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Question-116884

Question Number 116884 by zakirullah last updated on 07/Oct/20 Answered by Olaf last updated on 07/Oct/20 $$\mathrm{In}\:\mathrm{linear}\:\mathrm{algebra},\:\mathrm{a}\:\mathrm{matrix}\:\mathrm{is}\:\mathrm{said}\:\mathrm{to}\:\mathrm{be} \\ $$$$\mathrm{scaled}\:\mathrm{in}\:\mathrm{rows}\:\mathrm{if}\:\mathrm{the}\:\mathrm{number}\:\mathrm{of}\:\mathrm{zeros} \\ $$$$\mathrm{preceding}\:\mathrm{the}\:\mathrm{first}\:\mathrm{non}−\mathrm{zero}\:\mathrm{value}\:\mathrm{of} \\ $$$$\mathrm{a}\:\mathrm{row}\:\mathrm{increases}\:\mathrm{row}\:\mathrm{by}\:\mathrm{row}\:\mathrm{until} \\ $$$$\mathrm{ultimately}\:\mathrm{all}\:\mathrm{that}\:\mathrm{remains}\:\mathrm{are}\:\mathrm{zero}\::…

Find-radius-and-center-of-S-S-x-y-z-4-y-2-yz-z-2-4-y-z-

Question Number 182369 by mathocean1 last updated on 08/Dec/22 $${Find}\:{radius}\:{and}\:{center}\:{of}\:\left({S}\right): \\ $$$$\left({S}\right):\begin{cases}{{x}+{y}+{z}=\mathrm{4}}\\{{y}^{\mathrm{2}} +{yz}+{z}^{\mathrm{2}} =\mathrm{4}\left({y}+{z}\right)}\end{cases} \\ $$ Commented by a.lgnaoui last updated on 09/Dec/22 $$\mathrm{y}+\mathrm{z}=\mathrm{4}−\mathrm{x}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\left(\mathrm{1}\right) \\…