Question Number 121301 by mathdave last updated on 06/Nov/20 Answered by JDamian last updated on 07/Nov/20 $$\left.\mathrm{1}\right)\:\mathrm{328}.\mathrm{3125}\:\:\mathrm{N}/\mathrm{m} \\ $$$$\left.\mathrm{2}\right)\:\:\mathrm{19}.\mathrm{5}\:\:\:\mathrm{m}/\mathrm{s} \\ $$$$\left.\mathrm{3}\right)\:\:\mathrm{656}.\mathrm{625}\:\mathrm{J} \\ $$ Commented by…
Question Number 121293 by abdullahquwatan last updated on 06/Nov/20 $$\mathrm{give}\:\mathrm{me}\:\mathrm{difficult}\:\mathrm{problems}\:\mathrm{exponent}\: \\ $$ Commented by liberty last updated on 06/Nov/20 $$\mathrm{3}^{\mathrm{2x}+\mathrm{1}} \:−\mathrm{4}.\mathrm{3}^{\mathrm{x}} \:=\:\left(\sqrt{−\mathrm{x}^{\mathrm{2}} −\frac{\mathrm{x}}{\mathrm{2}}+\frac{\mathrm{1}}{\mathrm{2}}}\right)^{\mathrm{2}} +\mathrm{x}^{\mathrm{2}} +\frac{\mathrm{x}}{\mathrm{2}}+\frac{\mathrm{5}}{\mathrm{2}}…
Question Number 186821 by yaslm last updated on 10/Feb/23 Answered by CElcedricjunior last updated on 11/Feb/23 $$\bigstar\underset{{x};\boldsymbol{{y}}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{\boldsymbol{{sin}}\left(\boldsymbol{{x}}^{\mathrm{2}} +\boldsymbol{{y}}^{\mathrm{2}} \right)}{\boldsymbol{{x}}^{\mathrm{2}} +\boldsymbol{{y}}}\blacksquare\boldsymbol{{M}}{oivre} \\ $$$$\boldsymbol{{posons}}\:\boldsymbol{{x}}^{\mathrm{2}} +\boldsymbol{{y}}^{\mathrm{2}} =\boldsymbol{{A}}…
Question Number 55756 by otchereabdullai@gmail.com last updated on 03/Mar/19 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{product}\:\mathrm{of}\:\mathrm{all}\:\mathrm{the}\:\mathrm{real}\:\mathrm{values} \\ $$$$\mathrm{of}\:\:\:\mathrm{a}\:\:\mathrm{that}\:\mathrm{satisfies}\:\mathrm{the}\:\mathrm{equation} \\ $$$$\mathrm{4}\mid\mathrm{a}−\mathrm{4}\mid=\mid\mathrm{a}+\mathrm{4}\mid \\ $$ Answered by mr W last updated on 03/Mar/19 $${if}\:{a}\leqslant−\mathrm{4}:…
Question Number 186805 by pascal889 last updated on 10/Feb/23 Answered by Rasheed.Sindhi last updated on 10/Feb/23 $${r}=\frac{{a}_{\mathrm{4}} }{{a}_{\mathrm{10}} }=\frac{{a}_{\mathrm{1}} }{{a}_{\mathrm{4}} } \\ $$$${r}=\frac{{a}+\mathrm{3}{d}}{{a}+\mathrm{9}{d}}=\frac{{a}}{{a}+\mathrm{3}{d}} \\ $$$${r}−\mathrm{1}=\frac{{a}+\mathrm{3}{d}}{{a}+\mathrm{9}{d}}−\mathrm{1}=\frac{{a}}{{a}+\mathrm{3}{d}}−\mathrm{1}…
Question Number 55724 by Kunal12588 last updated on 03/Mar/19 Commented by Kunal12588 last updated on 03/Mar/19 $${this}\:{make}\:{me}\:{stop}\:{learning}\:{calculus}. \\ $$ Commented by mr W last updated…
Question Number 121256 by ZiYangLee last updated on 06/Nov/20 $$\mathrm{Prove}\:\mathrm{2sin}^{\mathrm{2}} \mathrm{3}\theta−\mathrm{2sin}^{\mathrm{2}} \theta=\mathrm{cos2}\theta−\mathrm{cos6}\theta. \\ $$$$\mathrm{By}\:\mathrm{substitusing}\:\theta=\frac{\pi}{\mathrm{10}}\:\mathrm{in}\:\mathrm{the}\:\mathrm{above}\:\mathrm{identity}, \\ $$$$\mathrm{prove}\:\mathrm{that}\:\mathrm{sin}\frac{\mathrm{3}\pi}{\mathrm{10}}−\mathrm{sin}\frac{\pi}{\mathrm{10}}=\frac{\mathrm{1}}{\mathrm{2}} \\ $$ Answered by TANMAY PANACEA last updated on…
Question Number 186790 by mathocean1 last updated on 10/Feb/23 $${Solve}\:{using}\:{Fourier}'{s}\:{series}: \\ $$$${x}^{\mathrm{2}} \left(\mathrm{1}−{x}\right){y}''−{x}\left(\mathrm{1}+{x}\right){y}'+{y}=\mathrm{0} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 121235 by ZiYangLee last updated on 06/Nov/20 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{sum}\:\mathrm{of}\:{n}\:\mathrm{terms}\:\mathrm{of}\:\mathrm{the}\:\mathrm{series} \\ $$$${S}_{{n}} =\mathrm{1}+\mathrm{22}+\mathrm{333}+\mathrm{4444}+\ldots\ldots \\ $$ Answered by Ar Brandon last updated on 06/Nov/20 $$\mathrm{S}_{\mathrm{n}} =\mathrm{1}+\mathrm{22}+\mathrm{333}+\mathrm{4444}+\centerdot\centerdot\centerdot…
Question Number 186769 by naka3546 last updated on 10/Feb/23 $$\mathrm{Given}\:\:\mathrm{function}\:\:\:{f}\::\:\mathbb{R}\:\rightarrow\:\mathbb{R}\:\:\:\mathrm{satisfy}\:\:\mathrm{that} \\ $$$$\:\:\:\:\left({f}\:\circ\:{f}\right)\left({x}\right)\:+\:{x}\:=\:\left({x}+\mathrm{1}\right)\:{f}\left({x}\right)\:. \\ $$$$\mathrm{Find}\:\:\mathrm{the}\:\:\mathrm{value}\:\:\mathrm{of}\:\:{f}\left(\mathrm{1}\right)\:. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com