Question Number 182791 by Matica last updated on 14/Dec/22 $$\:{We}\:{have}\:\mathrm{0}<{x}<{a}\:{and}\:{m},{n}\:\in\mathbb{N}. \\ $$$$\:{Prove}\:{x}^{{m}} \left({a}−{x}\right)^{{n}} \leqslant\:\frac{{m}^{{m}} {n}^{{n}} }{\left({m}+{n}\right)^{{m}+{n}} }\centerdot{a}^{{m}+{n}} \\ $$ Answered by mahdipoor last updated on…
Question Number 182786 by SANOGO last updated on 14/Dec/22 $${existant}\:{and}\:{value}\:{m}\geqslant\mathrm{1}\:{of} \\ $$$${S}_{{m}} =\underset{{n}=\mathrm{1}\:\overset{} {\:}} {\overset{+{oo}} {\sum}}\frac{\mathrm{1}}{{n}\left({n}+\mathrm{1}\right)…\left({n}+{m}\right)}\: \\ $$ Answered by dre23 last updated on 15/Dec/22…
Question Number 117243 by A8;15: last updated on 10/Oct/20 Commented by A8;15: last updated on 10/Oct/20 please help sir Answered by Olaf last updated on 10/Oct/20 $$…
Question Number 182771 by liuxinnan last updated on 14/Dec/22 $$\int\:_{\mathrm{0}} ^{{r}} \:\frac{\mathrm{1}}{{R}^{\mathrm{2}} −{r}^{\mathrm{2}} }{dr}=? \\ $$ Commented by Frix last updated on 14/Dec/22 $$\mathrm{Error}:\:\mathrm{dependent}\:\mathrm{borders}\:\mathrm{are}\:\mathrm{not}\:\mathrm{allowed}. \\…
Question Number 117215 by Tinku Tara last updated on 10/Oct/20 $$\mathrm{v2}.\mathrm{220}:\:\mathrm{Forum}\:\mathrm{viewing}\:\mathrm{improvement} \\ $$$$\bullet\:\mathrm{After}\:\mathrm{update}\:\mathrm{you}\:\mathrm{will}\:\mathrm{see}\:\mathrm{options} \\ $$$$\mathrm{to}\:\mathrm{zoom}\:\mathrm{out}\:\mathrm{of}\:\mathrm{post}\:\mathrm{with}\:\mathrm{longer}\:\mathrm{lines} \\ $$$$\mathrm{to}\:\mathrm{view}\:\mathrm{whole}\:\mathrm{posts}\:\mathrm{without}\:\mathrm{scrolling}. \\ $$$$\mathrm{Similar}\:\mathrm{option}\:\mathrm{are}\:\mathrm{added}\:\mathrm{while} \\ $$$$\mathrm{editing}\:\mathrm{in}\:'\mathrm{Cursor\&Page}'\:\mathrm{menu} \\ $$ Commented by…
Question Number 182726 by SANOGO last updated on 13/Dec/22 $$\int_{\mathrm{0}} ^{\mathrm{1}} \:{t}\sqrt{\frac{\mathrm{1}−{t}}{\mathrm{1}+{t}}}{dt}=? \\ $$ Commented by CElcedricjunior last updated on 13/Dec/22 $$\int_{\mathrm{0}} ^{\mathrm{1}} \boldsymbol{{t}}\sqrt{\frac{\mathrm{1}−\boldsymbol{{t}}}{\mathrm{1}+\boldsymbol{{t}}}}\boldsymbol{{dt}}=\boldsymbol{{k}} \\…
Question Number 117184 by Eric002 last updated on 10/Oct/20 $${let}\:{I}\:{be}\:{an}\:{interval}.{prove}\:{that} \\ $$$${c}^{\left(\infty\right)} \left({I}\right)=\underset{{n}=\mathrm{1}} {\overset{\infty} {\cap}}{c}^{{n}} \left({I}\right) \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 182716 by sciencestudent last updated on 13/Dec/22 Answered by ARUNG_Brandon_MBU last updated on 13/Dec/22 $$\mathrm{In}\:\mathrm{a}\:\mathrm{space}\:\mathrm{of}\:\mathrm{20}\:\mathrm{seconds}\:\mathrm{the}\:\mathrm{school}\:\mathrm{bus}\:\mathrm{covered}\:\mathrm{a}\:\mathrm{distance} \\ $$$$\mathrm{of}\:{d}\:\mathrm{and}\:\mathrm{the}\:\mathrm{ambulance}\:\mathrm{covered}\:\mathrm{a}\:\mathrm{distance}\:\mathrm{of}\:\mathrm{40}+{d}+\mathrm{60}=\mathrm{100}+{d}. \\ $$$$ \\ $$$$\mathrm{Meanwhile}\:\mathrm{speed}\:\mathrm{of}\:\mathrm{ambulance}=\frac{\mathrm{100}+{d}}{\mathrm{20}}=\mathrm{30}×\frac{\mathrm{5}}{\mathrm{18}}\:\left(\mathrm{in}\:{ms}^{−\mathrm{1}} \right) \\…
Question Number 182715 by islamo last updated on 13/Dec/22 Commented by BaliramKumar last updated on 13/Dec/22 $${i}\:{think}\:{tan}^{−\mathrm{1}} \left(−{x}\right)\:=\:−\:{tan}^{−\mathrm{1}} \left({x}\right) \\ $$ Answered by Frix last…
Question Number 182676 by yaslm last updated on 12/Dec/22 Answered by Acem last updated on 12/Dec/22 $${If}\:{we}\:{consider}\:{that}\:{the}\:{sequare}\:{isn}'{t}\:{a}\:{special} \\ $$$$\:{case}\:{of}\:{the}\:{rectangle},\:{then}\:{the}\:{required}\:{rectangles} \\ $$$$\left.\:{are}:\:\underset{\ell} {\underbrace{\right]\mathrm{0},\:\mathrm{1}\left[\:\cup\:\right]\mathrm{1},\:+\infty\left[}}\:×\:\underset{{w}} {\underbrace{\mathrm{1}}}\:\:\:\:\Leftrightarrow\:\:\:\:\underset{\ell} {\underbrace{\mathbb{R}^{+\bigstar,\:+\mathrm{1}} }}\:×\:\underset{{w}}…