Question Number 186853 by liuxinnan last updated on 11/Feb/23 $${lim}\left({k}\rightarrow\infty\right)\underset{{i}=\mathrm{1}} {\overset{{k}} {\sum}}\frac{\mathrm{1}}{\:\sqrt{{ki}}}=? \\ $$ Answered by Ar Brandon last updated on 11/Feb/23 $$\mathscr{L}=\underset{{k}\rightarrow\infty} {\mathrm{lim}}\underset{{i}=\mathrm{1}} {\overset{{k}}…
Question Number 186858 by aba last updated on 11/Feb/23 $${Discuss}\:{according}\:{to}\:{the}\:{value}\:{of}\:{the}\:{parametre} \\ $$$$\alpha\in\mathbb{R}\:{the}\:{convergence}\:{of}\:{the}\:{improper}\:{integral} \\ $$$$\int_{\mathrm{0}} ^{+\infty} {x}^{\alpha} {ln}\left({x}+{e}^{\alpha{x}} \right){dx} \\ $$ Terms of Service Privacy Policy…
Question Number 186854 by liuxinnan last updated on 11/Feb/23 $$\int_{\mathrm{0}} ^{\:{R}} \frac{{Rcosx}}{{l}−{Rcosx}}{dx}=? \\ $$ Answered by Ar Brandon last updated on 11/Feb/23 $${I}=\int_{\mathrm{0}} ^{{R}} \frac{{R}\mathrm{cos}{x}}{{l}−{R}\mathrm{cos}{x}}{dx}=\int_{\mathrm{0}}…
Question Number 186849 by Beginner last updated on 11/Feb/23 Commented by Beginner last updated on 11/Feb/23 $${i}\:{am}\:{getting}\:\mathrm{82}.\mathrm{4\%}\:{here}\:{and}\:{it}\:{is}\:{wrong}.\:{Can}\:{someone}\:{please}\:{check} \\ $$ Terms of Service Privacy Policy Contact:…
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Question Number 121301 by mathdave last updated on 06/Nov/20 Answered by JDamian last updated on 07/Nov/20 $$\left.\mathrm{1}\right)\:\mathrm{328}.\mathrm{3125}\:\:\mathrm{N}/\mathrm{m} \\ $$$$\left.\mathrm{2}\right)\:\:\mathrm{19}.\mathrm{5}\:\:\:\mathrm{m}/\mathrm{s} \\ $$$$\left.\mathrm{3}\right)\:\:\mathrm{656}.\mathrm{625}\:\mathrm{J} \\ $$ Commented by…
Question Number 121293 by abdullahquwatan last updated on 06/Nov/20 $$\mathrm{give}\:\mathrm{me}\:\mathrm{difficult}\:\mathrm{problems}\:\mathrm{exponent}\: \\ $$ Commented by liberty last updated on 06/Nov/20 $$\mathrm{3}^{\mathrm{2x}+\mathrm{1}} \:−\mathrm{4}.\mathrm{3}^{\mathrm{x}} \:=\:\left(\sqrt{−\mathrm{x}^{\mathrm{2}} −\frac{\mathrm{x}}{\mathrm{2}}+\frac{\mathrm{1}}{\mathrm{2}}}\right)^{\mathrm{2}} +\mathrm{x}^{\mathrm{2}} +\frac{\mathrm{x}}{\mathrm{2}}+\frac{\mathrm{5}}{\mathrm{2}}…
Question Number 186821 by yaslm last updated on 10/Feb/23 Answered by CElcedricjunior last updated on 11/Feb/23 $$\bigstar\underset{{x};\boldsymbol{{y}}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{\boldsymbol{{sin}}\left(\boldsymbol{{x}}^{\mathrm{2}} +\boldsymbol{{y}}^{\mathrm{2}} \right)}{\boldsymbol{{x}}^{\mathrm{2}} +\boldsymbol{{y}}}\blacksquare\boldsymbol{{M}}{oivre} \\ $$$$\boldsymbol{{posons}}\:\boldsymbol{{x}}^{\mathrm{2}} +\boldsymbol{{y}}^{\mathrm{2}} =\boldsymbol{{A}}…
Question Number 55756 by otchereabdullai@gmail.com last updated on 03/Mar/19 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{product}\:\mathrm{of}\:\mathrm{all}\:\mathrm{the}\:\mathrm{real}\:\mathrm{values} \\ $$$$\mathrm{of}\:\:\:\mathrm{a}\:\:\mathrm{that}\:\mathrm{satisfies}\:\mathrm{the}\:\mathrm{equation} \\ $$$$\mathrm{4}\mid\mathrm{a}−\mathrm{4}\mid=\mid\mathrm{a}+\mathrm{4}\mid \\ $$ Answered by mr W last updated on 03/Mar/19 $${if}\:{a}\leqslant−\mathrm{4}:…
Question Number 186805 by pascal889 last updated on 10/Feb/23 Answered by Rasheed.Sindhi last updated on 10/Feb/23 $${r}=\frac{{a}_{\mathrm{4}} }{{a}_{\mathrm{10}} }=\frac{{a}_{\mathrm{1}} }{{a}_{\mathrm{4}} } \\ $$$${r}=\frac{{a}+\mathrm{3}{d}}{{a}+\mathrm{9}{d}}=\frac{{a}}{{a}+\mathrm{3}{d}} \\ $$$${r}−\mathrm{1}=\frac{{a}+\mathrm{3}{d}}{{a}+\mathrm{9}{d}}−\mathrm{1}=\frac{{a}}{{a}+\mathrm{3}{d}}−\mathrm{1}…