Question Number 190811 by otchereabdullai last updated on 12/Apr/23 $$\:{If}\:{the}\:{angle}\:{between}\:{the}\:{vectors} \\ $$$$\:{c}\:={ai}+\mathrm{2}{j}\:{and}\:\:{d}=\mathrm{3}{i}+{j}\:{is}\:\mathrm{45}°\:,\:{find} \\ $$$$\:{the}\:{two}\:{possible}\:{values}\:{of}\:{a} \\ $$ Answered by safojontoshtemirov last updated on 12/Apr/23 $${c}=\left({a};\mathrm{2}\right)\:{d}=\left(\mathrm{3};\mathrm{1}\right) \\…
Question Number 59733 by otchereabdullai@gmail.com last updated on 14/May/19 $$\mathrm{If}\:\mathrm{y}=\sqrt{\mathrm{x}}\:\:,\mathrm{find}\:\mathrm{approximate}\:\mathrm{value}\:\mathrm{of}\: \\ $$$$\:\sqrt{\mathrm{101}} \\ $$ Commented by prakash jain last updated on 14/May/19 $$\left(\mathrm{101}\right)^{\mathrm{1}/\mathrm{2}} =\mathrm{100}^{\mathrm{1}/\mathrm{2}} \left(\mathrm{1}+\frac{\mathrm{1}}{\mathrm{100}}\right)^{\mathrm{1}/\mathrm{2}}…
Question Number 125266 by ZiYangLee last updated on 09/Dec/20 $$\mathrm{Let}\:{S}_{{n}} =\mathrm{1}+\mathrm{11}+\mathrm{111}+\mathrm{1111}+\mathrm{11111}+\ldots\:\mathrm{to}\:{n}\:\mathrm{terms} \\ $$$$\mathrm{Show}\:\mathrm{that}\:{S}_{{n}} =\frac{\mathrm{10}^{{n}+\mathrm{1}} −\mathrm{10}−\mathrm{9}{n}}{\mathrm{81}} \\ $$ Answered by Dwaipayan Shikari last updated on 09/Dec/20…
Question Number 59730 by muneshkumar last updated on 14/May/19 $$\mathrm{5}^{\mathrm{2}{x}−\mathrm{1}\:} =\mathrm{25}^{{x}−\mathrm{1}} +\mathrm{100}\:{find}\:{value}\:{of}\:\mathrm{3}^{\mathrm{3}−{x}} \\ $$ Answered by tanmay last updated on 14/May/19 $$\frac{\mathrm{5}^{\mathrm{2}{x}} }{\mathrm{5}}=\left(\mathrm{5}^{\mathrm{2}} \right)^{{x}−\mathrm{1}} +\mathrm{100}…
Question Number 190800 by 07049753053 last updated on 12/Apr/23 $$\frac{\boldsymbol{\mathrm{d}}^{\boldsymbol{\mathrm{n}}} }{\boldsymbol{\mathrm{da}}^{\boldsymbol{\mathrm{n}}} }\boldsymbol{\Gamma}\left(\boldsymbol{{a}}+\mathrm{1}\right)=? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 125264 by mohammad17 last updated on 09/Dec/20 Answered by Ar Brandon last updated on 09/Dec/20 $$\mathrm{x}^{\mathrm{2}} −\mathrm{x}+\mathrm{1}=\mathrm{0}\:\Rightarrow\:\mathrm{x}^{\mathrm{2}} =\mathrm{x}−\mathrm{1} \\ $$$$\Rightarrow\mathrm{x}^{\mathrm{3}} =\mathrm{x}^{\mathrm{2}} −\mathrm{x}=\mathrm{x}−\mathrm{1}−\mathrm{x}=−\mathrm{1} \\…
Question Number 59727 by muneshkumar last updated on 14/May/19 $${a}={b}^{\mathrm{2}{p}\:\:} {b}={c}^{\mathrm{2}{q}\:} \:{c}={a}^{\mathrm{2}{r}} \:{prove}\:{that}\:{pqr}=\frac{\mathrm{1}}{\mathrm{8}} \\ $$ Answered by MJS last updated on 13/May/19 $$\mathrm{ln}\:{a}\:=\mathrm{2}{p}\mathrm{ln}\:{b} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{ln}\:{b}\:=\mathrm{2}{q}\mathrm{ln}\:{c}…
Question Number 125263 by mohammad17 last updated on 09/Dec/20 Commented by mohammad17 last updated on 09/Dec/20 $${help}\:{me}\:{sir} \\ $$ Answered by Olaf last updated on…
Question Number 125256 by 676597498 last updated on 09/Dec/20 $$\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{\mathrm{6}^{{n}} }{\left(\mathrm{3}^{{n}} −\mathrm{2}^{{n}} \right)\left(\mathrm{3}^{{n}+\mathrm{1}} −\mathrm{2}^{{n}+\mathrm{1}} \right)} \\ $$ Answered by mathmax by abdo last…
Question Number 125257 by Schwartzman94 last updated on 09/Dec/20 $${S}=\frac{{C}_{{n}} ^{\mathrm{0}} }{{C}_{{n}+\mathrm{2}} ^{\mathrm{1}} }+\frac{{C}_{{n}} ^{\mathrm{1}} }{{C}_{{n}+\mathrm{2}} ^{\mathrm{2}} }+…+\frac{{C}_{{n}} ^{{n}} }{{C}_{{n}+\mathrm{2}} ^{{n}+\mathrm{1}} } \\ $$ Commented…