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1-0-ln-ln-1-x-2-dx-

Question Number 116271 by mohammad17 last updated on 02/Oct/20 $$\int_{−\mathrm{1}} ^{\:\mathrm{0}} \left[{ln}\left({ln}\left(\mathrm{1}+{x}\right)\right)\right]^{\mathrm{2}} {dx} \\ $$ Answered by mnjuly1970 last updated on 03/Oct/20 $${answer}\::\gamma^{\mathrm{2}} −\mathrm{1}−\:\frac{\mathrm{5}\pi^{\mathrm{2}} }{\mathrm{6}}…

Question-50732

Question Number 50732 by hassentimol last updated on 19/Dec/18 Answered by Rasheed.Sindhi last updated on 19/Dec/18 $$\left(\mathrm{10}{a}+{b}\right)×{c}=\mathrm{10}{d}+{e} \\ $$$$\left(\mathrm{10}{d}+{e}\right)+\left(\mathrm{10}{f}+{g}\right)=\mathrm{10}{h}+{i} \\ $$$$\bullet\:{c}\:{can}'{t}\:{be}\:\mathrm{1}\:{because}\:{in}\:{that}\:{case} \\ $$$${a}={d}\:\&\:{b}={e} \\ $$$$\bullet\mathrm{12}\leqslant\mathrm{10}{a}+{b}\leqslant\mathrm{49}\:\left({b}/{c}\:\:{c}\:{is}\:{at}\:{least}\:\mathrm{2}\right)…

Question-181785

Question Number 181785 by yaslm last updated on 30/Nov/22 Commented by Frix last updated on 30/Nov/22 $$\mathrm{You}\:\mathrm{seriously}\:\mathrm{ask}\:\mathrm{this}\:\mathrm{question}\:\mathrm{after}\:\mathrm{asking} \\ $$$$\mathrm{question}\:\mathrm{180614}? \\ $$ Commented by MJS_new last…

3-4x-11-3-10-x-2-3-x-2-2-6x-x-2-

Question Number 181779 by DAVONG last updated on 30/Nov/22 $$\mathrm{3}^{\mathrm{4x}−\mathrm{11}} +\mathrm{3}^{\mathrm{10}−\mathrm{x}^{\mathrm{2}} } +\mathrm{3}^{\left(\mathrm{x}−\mathrm{2}\right)^{\mathrm{2}} } =\mathrm{6x}−\mathrm{x}^{\mathrm{2}} \\ $$ Answered by manxsol last updated on 01/Dec/22 $$\mathrm{6}{x}−{x}^{\mathrm{2}}…

if-3x-1-7-x-

Question Number 50685 by majidedalt last updated on 18/Dec/18 $$\boldsymbol{\mathrm{if}}\::\:\mathrm{3}\boldsymbol{\mathrm{x}}+\mathrm{1}=\mathrm{7} \\ $$$$\boldsymbol{\mathrm{x}}=? \\ $$ Answered by OTCHRRE ABDULLAI last updated on 18/Dec/18 $$\mathrm{3}{x}=\mathrm{7}−\mathrm{1} \\ $$$$\mathrm{3}{x}=\mathrm{6}…

Question-181741

Question Number 181741 by yaslm last updated on 29/Nov/22 Answered by cortano1 last updated on 30/Nov/22 $$\:\Rightarrow\mathrm{11}\:\mathrm{sin}\:\theta\:+\:\mathrm{60}\:\mathrm{cos}\:\theta\:=\:\mathrm{61}\:;\:\theta\:\in\left(\mathrm{0},\frac{\pi}{\mathrm{2}}\right) \\ $$$$\Rightarrow\mathrm{11}\:\mathrm{tan}\:\theta\:+\mathrm{60}\:=\:\mathrm{61}\:\mathrm{sec}\:\theta\: \\ $$$$\Rightarrow\left(\mathrm{11}\:\mathrm{tan}\:\theta+\mathrm{60}\right)^{\mathrm{2}} =\:\mathrm{3721}\:\mathrm{sec}\:^{\mathrm{2}} \theta \\ $$$$\Rightarrow\mathrm{121}\:\mathrm{tan}\:^{\mathrm{2}}…