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Question Number 183750 by kapoorshah last updated on 29/Dec/22 Answered by mr W last updated on 30/Dec/22 $${S}_{\mathrm{1}} ={a} \\ $$$${S}_{\mathrm{6}} =\frac{{a}\left(\mathrm{1}−{q}^{\mathrm{6}} \right)}{\mathrm{1}−{q}} \\ $$$${a}+\frac{{a}\left(\mathrm{1}−{q}^{\mathrm{6}}…

Question Number 118203 by aurpeyz last updated on 15/Oct/20 Answered by MJS_new last updated on 15/Oct/20 $$\mathrm{at}\:\mathrm{first}\:\mathrm{glance}\:{x}=\mathrm{1} \\ $$ Commented by aurpeyz last updated on…

Question Number 183726 by LEKOUMA last updated on 29/Dec/22 $${Prove}\:{that}\:\underset{{k}=\mathrm{0}} {\overset{{n}−\mathrm{1}} {\sum}}\mathrm{2}^{{n}−\mathrm{1}} ={n}×\mathrm{2}^{{n}−\mathrm{1}} \: \\ $$ Commented by JDamian last updated on 29/Dec/22 seriously? Answered…

Question Number 118166 by andilizhaa last updated on 15/Oct/20 Answered by Olaf last updated on 15/Oct/20 $$\left(\mathrm{162}×\mathrm{2}+\mathrm{167}×\mathrm{7}+\mathrm{172}×\mathrm{10}+\mathrm{177}×\mathrm{8}\right. \\ $$$$\left.+\mathrm{182}×\mathrm{2}\right)\boldsymbol{\div}\mathrm{30}\:=\:\mathrm{172},\mathrm{5} \\ $$ Terms of Service Privacy…

Question Number 183693 by LEKOUMA last updated on 28/Dec/22 $$\underset{{x}\rightarrow+\infty} {\mathrm{lim}}\frac{\left(\mathrm{ln}\:{x}\right)^{{x}} }{{x}^{\mathrm{ln}\:{x}} } \\ $$ Answered by a.lgnaoui last updated on 28/Dec/22 $$\mathrm{lnx}=\mathrm{t}\:\:\:\:\:\Rightarrow\mathrm{x}=\mathrm{e}^{\mathrm{t}} \\ $$$$\mathrm{x}\rightarrow+\infty\:\:\:\:\:\:\Rightarrow{t}\rightarrow+\infty…