Question Number 182279 by meetbhavsar25 last updated on 06/Dec/22 $$\int_{\mathrm{0}} ^{\infty} \frac{{x}^{\mathrm{10}} \left(\mathrm{1}+{x}^{\mathrm{5}} \right)}{\left(\mathrm{1}+{x}\right)^{\mathrm{27}} }{dx}\:=\:? \\ $$ Answered by Frix last updated on 07/Dec/22 $$\underset{\mathrm{0}}…
Question Number 182271 by SANOGO last updated on 06/Dec/22 Answered by SEKRET last updated on 06/Dec/22 $$\:\:\:\:\frac{−\boldsymbol{\pi}}{\mathrm{2}}\centerdot\boldsymbol{\mathrm{ln}}\left(\mathrm{2}\right) \\ $$ Answered by SEKRET last updated on…
Question Number 51174 by malwaan last updated on 24/Dec/18 $$\mathrm{please} \\ $$$$\mathrm{can}\:\mathrm{you}\:\mathrm{make}\:\mathrm{arabic}\:\mathrm{app} \\ $$$$\mathrm{like}\:\mathrm{this}\:? \\ $$$$\mathrm{or}\:\mathrm{add}\:\mathrm{arabic}\:\mathrm{language} \\ $$$$\mathrm{to}\:\mathrm{this}\:\mathrm{great}\:\mathrm{app}\:? \\ $$ Commented by Tinku Tara last…
Question Number 51153 by Gulay last updated on 24/Dec/18 Commented by Gulay last updated on 24/Dec/18 $$\mathrm{Sir}\:\mathrm{could}\:\mathrm{you}\:\mathrm{help}\:\mathrm{me}? \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on…
Question Number 182219 by SANOGO last updated on 05/Dec/22 Answered by Ar Brandon last updated on 06/Dec/22 $$\mathrm{Sea}\:{I}\left(\alpha\right)=\int_{\mathrm{0}} ^{\mathrm{1}} \frac{{t}^{\alpha} −\mathrm{1}}{\mathrm{ln}{t}}{dt} \\ $$$$\mathrm{Derivando}\:\mathrm{con}\:\mathrm{respecto}\:\mathrm{a}\:\alpha\:\mathrm{obtenemos} \\ $$$${I}\:'\left(\alpha\right)=\int_{\mathrm{0}}…
Question Number 116674 by ZiYangLee last updated on 05/Oct/20 Commented by ZiYangLee last updated on 05/Oct/20 $${A}_{\mathrm{1}} {B}_{\mathrm{1}} {C}_{\mathrm{1}} \:\mathrm{is}\:\mathrm{a}\:\mathrm{regular}\:\mathrm{triangle}. \\ $$$${A}_{\mathrm{2}} {B}_{\mathrm{2}} {C}_{\mathrm{2}} \mathrm{are}\:\mathrm{points}\:\mathrm{on}\:{A}_{\mathrm{1}}…
Question Number 116666 by zakirullah last updated on 05/Oct/20 Answered by $@y@m last updated on 05/Oct/20 $$\sqrt{}\left(\mathrm{794}−\mathrm{169}\right)=\mathrm{25} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 116658 by zakirullah last updated on 05/Oct/20 Commented by Rasheed.Sindhi last updated on 08/Oct/20 $$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathbb{A}\mathrm{n}\mathbb{O}\mathrm{ther}\:\mathbb{W}\mathrm{ay}\:\curvearrowleft\underset{\downarrow} {\uparrow}\curvearrowright \\ $$$$\mathrm{12}=\mathrm{2}^{\mathrm{2}} .\mathrm{3} \\ $$$${The}\:{smallest}\:{perfect}\:{square}\: \\ $$$${divisible}\:{by}\:\mathrm{12}\::\:\mathrm{2}^{\mathrm{2}}…
Question Number 116641 by nguyenthanh last updated on 05/Oct/20 Answered by TANMAY PANACEA last updated on 05/Oct/20 $${A}={B}={C}=\mathrm{60}^{{o}} \\ $$$${sin}\mathrm{30}^{{o}} ×{sin}\mathrm{30}^{{o}} ×{sin}\mathrm{30}^{{o}} =\frac{\mathrm{1}}{\mathrm{8}} \\ $$$${cos}\mathrm{60}^{{o}}…
Question Number 116616 by nguyenthanh last updated on 05/Oct/20 Commented by Dwaipayan Shikari last updated on 05/Oct/20 $$\mathrm{No}\:\mathrm{unique}\:\mathrm{solution}.\mathrm{You}\:\mathrm{have}\:{to}\:\mathrm{specify}\:\mathrm{Relation}\:\mathrm{Between}\:\mathrm{A}\:,\mathrm{B},\mathrm{C} \\ $$ Terms of Service Privacy Policy…