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Question Number 120409 by SOMEDAVONG last updated on 31/Oct/20 $$\mathrm{I}/.\int\left(\frac{\mathrm{1}}{\mathrm{lnx}}\:−\:\frac{\mathrm{1}}{\mathrm{ln}^{\mathrm{2}} \mathrm{x}}\right)\mathrm{dx} \\ $$$$\left(\mathrm{Helpe}\:\mathrm{me}\:\mathrm{please}\right) \\ $$ Commented by soumyasaha last updated on 31/Oct/20 $$\mathrm{I}\:=\:\int\frac{\mathrm{1}}{\mathrm{lnx}}\mathrm{dx}\:−\:\int\frac{\mathrm{1}}{\mathrm{ln}^{\mathrm{2}} \mathrm{x}}\mathrm{dx} \\…
Question Number 185932 by aurpeyz last updated on 30/Jan/23 Commented by aurpeyz last updated on 30/Jan/23 $${pls}\:{help} \\ $$ Answered by mr W last updated…
Question Number 185933 by aymanadnan last updated on 30/Jan/23 Answered by qaz last updated on 30/Jan/23 $${dV}=\mathrm{2}\left({y}^{\mathrm{2}} −{x}^{\mathrm{2}} \right){d}\left({y}^{\mathrm{2}} −{x}^{\mathrm{2}} \right)=\mathrm{4}\left({y}^{\mathrm{2}} −{x}^{\mathrm{2}} \right)\left({ydy}−{xdx}\right) \\ $$$$\Rightarrow{V}_{{x}}…
Question Number 54858 by Otchere Abdullai last updated on 13/Feb/19 $$\left({Q}\mathrm{1}\right)\:{The}\:{expansion}\:\left({x}−\frac{\mathrm{1}}{\mathrm{3}{x}}\right)^{\mathrm{12}} \\ $$$$\left({i}\right)\:{find}\:{the}\:{term}\:{independent}\:{of}\:{x} \\ $$$$\left({ii}\right)\:{find}\:{the}\:{term}\:{x}^{\mathrm{4}} \\ $$$$\left({Q}\mathrm{2}\right)\:{There}\:{are}\:{some}\:{nut}\:{in}\:{a}\:{bag}.\:{when} \\ $$$$\:\mathrm{2}\:{ounces}\:{of}\:{peanut}\:{are}\:{added}\:{to}\:{the} \\ $$$${mixture},\:{the}\:{percentage}\:{of}\:{peanut}\: \\ $$$${becomes}\:\mathrm{20\%}\:.\:{Richard}\:\:{added}\:\:\mathrm{2}\: \\ $$$${ounces}\:{of}\:{cashew}\:{to}\:{the}\:{mixture}\:{and}…
Question Number 120393 by help last updated on 31/Oct/20 Commented by help last updated on 31/Oct/20 pls how to prove the identity? Commented by $@y@m last updated on 31/Oct/20 $${Please}\:{type}\:{the}\:{question}.…
Question Number 120383 by SOMEDAVONG last updated on 31/Oct/20 $$\mathrm{I}/\:.\int_{\mathrm{0}} ^{\mathrm{1}} \frac{\mathrm{lnt}\:}{\left(\mathrm{1}+\mathrm{t}\right)^{\mathrm{2}} }\mathrm{dt}\:\:=? \\ $$$$\:\left(\mathrm{Helpe}\:\mathrm{me}\:\mathrm{please}\right) \\ $$ Answered by Dwaipayan Shikari last updated on 31/Oct/20…
Question Number 120389 by help last updated on 31/Oct/20 Commented by help last updated on 31/Oct/20 $${question}\:\mathrm{2}{a} \\ $$ Commented by help last updated on…
Question Number 120365 by help last updated on 30/Oct/20 $$\mathrm{A}\:\mathrm{body}\:\mathrm{is}\:\mathrm{released}\:\mathrm{from}\:\mathrm{rest}\:\mathrm{at}\:\mathrm{the}\:\mathrm{top}\: \\ $$$$\mathrm{ofa}\:\mathrm{plane}\:\mathrm{inclined}\:\mathrm{at}\:\mathrm{30}\:\mathrm{to}\:\mathrm{the}\: \\ $$$$\mathrm{horizontaland}\:\mathrm{4}.\mathrm{0m}\:\mathrm{high}\:.\:\mathrm{If}\:\mathrm{the} \\ $$$$\mathrm{coefficiet}\:\mathrm{of}\:\mathrm{friction}\:\mathrm{between}\:\mathrm{the}\:\mathrm{body} \\ $$$$\mathrm{an}{d}\:\mathrm{plane}\:\mathrm{is}\:\mathrm{0}.\mathrm{3}.\:\mathrm{calculate}\:\mathrm{to}\:\mathrm{the}\:\mathrm{time}\:\mathrm{theb} \\ $$$$\mathrm{ody}\:\mathrm{takes}\:\mathrm{to}\:\mathrm{reach}\:\mathrm{the}\:\mathrm{bottom}\:\mathrm{of}.\:\mathrm{thea} \\ $$ Commented by Dwaipayan…
Question Number 54827 by problem solverd last updated on 12/Feb/19 $$\mathrm{logx}^{\mathrm{2}} +\mathrm{log}_{\mathrm{2}} \left(\mathrm{x}−\mathrm{6}\right)=\mathrm{3} \\ $$$$\mathrm{solve}\:\mathrm{for}\:\mathrm{x} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com