with}\:\left({PGF}\right)\: \\ $$$${P}_{{x}} \left({t}\right)\:=\:\frac{{t}}{\mathrm{5}}\left(\mathrm{2}+\mathrm{3}{t}^{\mathrm{2}} \right) \\ $$$${find}\:{the}\:{distribution}\:{of}\:{x} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 187069 by Humble last updated on 13/Feb/23 $$\left(\mathrm{2}{x}\:−\mathrm{3}{y}\:+\mathrm{2}{z}\:+\mathrm{4}\right)^{\mathrm{2}\:} +\left({x}−{y}−{z}\right)^{\mathrm{2}} +\left({x}+{y}+{z}−\mathrm{8}\right)^{\mathrm{2}} =\mathrm{0} \\ $$$${find} \\ $$$${x}\:,\:{y},\:{z}\: \\ $$ Answered by ARUNG_Brandon_MBU last updated on…
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Question Number 187054 by Humble last updated on 13/Feb/23 Commented by mr W last updated on 13/Feb/23 $${do}\:{you}\:{see}\:{an}\:{equation}? \\ $$ Commented by Frix last updated…
Question Number 55980 by Hassen_Timol last updated on 07/Mar/19 $${Does}\:{the}\:{function}\:{f}\left({x}\right)\:=\:{x}^{{x}} \:{have} \\ $$$${an}\:{antiderivative}\:? \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\Box\:{yes}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\Box\:{no} \\ $$$${How}\:{this}\:{may}\:{be}\:{proved}\:? \\ $$ Commented by 121194 last updated on…
Question Number 187051 by pascal889 last updated on 13/Feb/23 Commented by mr W last updated on 13/Feb/23 $$\left(\mathrm{1}+\frac{\mathrm{1}}{\mathrm{1000}}\right)^{\mathrm{8}} =\underset{{n}=\mathrm{0}} {\overset{\mathrm{8}} {\sum}}\frac{{C}_{{n}} ^{\mathrm{8}} }{\mathrm{10}^{\mathrm{3}{n}} } \\…
Question Number 187046 by Humble last updated on 12/Feb/23 $${find}\:\:\:{the}\:{general}\:\:{solution}\:{for}\:\:{the}\:{following} \\ $$$${system}\:{of}\:{equations} \\ $$$$\left(\frac{{dx}_{\mathrm{1}} }{{dt}}\right)=\mathrm{2}{x}_{\mathrm{1}} +\mathrm{2}{x}_{\mathrm{2}} \\ $$$$\left(\frac{{dx}_{\mathrm{2}} }{{dt}}\right)={x}_{\mathrm{1}} +\mathrm{3}{x}_{\mathrm{2}} \\ $$$$ \\ $$ Answered…
Question Number 187044 by Humble last updated on 12/Feb/23 $${f}\left({x},{y}\right)=\left\{\left({x}+{y}\right),\mathrm{0}<{x}<\mathrm{1},\:\mathrm{0}<{y}<\mathrm{1}\right. \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{0},\:{otherwise} \\ $$$${find}: \\ $$$$\left(\mathrm{1}\right)\:\sigma{xy} \\ $$$$ \\ $$$$\left(\mathrm{2}\right)\:\:{p}\left(\mathrm{0}<{x}<\left(\frac{\mathrm{1}}{\mathrm{4}}\right)\mid\left(\frac{\mathrm{2}}{\mathrm{5}}\right)>{y}>\left(\frac{\mathrm{1}}{\mathrm{3}}\right)\right) \\ $$$$ \\ $$$${note}:\:{f}\left({x},{y}\right)\:{is}\:{the}\:{joint}\:{PDF} \\…
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Question Number 187029 by yaslm last updated on 12/Feb/23 Answered by cortano12 last updated on 12/Feb/23 $$\:\left(\mathrm{1}\right)\:\underset{{x}\rightarrow−\mathrm{2}^{−} } {\mathrm{lim}}\:\left({ax}+{b}\right)=\:\underset{{x}\rightarrow−\mathrm{2}^{+} } {\mathrm{lim}}\left({x}^{\mathrm{2}} +\mathrm{2}{b}−\mathrm{17}\right) \\ $$$$\:\:\:\:\:\:\:−\mathrm{2}{a}+{b}\:=\:\mathrm{4}+\mathrm{2}{b}−\mathrm{17} \\…