Question Number 51847 by hassentimol last updated on 31/Dec/18 Commented by hassentimol last updated on 31/Dec/18 $$\mathrm{Can}\:\mathrm{you}\:\mathrm{help}\:\mathrm{me}\:\mathrm{to}\:\mathrm{prove}\:\mathrm{the}\:\mathrm{above}\:\mathrm{equation}\:? \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 182909 by SANOGO last updated on 16/Dec/22 $$\left.{x}\epsilon\right]−\mathrm{1},\mathrm{1}\left[\:{calcul}:\right. \\ $$$$\underset{{n}=\mathrm{1}} {\overset{+{oo}} {\sum}}\frac{{x}^{{n}} }{\left(\mathrm{1}−{x}^{{n}} \right)\left(\mathrm{1}−{x}^{{n}+\mathrm{1}} \right)} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 182905 by balliu last updated on 16/Dec/22 $$\mathrm{33} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
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Question Number 182906 by balliu last updated on 16/Dec/22 $$\mathrm{2}^{−\mathrm{1}} =\frac{\mathrm{1}}{\mathrm{2}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 182896 by sciencestudent last updated on 16/Dec/22 Commented by JDamian last updated on 16/Dec/22 bigger than what? Answered by mr W last updated on 17/Dec/22…
Question Number 51823 by hassentimol last updated on 30/Dec/18 $$ \\ $$$$\:\:\:\:\:\:\boldsymbol{\mathrm{Give}}\:\boldsymbol{\mathrm{a}}\:\boldsymbol{\mathrm{proof}}\:\boldsymbol{\mathrm{for}}\:: \\ $$$$ \\ $$$$\:\:\:\underset{{n}=\mathrm{1}} {\overset{{k}} {\sum}}\:\left(\underset{{n}'=\mathrm{0}} {\overset{{m}} {\prod}}\left(\:{n}+\mathrm{n}'\right)\right)\:\:=\:\:\frac{\underset{{x}=\mathrm{0}} {\overset{{m}+\mathrm{1}} {\prod}}\left({k}+{x}\right)}{{m}+\mathrm{2}}\: \\ $$$$ \\…
Question Number 182895 by sciencestudent last updated on 16/Dec/22 Answered by Rasheed.Sindhi last updated on 16/Dec/22 $${x}:\:{total}\:{number}\:{of}\:{employees} \\ $$$$\frac{\mathrm{5}}{\mathrm{8}}\:\mathrm{of}\:{x}\:=\mathrm{240} \\ $$$$\frac{\mathrm{5}}{\mathrm{8}}×{x}=\mathrm{240} \\ $$$${x}=\cancel{\overset{\mathrm{48}} {\mathrm{240}}}×\frac{\mathrm{8}}{\cancel{\mathrm{5}}}=\mathrm{384} \\…
Question Number 51805 by azizullah last updated on 30/Dec/18 Commented by tanmay.chaudhury50@gmail.com last updated on 30/Dec/18 Commented by maxmathsup by imad last updated on 30/Dec/18…
Question Number 51798 by Gulay last updated on 30/Dec/18 Commented by Gulay last updated on 30/Dec/18 $$\mathrm{ENM}=\mathrm{60}\:\:\:\:\:\:\mathrm{Find}\:\:\:\:\:\:\:\:\mathrm{PEM} \\ $$ Commented by Gulay last updated on…