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Question Number 120295 by A8;15: last updated on 30/Oct/20 Commented by TANMAY PANACEA last updated on 30/Oct/20 Answered by Dwaipayan Shikari last updated on 30/Oct/20…
Question Number 120284 by Algoritm last updated on 30/Oct/20 Commented by Algoritm last updated on 30/Oct/20 $$\mathrm{x}=? \\ $$ Answered by TITA last updated on…
Question Number 120279 by Khalmohmmad last updated on 30/Oct/20 Commented by benjo_mathlover last updated on 30/Oct/20 $${is}\:{it}\:{same}\:{to}\:\mathrm{log}\:_{\mathrm{3}} \left(\mathrm{log}\:_{\mathrm{2}} \left(\mathrm{5}\left(\mathrm{25}\right)\right)\right)? \\ $$ Commented by Khalmohmmad last…
Question Number 185815 by naka3546 last updated on 28/Jan/23 $$\mathrm{Let}\:\:\mathrm{function}\:\:{g}\left({x}\right)\:\:=\:\frac{{a}}{{g}\left({ax}\right)}\:\:,\:\:\:{a},\:{r}\:\in\:\:\mathbb{R}^{+} \:\:{and} \\ $$$${g}\left(\mathrm{2}\right)\:\:=\:\mathrm{3}\:.\:\:\mathrm{Find}\:\mathrm{value}\:\:\mathrm{of}\:\:{g}\left(\mathrm{2016}\right)\:. \\ $$ Commented by naka3546 last updated on 28/Jan/23 $$\mathrm{I}\:\mathrm{meant}\:\:{g}\left({x}\right)\:,\:\:\mathrm{sir}. \\ $$…
Question Number 54730 by yorrick23ralph@gmail.com last updated on 09/Feb/19 $${prove}\:{lnx}\leqslant{x} \\ $$ Commented by Abdo msup. last updated on 09/Feb/19 $${first}\:{x}>\mathrm{0}\:\:{let}\:\:{f}\left({x}\right)={x}−{ln}\left({x}\right)\:\Rightarrow \\ $$$${f}^{'} \left({x}\right)=\mathrm{1}−\frac{\mathrm{1}}{{x}}\:=\frac{{x}−\mathrm{1}}{{x}}\:{and}\:{f}^{'} \left({x}\right)\geqslant\mathrm{0}\:\Leftrightarrow{x}\geqslant\mathrm{1}…
Question Number 185764 by CrispyXYZ last updated on 27/Jan/23 $$\mathrm{If}\:{f}\left({x}\right)=−\frac{{x}^{\mathrm{2}} }{\mathrm{8}}+{x}−\frac{{a}}{\mathrm{8}}−\mathrm{1}\:\mathrm{has}\:\mathrm{2}\:\mathrm{diffrent}\:\mathrm{real} \\ $$$$\mathrm{roots}\:\mathrm{in}\:\left(\sqrt{\mathrm{7}{a}},+\infty\right),\:\mathrm{find}\:\mathrm{the}\:\mathrm{range}\:\mathrm{of}\:{a}>\mathrm{0}. \\ $$ Answered by CrispyXYZ last updated on 28/Jan/23 $$\mathrm{Let}\:{g}\left({x}\right)={f}\left({x}+\sqrt{\mathrm{7}{a}}\right)\: \\ $$$$=\:−\frac{{x}^{\mathrm{2}}…
Question Number 120206 by ZiYangLee last updated on 30/Oct/20 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{remainder}\:\mathrm{when}\: \\ $$$$\mathrm{1}×\mathrm{3}×\mathrm{5}×\mathrm{7}×\ldots×\mathrm{2017}×\mathrm{2019}\:\mathrm{is}\:\mathrm{divided} \\ $$$$\mathrm{by}\:\mathrm{1000}. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 120196 by ZiYangLee last updated on 30/Oct/20 $$\mathrm{The}\:\mathrm{ratio}\:\mathrm{of}\:\mathrm{male}\:\mathrm{and}\:\mathrm{female}\:\mathrm{participants} \\ $$$$\mathrm{in}\:\mathrm{a}\:\mathrm{competition}\:\mathrm{is}\:\mathrm{3}:\mathrm{2}.\:\mathrm{Given}\:\mathrm{that}\:\mathrm{15\%}\: \\ $$$$\mathrm{of}\:\mathrm{participants}\:\mathrm{are}\:\mathrm{prize}\:\mathrm{winner},\:\mathrm{and}\:\mathrm{among} \\ $$$$\mathrm{the}\:\mathrm{prize}\:\mathrm{winner},\:\mathrm{the}\:\mathrm{ratio}\:\mathrm{of}\:\mathrm{male}\:\mathrm{to}\:\mathrm{female} \\ $$$$\mathrm{is}\:\mathrm{2}:\mathrm{1}.\:\mathrm{Find}\:\mathrm{the}\:\mathrm{ratio}\:\mathrm{of}\:\mathrm{male}\:\mathrm{and}\:\mathrm{female} \\ $$$$\mathrm{among}\:\mathrm{the}\:\mathrm{participants}\:\mathrm{that}\:\mathrm{are}\:\mathrm{not}\:\mathrm{prize} \\ $$$$\mathrm{winner}. \\ $$ Answered…
Question Number 54659 by Gulay last updated on 08/Feb/19 Commented by Gulay last updated on 08/Feb/19 $$\mathrm{sir}\:\mathrm{could}\:\mathrm{you}\:\mathrm{help}\:\mathrm{me}? \\ $$$$ \\ $$ Commented by maxmathsup by…