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Question Number 181733 by SANOGO last updated on 30/Nov/22 $$\left.\mathrm{1}\right){calcul}\:{n}−+{oo}:\:{sn}=\underset{{k}={n}+\mathrm{1}} {\overset{\mathrm{2}{n}} {\sum}}\:\frac{\mathrm{1}}{{k}} \\ $$$$\left.\mathrm{2}\right){find}:\:\underset{{k}=\mathrm{1}} {\overset{+{oo}} {\sum}}\:\frac{\left(−\mathrm{1}\right)^{{k}+\mathrm{1}} }{{k}} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 116184 by ZiYangLee last updated on 01/Oct/20 $$\mathrm{How}\:\mathrm{many}\:\mathrm{6}-\mathrm{digits}\:\mathrm{positive}\:\mathrm{integers}\:\mathrm{which}\:\mathrm{are} \\ $$$$\mathrm{formed}\:\mathrm{by}\:\mathrm{the}\:\mathrm{digits}\:\mathrm{1}\:\mathrm{to}\:\mathrm{9}\:\mathrm{are}\:\mathrm{such}\:\mathrm{that}\:\mathrm{each} \\ $$$$\mathrm{of}\:\mathrm{the}\:\mathrm{digits}\:\mathrm{in}\:\mathrm{the}\:\mathrm{number}\:\mathrm{appears}\:\mathrm{at}\:\mathrm{least} \\ $$$$\mathrm{twice}?\:\left[\mathrm{For}\:\mathrm{instance}:\:\mathrm{121233},\mathrm{122221},\mathrm{777777}\:\mathrm{and}\:\mathrm{etc}.\right] \\ $$ Answered by mr W last updated on…
Question Number 116149 by A8;15: last updated on 01/Oct/20 Commented by A8;15: last updated on 01/Oct/20 please help Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 181676 by yaslm last updated on 28/Nov/22 Answered by floor(10²Eta[1]) last updated on 28/Nov/22 $$\mathrm{def}\:\mathrm{of}\:\mathrm{square}\:\mathrm{root}: \\ $$$$\sqrt{\mathrm{b}}=\mathrm{a}\Leftrightarrow\mathrm{b}=\mathrm{a}^{\mathrm{2}} \wedge\mathrm{a}\geqslant\mathrm{0} \\ $$$$ \\ $$$$\sqrt{\mathrm{x}}−\mathrm{7}=\sqrt{\mathrm{x}−\mathrm{7}}\Leftrightarrow\mathrm{x}−\mathrm{7}=\left(\sqrt{\mathrm{x}}−\mathrm{7}\right)^{\mathrm{2}} \wedge\sqrt{\mathrm{x}}\geqslant\mathrm{7}…
Question Number 116114 by Khalmohmmad last updated on 01/Oct/20 Answered by Dwaipayan Shikari last updated on 01/Oct/20 $$\mathrm{tan}^{−\mathrm{1}} \left(\mathrm{3}+\mathrm{2}\sqrt{\mathrm{2}}\right)−\mathrm{tan}^{−\mathrm{1}} \left(\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}}\right) \\ $$$$\mathrm{tan}^{−\mathrm{1}} \frac{\mathrm{3}+\mathrm{2}\sqrt{\mathrm{2}}−\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}}}{\mathrm{1}+\left(\mathrm{3}+\mathrm{2}\sqrt{\mathrm{2}}\right)\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}}}=\mathrm{tan}^{−\mathrm{1}} \left(\frac{\mathrm{3}+\frac{\mathrm{3}}{\:\sqrt{\mathrm{2}}}}{\mathrm{1}+\frac{\mathrm{3}}{\:\sqrt{\mathrm{2}}}+\mathrm{2}}\right)=\mathrm{tan}^{−\mathrm{1}} \left(\mathrm{1}\right)=\frac{\pi}{\mathrm{4}}…
Question Number 50560 by Gulay last updated on 17/Dec/18 $$\mathrm{2}\frac{\mathrm{1}}{\mathrm{3}}\mathrm{x}−\mathrm{4y}\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{x}=\mathrm{3}\:\:\:\:\:\:\mathrm{y}=−\mathrm{1} \\ $$$$\mathrm{help}\:\mathrm{md}\:\mathrm{plz}\:\mathrm{sir} \\ $$ Answered by ajfour last updated on 17/Dec/18 $$\frac{\mathrm{7}{x}}{\mathrm{3}}−\mathrm{4}{y}\:=\:\frac{\mathrm{7}×\mathrm{3}}{\mathrm{3}}−\mathrm{4}\left(−\mathrm{1}\right)\:=\:\mathrm{7}+\mathrm{4}\:=\:\mathrm{11}\:. \\ $$ Commented…
Question Number 50558 by Gulay last updated on 17/Dec/18 $$\mathrm{thanks}\:\mathrm{sir} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 116090 by oustmuchiya@gmail.com last updated on 30/Sep/20 $${what}\:{is}\:\mathrm{3}\frac{\mathrm{7}}{\mathrm{8}}{hrs}? \\ $$ Answered by 1549442205PVT last updated on 01/Oct/20 $$\mathrm{I}\:\mathrm{think}\:\mathrm{that}\:\mathrm{it}\:\mathrm{is}\:\mathrm{3}\:\mathrm{hours}\:\mathrm{and} \\ $$$$\mathrm{52minutes}\:\mathrm{and}\:\mathrm{30}\:\mathrm{second} \\ $$ Terms…
Question Number 50553 by mondodotto@gmail.com last updated on 17/Dec/18 $$\boldsymbol{\mathrm{find}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{area}}\:\boldsymbol{\mathrm{of}}\:\boldsymbol{\mathrm{triangle}}\:\boldsymbol{\mathrm{given}} \\ $$$$\boldsymbol{\mathrm{P}}\left(\boldsymbol{{x}}_{\mathrm{1}} ,\boldsymbol{{y}}_{\mathrm{1}} \right)\:\boldsymbol{\mathrm{Q}}\left(\boldsymbol{{x}}_{\mathrm{2}} ,\boldsymbol{{y}}_{\mathrm{2}} \right)\:\boldsymbol{\mathrm{and}}\:\boldsymbol{\mathrm{R}}\left(\boldsymbol{{x}}_{\mathrm{3}} ,\boldsymbol{{y}}_{\mathrm{3}} \right) \\ $$ Commented by tanmay.chaudhury50@gmail.com last updated…