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Question-120194

Question Number 120194 by huotpat last updated on 30/Oct/20 Answered by MJS_new last updated on 30/Oct/20 $$\mathrm{let}\:{y}={px}\wedge{z}={qx}\:\mathrm{with}\:{p},\:{q}\:\in\mathbb{R} \\ $$$$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{{pqx}^{\mathrm{3}} }{\left({p}^{\mathrm{2}} +{q}^{\mathrm{2}} +\mathrm{1}\right){x}^{\mathrm{2}} }\:=\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{{pqx}}{{p}^{\mathrm{2}}…

C-lim-z-0-Re-z-Im-z-Re-z-Im-z-

Question Number 120195 by SOMEDAVONG last updated on 30/Oct/20 $$\mathbb{C}\:.\underset{\mathrm{z}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{\mathrm{Re}\left(\mathrm{z}\right).\mathrm{Im}\left(\mathrm{z}\right)}{\mathrm{Re}\left(\mathrm{z}\right)+\mathrm{Im}\left(\mathrm{z}\right)}\:=? \\ $$ Answered by snipers237 last updated on 30/Oct/20 $${z}_{{n}} =\frac{\mathrm{1}}{{n}_{} }−{i}\frac{\mathrm{1}}{{n}}\:\underset{\infty} {\rightarrow}\mathrm{0}\:\:\:\:\:\:{and}\:\:{s}_{{n}} =\frac{\mathrm{1}}{{n}}\underset{\infty}…

x-2013-6-7-x-

Question Number 185728 by aba last updated on 26/Jan/23 $$\left(\mathrm{x}−\mathrm{2013}\right)!=\mathrm{6}!\mathrm{7}! \\ $$$$\mathrm{x}=?? \\ $$ Answered by mr W last updated on 26/Jan/23 $$\mathrm{6}!\mathrm{7}! \\ $$$$=\mathrm{1}×\mathrm{2}×\mathrm{3}×\mathrm{4}×\mathrm{5}×\mathrm{6}×\mathrm{7}!…

Question-185708

Question Number 185708 by mokys last updated on 26/Jan/23 Answered by mr W last updated on 26/Jan/23 $${t}=\mathrm{4}\:\mathrm{log}_{\mathrm{2}} \:{x}=\frac{\mathrm{4}\:\mathrm{ln}\:{x}}{\mathrm{ln}\:\mathrm{2}} \\ $$$${dt}=\frac{\mathrm{4}}{{x}\:\mathrm{ln}\:\mathrm{2}}{dx} \\ $$$$\int_{\mathrm{1}} ^{\mathrm{8}} \frac{{f}\left(\mathrm{4}\:\mathrm{log}_{\mathrm{2}}…