Question Number 203625 by professorleiciano last updated on 23/Jan/24 Answered by esmaeil last updated on 23/Jan/24 $$\mathrm{1}+\frac{\left({sin}^{\mathrm{2}} {x}+{cos}^{\mathrm{2}} {x}\right)^{\mathrm{2}} −\mathrm{2}{sin}^{\mathrm{2}} {xcos}^{\mathrm{2}} {x}}{{sin}^{\mathrm{2}} {xcos}^{\mathrm{2}} {x}}=\mathrm{3}\rightarrow \\…
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Question Number 203576 by sonukgindia last updated on 22/Jan/24 Answered by mr W last updated on 22/Jan/24 Commented by mr W last updated on 22/Jan/24…
Question Number 203573 by sonukgindia last updated on 22/Jan/24 Answered by esmaeil last updated on 22/Jan/24 $$\int−{e}^{{cosx}} \left(\mathrm{1}−{cos}^{\mathrm{2}} {x}−{cosx}\right){dx} \\ $$$$\int−{e}^{{cosx}} \left({sin}^{\mathrm{2}} {x}−{cosx}\right){dx}= \\ $$$$\int−{e}^{{cosx}}…
Question Number 203544 by laxmanb2111 last updated on 21/Jan/24 $$\int_{\mathrm{0}} ^{\mathrm{1}_{} } \frac{{dx}}{\left(\mathrm{1}−{x}^{\mathrm{6}} \right)^{\frac{\mathrm{1}}{\mathrm{6}}} }\:=\frac{\pi}{\mathrm{3}} \\ $$ Answered by DwaipayanShikari last updated on 23/Jan/24 $$\int_{\mathrm{0}}…
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Question Number 203454 by Denis_volosenko352 last updated on 19/Jan/24 $$\sqrt{\mathrm{5}}+\sqrt{\mathrm{5}}={x} \\ $$$${x}×\mathrm{5}\pi=?\:{find}\:{all}\:{answers}\:{until}\:\mathrm{24}.\mathrm{01}.\mathrm{2024} \\ $$ Answered by MathematicalUser2357 last updated on 20/Jan/24 $${x}=\sqrt{\mathrm{5}}+\sqrt{\mathrm{5}}=\mathrm{2}\sqrt{\mathrm{5}} \\ $$$${x}×\mathrm{5}\pi=\mathrm{2}\sqrt{\mathrm{5}}×\mathrm{5}\pi=\mathrm{10}\pi\sqrt{\mathrm{5}} \\…
Question Number 203468 by MrGHK last updated on 19/Jan/24 $$\:\boldsymbol{\mathrm{let}}\:\boldsymbol{\mathrm{A}}\:{B}\:{and}\:{C}\:\:\boldsymbol{\mathrm{be}}\:\boldsymbol{\mathrm{sets}}\:\boldsymbol{\mathrm{prove}}\:\boldsymbol{\mathrm{using}}\:\boldsymbol{\mathrm{venn}}\:\boldsymbol{\mathrm{diagrams}}\:\boldsymbol{\mathrm{and}}\:\boldsymbol{\mathrm{by}}\:\boldsymbol{\mathrm{first}}\:\boldsymbol{\mathrm{principle}} \\ $$$$\left.\:\boldsymbol{\mathrm{a}}\right)\boldsymbol{\mathrm{A}}×\left(\boldsymbol{\mathrm{B}}\cup\boldsymbol{\mathrm{C}}\right)=\left(\boldsymbol{\mathrm{A}}×\boldsymbol{\mathrm{B}}\right)\cup\left(\boldsymbol{\mathrm{A}}×\boldsymbol{\mathrm{C}}\right) \\ $$$$\left.\boldsymbol{\mathrm{b}}\right)\mathrm{A}×\left(\boldsymbol{\mathrm{B}}\cap\boldsymbol{\mathrm{C}}\right)=\left(\boldsymbol{\mathrm{A}}×\boldsymbol{\mathrm{B}}\right)\cap\left(\boldsymbol{\mathrm{A}}×\boldsymbol{\mathrm{C}}\right) \\ $$$$\left.\boldsymbol{\mathrm{c}}\right)\left(\boldsymbol{\mathrm{A}}−\boldsymbol{\mathrm{B}}\right)\cap\left(\boldsymbol{{A}}\cap\boldsymbol{\mathrm{B}}\right)\cap\left(\boldsymbol{\mathrm{B}}−\boldsymbol{\mathrm{A}}\right)=\left\{\right\} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com