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Question Number 209718 by Ismoiljon_008 last updated on 19/Jul/24 Answered by mr W last updated on 19/Jul/24 $${a}_{{n}} =\frac{\mathrm{1}}{{n}!×\left({n}+\mathrm{2}\right)}=\frac{\mathrm{1}}{\left({n}+\mathrm{1}\right)!}−\frac{\mathrm{1}}{\left({n}+\mathrm{2}\right)!} \\ $$$$\underset{{n}=\mathrm{1}} {\overset{\mathrm{2023}} {\sum}}{a}_{{n}} =\left(\frac{\mathrm{1}}{\mathrm{2}!}−\frac{\mathrm{1}}{\mathrm{3}!}\right)+\left(\frac{\mathrm{1}}{\mathrm{3}!}−\frac{\mathrm{1}}{\mathrm{4}!}\right)+…+\left(\frac{\mathrm{1}}{\mathrm{2024}!}−\frac{\mathrm{1}}{\mathrm{2025}!}\right. \\…

Question Number 209672 by Ansu last updated on 18/Jul/24 Answered by som(math1967) last updated on 18/Jul/24 $$\:\frac{\mathrm{3}{x}−\mathrm{1}}{\mathrm{4}}=\frac{\mathrm{9}−{x}}{{x}} \\ $$$$\Rightarrow\mathrm{3}{x}^{\mathrm{2}} −{x}=\mathrm{36}−\mathrm{4}{x} \\ $$$$\Rightarrow\mathrm{3}{x}^{\mathrm{2}} +\mathrm{3}{x}−\mathrm{36}=\mathrm{0} \\ $$$$\Rightarrow{x}^{\mathrm{2}}…

Question Number 209671 by Ansu last updated on 18/Jul/24 $$\mathrm{5}{x}+\mathrm{3}{x}=\mathrm{10} \\ $$ Answered by SWPlaysMC last updated on 19/Jul/24 $${x}=\frac{\mathrm{5}}{\mathrm{4}} \\ $$ Answered by Frix…

Question Number 209659 by mokys last updated on 17/Jul/24 Answered by efronzo1 last updated on 18/Jul/24 $$\:\:\:\mathrm{S}\:=\:\underset{\mathrm{0}} {\overset{\mathrm{1}} {\int}}\:\mathrm{2}^{\mathrm{x}} \:\mathrm{dx}\:+\:\underset{\mathrm{1}} {\overset{\sqrt{\mathrm{3}}} {\int}}\:\left(\mathrm{3}−\mathrm{x}^{\mathrm{2}} \right)\mathrm{dx} \\ $$…

Question Number 209630 by otchereabdullai@gmail.com last updated on 16/Jul/24 $$\:\:{If}\:{A}\:\:{varies}\:{as}\:{r}^{\mathrm{2}} \:{and}\:{V}\:\:{varies}\:{as}\:{r}^{\mathrm{3}} \\ $$$$\:{find}\:{percentage}\:{increase}\:{in}\:{A}\:{and}\:{V} \\ $$$$\:{if}\:\:{r}\:{is}\:{increased}\:{by}\:\mathrm{20\%} \\ $$ Answered by som(math1967) last updated on 17/Jul/24 $$\:{A}\propto{r}^{\mathrm{2}}…