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13-14-4-Remaining-

Question Number 115932 by Khalmohmmad last updated on 29/Sep/20 $$\mathrm{13}^{\mathrm{14}} \boldsymbol{\div}\mathrm{4} \\ $$$$\mathrm{Remaining}? \\ $$ Answered by JDamian last updated on 29/Sep/20 $$\mathrm{13}^{\mathrm{14}} {mod}\:\mathrm{4}\:=\:\left(\mathrm{13}\:{mod}\:\mathrm{4}\right)^{\mathrm{14}} =…

3-5-2x-1-7-2-4x-1-19-x-

Question Number 181466 by SEKRET last updated on 25/Nov/22 $$\:\mathrm{3}\centerdot\mathrm{5}^{\mathrm{2}\boldsymbol{\mathrm{x}}+\mathrm{1}} \:−\:\mathrm{7}\centerdot\mathrm{2}^{\mathrm{4}\boldsymbol{\mathrm{x}}+\mathrm{1}} \:=\:\mathrm{19} \\ $$$$ \\ $$$$\:\:\: \\ $$$$\:\:\:\:\:\:\:\boldsymbol{\mathrm{x}}=\:? \\ $$$$ \\ $$$$ \\ $$ Answered…

2-u-t-2-4-2-u-x-2-u-t-0-sin-x-u-t-t-0-x-

Question Number 181435 by SEKRET last updated on 25/Nov/22 $$\:\:\:\frac{\boldsymbol{\delta}^{\mathrm{2}} \boldsymbol{\mathrm{u}}}{\boldsymbol{\delta\mathrm{t}}^{\mathrm{2}} }\:=\:\mathrm{4}\:\frac{\boldsymbol{\delta}^{\mathrm{2}} \boldsymbol{\mathrm{u}}}{\boldsymbol{\delta\mathrm{x}}^{\mathrm{2}} }\:\:\:;\:\:\boldsymbol{\mathrm{u}}\mid_{\boldsymbol{\mathrm{t}}=\mathrm{0}} =\boldsymbol{\mathrm{sin}}\left(\boldsymbol{\mathrm{x}}\right)\:\:\:;\:\:\:\frac{\boldsymbol{\delta\mathrm{u}}}{\boldsymbol{\delta\mathrm{t}}}\mid_{\boldsymbol{\mathrm{t}}=\mathrm{0}} =\boldsymbol{\mathrm{x}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com

Question-115892

Question Number 115892 by mohammad17 last updated on 29/Sep/20 Answered by Dwaipayan Shikari last updated on 29/Sep/20 $$\int_{\mathrm{0}} ^{\mathrm{4}} \mathrm{xlogxdx} \\ $$$$\left[\frac{\mathrm{x}^{\mathrm{2}} }{\mathrm{2}}\mathrm{logx}\right]_{\mathrm{0}} ^{\mathrm{4}} −\left[\frac{\mathrm{x}^{\mathrm{2}}…

2x-3y-4z-1-min-1-x-1-y-1-z-

Question Number 115888 by Fikret last updated on 29/Sep/20 $$\mathrm{2}{x}+\mathrm{3}{y}+\mathrm{4}{z}=\mathrm{1}\:\:\Rightarrow{min}\left(\frac{\mathrm{1}}{{x}}+\frac{\mathrm{1}}{{y}}+\frac{\mathrm{1}}{{z}}\right) \\ $$ Commented by mr W last updated on 29/Sep/20 $${let}\:\mathrm{3}{y}+\mathrm{4}{z}\rightarrow\mathrm{1} \\ $$$$\Rightarrow\mathrm{2}{x}+\mathrm{1}\rightarrow\mathrm{1} \\ $$$$\Rightarrow{x}\rightarrow\mathrm{0}…

Question-115882

Question Number 115882 by Khalmohmmad last updated on 29/Sep/20 Answered by PRITHWISH SEN 2 last updated on 29/Sep/20 $$\mathrm{sgn}\left(\mathrm{x}+\mathrm{1}\right)=\mathrm{1}\:\:\mathrm{when}\:\mathrm{x}>−\mathrm{1} \\ $$$$\mathrm{sgn}\left(\mathrm{x}+\mathrm{1}\right)=\mathrm{0}\:\:\mathrm{when}\:\mathrm{x}+\mathrm{1}=\mathrm{0} \\ $$$$\mathrm{sgn}\left(\mathrm{x}+\mathrm{1}\right)=−\mathrm{1}\:\mathrm{when}\:\mathrm{x}<−\mathrm{1} \\ $$$$\because\:\mathrm{denominator}\:\neq\mathrm{0}\:\therefore\:\mathrm{sgn}\left(\mathrm{x}+\mathrm{1}\right)\neq\:\mathrm{1}…

Prove-that-f-x-ax-2-bx-c-has-no-real-roots-if-and-only-if-a-f-b-2a-gt-0-

Question Number 115876 by ZiYangLee last updated on 29/Sep/20 $$\mathrm{Prove}\:\mathrm{that}\:{f}\left({x}\right)={ax}^{\mathrm{2}} +{bx}+{c}\:\mathrm{has}\: \\ $$$$\mathrm{no}\:\mathrm{real}\:\mathrm{roots}\:\mathrm{if}\:\mathrm{and}\:\mathrm{only}\:\mathrm{if}\:{a}\centerdot\left[{f}\left(−\frac{{b}}{\mathrm{2}{a}}\right)\right]>\mathrm{0} \\ $$ Answered by Henri Boucatchou last updated on 29/Sep/20 $$\:\:\:\bullet\:{a}>\mathrm{0},\:\:{f}\left({x}\right)\:\:{has}\:\:{no}\:\:{real}\:\:{roots}\:\:{iif}\:\:\:{b}^{\mathrm{2}} −\mathrm{4}{ac}<\mathrm{0}…