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Question Number 57357 by ANTARES VY last updated on 03/Apr/19 $$\mathrm{1}−\mathrm{2}\boldsymbol{\mathrm{sin}}\left(\mathrm{4}\boldsymbol{\mathrm{x}}\right)<\boldsymbol{\mathrm{cos}}^{\mathrm{2}} \left(\mathrm{4}\boldsymbol{\mathrm{x}}\right) \\ $$$$\boldsymbol{\mathrm{solve}}. \\ $$ Commented by bshahid010@gmail.com last updated on 03/Apr/19 $$\mathrm{1}−\mathrm{2sin}\left(\mathrm{4x}\right)<\mathrm{cos}^{\mathrm{2}} \left(\mathrm{4x}\right)…
Question Number 57356 by ANTARES VY last updated on 03/Apr/19 $$\boldsymbol{\mathrm{S}}=\frac{\boldsymbol{\pi\mathrm{R}}^{\mathrm{2}} }{\mathrm{360}°}×\boldsymbol{\alpha}° \\ $$$$\boldsymbol{\mathrm{prove}}. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 188417 by 073 last updated on 01/Mar/23 Commented by SEKRET last updated on 01/Mar/23 $$\:\boldsymbol{\mathrm{D}} \\ $$ Answered by SEKRET last updated on…
Question Number 188416 by 073 last updated on 01/Mar/23 Answered by manxsol last updated on 01/Mar/23 $$\Sigma=\frac{\mathrm{1}}{\mathrm{3}^{\mathrm{2}} }+\frac{\mathrm{1}}{\mathrm{3}^{\mathrm{3}} }+……. \\ $$$$\Sigma=\frac{\mathrm{1}}{\mathrm{3}}\left[\frac{\mathrm{1}}{\mathrm{3}}+\frac{\mathrm{1}}{\mathrm{3}^{\mathrm{2}} }…….\right] \\ $$$$\mathrm{3}\Sigma=\frac{\mathrm{1}}{\mathrm{3}}+\Sigma \\…
Question Number 188418 by 073 last updated on 01/Mar/23 Answered by manxsol last updated on 01/Mar/23 $${T}_{{n}} ={i}^{\mathrm{4}{n}−\mathrm{3}} \\ $$$${T}_{{n}} =\frac{{i}^{\mathrm{4}{n}} }{{i}^{\mathrm{3}} }=\frac{\left({i}^{\mathrm{2}} \right)^{\mathrm{2}{n}} }{−{i}}=\frac{\mathrm{1}}{−{i}}×\frac{{i}}{{i}}=…
Question Number 57345 by behi83417@gmail.com last updated on 02/Apr/19 $$\left.\mathrm{1}\right)\boldsymbol{\mathrm{if}}:\:\:\:\:\boldsymbol{\mathrm{sinx}}+\boldsymbol{\mathrm{tgx}}=\mathrm{1},\boldsymbol{\mathrm{then}}:\:\:\boldsymbol{\mathrm{sin}}^{\mathrm{4}} \boldsymbol{\mathrm{x}}+\boldsymbol{\mathrm{tg}}^{\mathrm{4}} \boldsymbol{\mathrm{x}}=? \\ $$$$\left.\mathrm{2}\right)\boldsymbol{\mathrm{if}}:\:\:\:\:\boldsymbol{\mathrm{sinx}}+\boldsymbol{\mathrm{tgx}}=\mathrm{2},\boldsymbol{\mathrm{then}}:\:\:\boldsymbol{\mathrm{sin}}\mathrm{4}\boldsymbol{\mathrm{x}}+\boldsymbol{\mathrm{tg}}\mathrm{4}\boldsymbol{\mathrm{x}}=? \\ $$$$\mathrm{3}.\boldsymbol{\mathrm{if}}:\:\:\:\:\boldsymbol{\mathrm{sinx}}+\boldsymbol{\mathrm{tgx}}=\mathrm{3},\boldsymbol{\mathrm{then}}:\:\:\frac{\boldsymbol{\mathrm{sin}}\mathrm{4}\boldsymbol{\mathrm{x}}}{\boldsymbol{\mathrm{sin}}^{\mathrm{4}} \boldsymbol{\mathrm{x}}}+\frac{\boldsymbol{\mathrm{tg}}\mathrm{4}\boldsymbol{\mathrm{x}}}{\boldsymbol{\mathrm{tg}}^{\mathrm{4}} \boldsymbol{\mathrm{x}}}=? \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated…
Question Number 57332 by problem solverd last updated on 02/Apr/19 $$\mathrm{find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{k}\:\mathrm{such}\:\mathrm{that} \\ $$$${k}\left({x}^{\mathrm{2}} +{y}^{\mathrm{2}} \right)+\left({y}−\mathrm{2}{x}+\mathrm{1}\right)\left({y}+\mathrm{2}{x}+\mathrm{3}\right)=\mathrm{0} \\ $$$$\mathrm{is}\:\mathrm{a}\:\mathrm{circle}\:\mathrm{hence}\:\mathrm{obtain}\: \\ $$$$\mathrm{the}\:\mathrm{centre}\:\mathrm{and}\:\mathrm{radius}\:\mathrm{of}\:\mathrm{the} \\ $$$$\mathrm{resulting}\:\mathrm{circle}. \\ $$ Commented by…
Question Number 57329 by naka3546 last updated on 02/Apr/19 $$\underset{−\mathrm{1}} {\int}\overset{\mathrm{2}} {\:}\:\mid{x}\mid\:\lfloor{x}\rfloor\:{dx}\:\:=\:\:\:? \\ $$ Commented by turbo msup by abdo last updated on 02/Apr/19 $${I}=\int_{−\mathrm{1}}…
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