Question Number 182582 by sciencestudent last updated on 11/Dec/22 Answered by Acem last updated on 11/Dec/22 $${a}\bullet{Mathematical}\:{method}:\:;\:{Distance}=\:{v}.{t} \\ $$$$\:\mathrm{80}=\:\mathrm{2}×\mathrm{2}×\mathrm{4}×\mathrm{5}\:;\:{diff}.\:{of}\:{time}=\:\mathrm{1}\:{hr}\:{we}\:{take}\:\mathrm{4},\:\mathrm{5} \\ $$$$\:\mathrm{80}=\:\mathrm{4}×\mathrm{20}=\:\mathrm{5}×\mathrm{16} \\ $$$$\:{daily}:\:{v}=\:\mathrm{16}\:{km}/{hr} \\ $$$$\:{this}\:{day}:\:{v}=\:\mathrm{20}\:{km}/{hr}…
Question Number 182571 by Khalmohmmad last updated on 11/Dec/22 Answered by aleks041103 last updated on 11/Dec/22 $$\sqrt[{\mathrm{3}}]{{x}^{\mathrm{2}} .\sqrt[{\mathrm{3}}]{{x}^{\mathrm{2}} .\sqrt[{\mathrm{3}}]{{x}^{\mathrm{2}} ….}}}={y}\Rightarrow{y}=\sqrt[{\mathrm{3}}]{{x}^{\mathrm{2}} {y}} \\ $$$$\Rightarrow{y}^{\mathrm{3}} ={x}^{\mathrm{2}} {y}\Rightarrow{y}=\pm{x},\:{but}\:{obv}.\:{y}>\mathrm{0}\Rightarrow{y}=\mid{x}\mid…
Question Number 182529 by sciencestudent last updated on 10/Dec/22 $$\underset{\mathrm{0}} {\overset{\mathrm{1}} {\int}}\frac{{x}−\mathrm{1}}{\left({x}+\mathrm{1}\right){lnx}}{dx}=? \\ $$ Answered by Ar Brandon last updated on 10/Dec/22 $$\Omega\left(\alpha\right)=\int_{\mathrm{0}} ^{\mathrm{1}} \frac{{x}^{\alpha}…
Question Number 116997 by mathdave last updated on 08/Oct/20 Answered by Olaf last updated on 09/Oct/20 $$\frac{\mathrm{1}}{\left(\mathrm{2}{n}+\mathrm{1}\right)\left(\mathrm{2}{n}+\mathrm{2}+{k}\right)}\:=\:\frac{\mathrm{1}}{{k}+\mathrm{1}}\left[\frac{\mathrm{1}}{\mathrm{2}{n}+\mathrm{1}}−\frac{\mathrm{1}}{\mathrm{2}{n}+\mathrm{2}+{k}}\right] \\ $$$$\mathrm{S}\:=\:\underset{{k}=\mathrm{0}} {\overset{\infty} {\sum}}\frac{\left(−\mathrm{1}\right)^{{k}} }{{k}+\mathrm{1}}\underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}\left[\frac{\mathrm{C}_{\mathrm{2}{n}} ^{{n}}…
Question Number 182528 by sciencestudent last updated on 10/Dec/22 $${li}\underset{{x}\rightarrow\mathrm{0}} {{m}}\left({x}!!\right)^{\frac{\mathrm{1}}{{x}}} =? \\ $$ Commented by sciencestudent last updated on 11/Dec/22 $$? \\ $$ Terms…
Question Number 116987 by ZiYangLee last updated on 08/Oct/20 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{largest}\:\mathrm{integer}\:\mathrm{smaller}\:\mathrm{than} \\ $$$$\left(\mathrm{7}+\mathrm{4}\sqrt{\mathrm{3}}\right)^{\mathrm{3}} . \\ $$ Answered by 1549442205PVT last updated on 08/Oct/20 $$\mathrm{a}=\left(\mathrm{7}+\mathrm{4}\sqrt{\mathrm{3}}\right)^{\mathrm{3}} =\mathrm{343}+\mathrm{588}\sqrt{\mathrm{3}}+\mathrm{1008}+\mathrm{64}\sqrt{\mathrm{3}} \\…
Question Number 182514 by Best1 last updated on 11/Dec/22 $$\mathrm{1}.\:{prove}\:{that}\:{the}\:{equaion}\:{of}\:{parabola} \\ $$$$\:\:{whose}\:{axis}\:{of}\:{symmetry}\:{is}\:{parallel}\: \\ $$$${to}\:{y}\:{axisis}\:{given}\:{as}\:\left({x}−{h}\right)^{\mathrm{2}} =\underset{−} {+}\:\mathrm{4}{p}\left({y}−{k}\right) \\ $$$$\mathrm{2}.\:\:\:{if}\:{Dis}\:{a}\:{perpendicular}\:{distance}\: \\ $$$$\:\:\:{of}\:{the}\:{point}\:{p}\left({r},{t}\right){from}\:{the}\:{line} \\ $$$$\:\:\:\:\left({L}\right):\frac{{x}}{{r}}+\frac{{y}}{{t}}=\mathrm{1}\:\:{then}\:{find}\:{the} \\ $$$$\:\:\:\:\:\:\:{value}\:{of}\:{D} \\…
Question Number 116975 by ZiYangLee last updated on 08/Oct/20 $$\mathrm{Prove}\:\frac{\mathrm{cos}\left({A}−{B}\right)}{\mathrm{sin}\left({A}+{B}\right)}=\frac{\mathrm{1}+\mathrm{tan}\:{A}\mathrm{tan}\:{B}}{\mathrm{tan}\:{A}\mathrm{tan}\:{B}} \\ $$ Commented by Dwaipayan Shikari last updated on 08/Oct/20 $$\frac{{cos}\left({A}−{B}\right)}{{sin}\left({A}+{B}\right)}=\frac{{cosAcosB}+{sinAsinB}}{{sinAcosB}+{cosAsinB}}=\frac{\mathrm{1}+{tanAtanB}}{{tanA}+{tanB}} \\ $$ Terms of…
Question Number 182507 by Matica last updated on 10/Dec/22 $$\:{Can}\:{a}\:{mathematician}\:{solve}\:{or}\:{know}\:{everything}? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 182506 by Matica last updated on 10/Dec/22 $$\:\:{Calculate}\:{S}\:=\:\mathrm{1}×\mathrm{1}!\:+\:\mathrm{2}×\mathrm{2}!\:+\:\mathrm{3}×\mathrm{3}!\:+\:…+\:{n}×{n}! \\ $$$$\:\:\: \\ $$ Answered by mr W last updated on 10/Dec/22 $${n}×{n}!=\left({n}+\mathrm{1}\right)!−{n}! \\ $$$$\Rightarrow{S}=\left({n}+\mathrm{1}\right)!−\mathrm{1}…