Question Number 50125 by ggny last updated on 14/Dec/18 $$\mathrm{help}\:\mathrm{me}\:\mathrm{plz}\:\mathrm{sir} \\ $$ Commented by afachri last updated on 14/Dec/18 $$\mathrm{sorry}\:\mathrm{sir}.\:\mathrm{where}'\mathrm{s}\:\mathrm{P}\:\mathrm{and}\:\mathrm{where}\:\mathrm{is}\:\mathrm{D}.\:\mathrm{Both}\:\mathrm{of} \\ $$$$\mathrm{them}\:\mathrm{look}\:\mathrm{alike}. \\ $$ Commented…
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Question Number 115646 by Khalmohmmad last updated on 27/Sep/20 Commented by Dwaipayan Shikari last updated on 27/Sep/20 $$\mathrm{5}\left(\sqrt{\sqrt{\mathrm{3}}−\sqrt{\mathrm{2}}}\right) \\ $$ Commented by Khalmohmmad last updated…
Question Number 115653 by mohammad17 last updated on 27/Sep/20 Commented by mohammad17 last updated on 27/Sep/20 $${help}\:{me}\:{sir} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 115645 by ZiYangLee last updated on 27/Sep/20 Commented by Dwaipayan Shikari last updated on 27/Sep/20 $$\frac{\left(\mathrm{n}+\mathrm{1}\right)\mathrm{p}+\left(\mathrm{n}−\mathrm{1}\right)\mathrm{q}}{\left(\mathrm{n}−\mathrm{1}\right)\mathrm{p}+\left(\mathrm{n}+\mathrm{1}\right)\mathrm{q}}=\mathrm{C} \\ $$$$\frac{\mathrm{2np}+\mathrm{2nq}}{\left(\mathrm{n}+\mathrm{1}\right)\mathrm{p}−\left(\mathrm{n}−\mathrm{1}\right)\mathrm{p}+\left(\mathrm{n}−\mathrm{1}\right)\mathrm{q}−\left(\mathrm{n}+\mathrm{1}\right)\mathrm{q}}=\frac{\mathrm{C}+\mathrm{1}}{\mathrm{C}−\mathrm{1}} \\ $$$$\mathrm{2n}.\frac{\mathrm{p}+\mathrm{q}}{\mathrm{p}−\mathrm{q}}=\frac{\mathrm{C}+\mathrm{1}}{\mathrm{C}−\mathrm{1}} \\ $$$$\mathrm{2n}\frac{\frac{\mathrm{p}}{\mathrm{q}}+\mathrm{1}}{\frac{\mathrm{p}}{\mathrm{q}}−\mathrm{1}}=\frac{\left(\frac{\mathrm{p}}{\mathrm{q}}\right)^{\mathrm{k}} +\mathrm{1}}{\left(\frac{\mathrm{p}}{\mathrm{q}}\right)^{\mathrm{k}}…
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Question Number 115627 by mohammad17 last updated on 27/Sep/20 Commented by prakash jain last updated on 27/Sep/20 $$\mathrm{P}\left({A}\right)+{P}\left({B}\right)+{P}\left({C}\right)=\mathrm{1} \\ $$$${P}\left({C}\right)={x} \\ $$$$\mathrm{4}{x}+\mathrm{2}{x}+{x}=\mathrm{1}\Rightarrow{x}=\frac{\mathrm{1}}{\mathrm{7}} \\ $$$${P}\left({B}\right)=\mathrm{2}{x}=\mathrm{2}/\mathrm{7} \\…
Question Number 115629 by mohammad17 last updated on 27/Sep/20 Commented by mohammad17 last updated on 27/Sep/20 $${pleas}\:{sir}\:{help}\:{me} \\ $$ Commented by mohammad17 last updated on…
Question Number 115625 by mohammad17 last updated on 27/Sep/20 Commented by mohammad17 last updated on 27/Sep/20 $${help}\:{me}\:{sir} \\ $$ Terms of Service Privacy Policy Contact:…