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Question-185203

Question Number 185203 by KONE last updated on 18/Jan/23 Answered by aba last updated on 18/Jan/23 $$ \\ $$$$\mathrm{1}.\mathrm{P}\left(\mathrm{G}_{\mathrm{1}} \right)=\mathrm{P}\left(\mathrm{G}_{\mathrm{1}} /\mathrm{A}_{\mathrm{1}} \right)×\mathrm{P}\left(\mathrm{A}_{\mathrm{1}} \right)+\:\mathrm{P}\left(\mathrm{G}_{\mathrm{1}} /\overset{−} {\mathrm{A}}_{\mathrm{1}}…

0-1-4x-1-f-12x-2-6x-dx-

Question Number 119659 by ZiYangLee last updated on 26/Oct/20 $$\int_{\mathrm{0}} ^{\mathrm{1}} \left[\left(\mathrm{4}{x}−\mathrm{1}\right){f}\left(\mathrm{12}{x}^{\mathrm{2}} −\mathrm{6}{x}\right)\right]{dx}=? \\ $$ Answered by bemath last updated on 26/Oct/20 $${let}\:{u}\:=\:\mathrm{12}{x}^{\mathrm{2}} −\mathrm{6}{x}\:\rightarrow{du}\:=\:\mathrm{24}{x}−\mathrm{6}\:{dx} \\…

Particles-of-mass-m-1-and-m-2-m-2-gt-m-1-are-connected-by-a-light-inextensible-string-passing-over-a-smooth-fixed-pulley-initially-both-masses-hang-vertically-with-mass-m-2-at-a-height-X-ab

Question Number 119648 by aurpeyz last updated on 26/Oct/20 $${Particles}\:{of}\:{mass}\:{m}_{\mathrm{1}} \:{and}\:{m}_{\mathrm{2}} \:\left({m}_{\mathrm{2}} >{m}_{\mathrm{1}} \right) \\ $$$${are}\:{connected}\:{by}\:{a}\:{light}\:{inextensible} \\ $$$${string}\:{passing}\:{over}\:{a}\:{smooth}\:{fixed}\: \\ $$$${pulley}.\:{initially}\:{both}\:{masses}\:{hang} \\ $$$${vertically}\:{with}\:{mass}\:{m}_{\mathrm{2}\:} {at}\:{a}\:{height} \\ $$$${X}\:{above}\:{the}\:{floor}.\:{if}\:{the}\:{system}\:{is}\:…

1-x-5-x-3-1-dx-2-dy-dx-3x-2y-1-2-

Question Number 119644 by bemath last updated on 25/Oct/20 $$\:\left(\mathrm{1}\right)\:\int\:{x}^{\mathrm{5}} \:\sqrt{{x}^{\mathrm{3}} +\mathrm{1}}\:{dx}\: \\ $$$$\left(\mathrm{2}\right)\:\frac{{dy}}{{dx}}\:=\:\left(\mathrm{3}{x}−\mathrm{2}{y}+\mathrm{1}\right)^{\mathrm{2}} \\ $$ Answered by benjo_mathlover last updated on 26/Oct/20 $$\left(\mathrm{1}\right)\int\:{x}^{\mathrm{3}} \:\left({x}^{\mathrm{2}}…

Question-119647

Question Number 119647 by IE last updated on 26/Oct/20 Answered by Ar Brandon last updated on 26/Oct/20 $$\mathrm{En}\:\mathrm{coordonn}\acute {\mathrm{e}es}\:\mathrm{sph}\acute {\mathrm{e}riques}\:\mathrm{nous}\:\mathrm{avons} \\ $$$$\begin{cases}{\mathrm{x}=\mathrm{rsin}\varphi\mathrm{cos}\theta}&{\mathrm{r}\in\left[\mathrm{0},\mathrm{R}\right]}\\{\mathrm{y}=\mathrm{rsin}\varphi\mathrm{sin}\theta}&{\theta\in\left[\mathrm{0},\pi\right]}\\{\mathrm{z}=\mathrm{rcos}\varphi}&{\varphi\in\left[\mathrm{0},\alpha\right]}\end{cases} \\ $$$$\Rightarrow\Omega=\int_{\mathrm{0}} ^{\pi}…

A-particle-of-mass-m-1-lies-on-a-smooth-horizontal-table-and-its-connected-to-a-freely-hanging-particle-of-mass-m-2-by-a-light-inextensible-string-passing-over-a-smooth-fixed-pulley-situated-at-the-

Question Number 119645 by aurpeyz last updated on 26/Oct/20 $${A}\:{particle}\:{of}\:{mass}\:{m}_{\mathrm{1}} \:{lies}\:{on}\:{a}\:{smooth} \\ $$$${horizontal}\:{table}\:{and}\:{its}\:{connected}\:{to} \\ $$$${a}\:{freely}\:{hanging}\:{particle}\:{of}\:{mass}\:{m}_{\mathrm{2}} \\ $$$${by}\:{a}\:{light}\:{inextensible}\:{string}\:{passing} \\ $$$${over}\:{a}\:{smooth}\:{fixed}\:{pulley}\:{situated} \\ $$$${at}\:{the}\:{edge}\:{of}\:{the}\:{table}.\:{obtain}\:{the} \\ $$$${expression}\:{for}\:{the}\:{time}\:{taken}\:{for} \\ $$$${mass}\:{m}_{\mathrm{1}\:}…

Question-119618

Question Number 119618 by help last updated on 25/Oct/20 Answered by ebi last updated on 25/Oct/20 $${Option}\:\mathrm{1} \\ $$$${Quarryton}−{Richfield}−{Bayview}−{Quarryton} \\ $$$${Quarryton}−{Richfield}\rightarrow\mathrm{3}{ways} \\ $$$${Richfield}−{Bayview}\rightarrow\mathrm{2}{ways} \\ $$$${Bayview}−{Quarryton}\rightarrow\mathrm{1}{ways}…