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Question-120467

Question Number 120467 by help last updated on 31/Oct/20 Answered by mathmax by abdo last updated on 31/Oct/20 $$\mathrm{tan}\left(\theta+\frac{\pi}{\mathrm{3}}\right)\:=\frac{\mathrm{tan}\theta\:+\mathrm{tan}\frac{\pi}{\mathrm{3}}}{\mathrm{1}−\mathrm{tan}\theta\:\mathrm{tan}\left(\frac{\pi}{\mathrm{3}}\right)}\:=\frac{\mathrm{tan}\theta\:+\sqrt{\mathrm{3}}}{\mathrm{1}−\sqrt{\mathrm{3}}\mathrm{tan}\theta} \\ $$$$\mathrm{tan}\left(\theta+\frac{\mathrm{2}\pi}{\mathrm{3}}\right)\:=\mathrm{tan}\left(\theta+\pi−\frac{\pi}{\mathrm{3}}\right)\:=\frac{\mathrm{tan}\theta−\sqrt{\mathrm{3}}}{\mathrm{1}+\sqrt{\mathrm{3}}\mathrm{tan}\theta} \\ $$$$\mathrm{e}\:\Rightarrow\mathrm{tan}\theta\:+\frac{\mathrm{tan}\theta\:+\sqrt{\mathrm{3}}}{\mathrm{1}−\sqrt{\mathrm{3}}\mathrm{tan}\theta}\:+\frac{\mathrm{tan}\theta−\sqrt{\mathrm{3}}}{\mathrm{1}+\sqrt{\mathrm{3}}\mathrm{tant}}\:=\mathrm{3}\:\:\:\mathrm{let}\:\mathrm{tan}\theta\:=\mathrm{x}\:\mathrm{so}\:\mathrm{e}\:\Rightarrow \\ $$$$\mathrm{x}\:+\frac{\mathrm{x}+\sqrt{\mathrm{3}}}{\mathrm{1}−\sqrt{\mathrm{3}}\mathrm{x}}+\frac{\mathrm{x}−\sqrt{\mathrm{3}}}{\mathrm{1}+\sqrt{\mathrm{3}}\mathrm{x}}\:=\mathrm{3}\:\Rightarrow\mathrm{x}\:+\frac{\left(\mathrm{x}+\sqrt{\mathrm{3}}\right)\left(\mathrm{1}+\sqrt{\mathrm{3}}\mathrm{x}\right)+\left(\mathrm{x}−\sqrt{\mathrm{3}}\right)\left(\mathrm{1}−\sqrt{\mathrm{3}}\mathrm{x}\right)}{\mathrm{1}−\mathrm{3x}^{\mathrm{2}}…

sin-lnx-dx-

Question Number 120461 by Khalmohmmad last updated on 31/Oct/20 $$\int\mathrm{sin}\left(\mathrm{ln}{x}\right){dx} \\ $$ Answered by Dwaipayan Shikari last updated on 31/Oct/20 $$\int{sin}\left({logx}\right){dx} \\ $$$$=\left(\int{e}^{{t}} {sin}\left({t}\right){dt}\:\right)\rightarrow{I}\:\:\:\:\:\:\:\:{logx}={t} \\…

x-3-ln-x-4-dx-

Question Number 185951 by manxsol last updated on 30/Jan/23 $$\int{x}^{\mathrm{3}} {ln}\left({x}+\mathrm{4}\right){dx} \\ $$ Answered by SEKRET last updated on 30/Jan/23 $$\:\int\:\boldsymbol{\mathrm{x}}^{\mathrm{3}} \centerdot\boldsymbol{\mathrm{ln}}\left(\boldsymbol{\mathrm{x}}+\mathrm{4}\right)\:\boldsymbol{\mathrm{dx}}= \\ $$$$\:\:=\frac{\boldsymbol{\mathrm{x}}^{\mathrm{4}} }{\mathrm{4}}\centerdot\boldsymbol{\mathrm{ln}}\left(\boldsymbol{\mathrm{x}}+\mathrm{4}\right)\:−\:\int\:\frac{\boldsymbol{\mathrm{x}}^{\mathrm{4}}…