Question Number 180919 by anne1344 last updated on 19/Nov/22 Answered by Socracious last updated on 19/Nov/22 $$\:\:\:\:\:\:\:\:\:\mathrm{V}_{\mathrm{r}} \:=\sqrt{\left(\mathrm{4ms}^{−\mathrm{1}} \right)^{\mathrm{2}} +\left(\mathrm{7}.\mathrm{0ms}^{−\mathrm{1}} \right)^{\mathrm{2}} } \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\sqrt{\left(\mathrm{16}\right)+\left(\mathrm{49}\right)}\:\frac{\mathrm{m}}{\mathrm{s}} \\…
Question Number 180917 by anne1344 last updated on 19/Nov/22 Answered by mr W last updated on 19/Nov/22 $$\left.{c}\right) \\ $$$${h}_{{max}} =\frac{\left({v}\:\mathrm{sin}\:\theta\right)^{\mathrm{2}} }{\mathrm{2}{g}}=\frac{\left(\mathrm{15}×\mathrm{sin}\:\mathrm{20}°\right)^{\mathrm{2}} }{\mathrm{2}×\mathrm{9}.\mathrm{81}}=\mathrm{1}.\mathrm{34}{m} \\ $$$$\left.{d}\right)…
Question Number 115380 by mathdave last updated on 25/Sep/20 $${if}\: \\ $$$${a}^{\mathrm{2}} +\mathrm{2}{ab}+\mathrm{3}{b}^{\mathrm{2}} =\mathrm{1},{prove}\:{that}\: \\ $$$$\left({a}+\mathrm{3}{b}\right)^{\mathrm{3}} \frac{{d}^{\mathrm{2}} {b}}{{da}^{\mathrm{2}} }+\mathrm{2}\left({a}^{\mathrm{2}} +\mathrm{2}{ab}+\mathrm{3}{b}^{\mathrm{2}} \right)=\mathrm{0} \\ $$ Answered by…
Question Number 115368 by mathdave last updated on 25/Sep/20 $${an}\:{open}\:{rectanqular}\:{container}\:{is}\:{to} \\ $$$${have}\:{a}\:{volume}\:{of}\:\mathrm{62}.\mathrm{5}{cm}^{\mathrm{3}} .{find}\:{the}\:{least} \\ $$$${possible}\:{surface}\:{area}\:{of}\:{the}\:{material} \\ $$$${required} \\ $$ Answered by 1549442205PVT last updated on…
Question Number 115363 by mathdave last updated on 25/Sep/20 $${evaluate} \\ $$$$\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{3}}} \frac{\mathrm{1}}{\mathrm{sin}^{\mathrm{2}} {x}+\mathrm{cos}^{\mathrm{2}} {x}}{dx} \\ $$ Answered by Dwaipayan Shikari last updated on…
Question Number 180874 by liuxinnan last updated on 18/Nov/22 Commented by liuxinnan last updated on 18/Nov/22 Commented by liuxinnan last updated on 18/Nov/22 Answered by…
Question Number 180871 by Junior01 last updated on 18/Nov/22 Commented by Junior01 last updated on 18/Nov/22 $${please}\:{help} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 49798 by ggny last updated on 10/Dec/18 $$\mathrm{help}\:\mathrm{me}\:\mathrm{sir}\:\mathrm{Plzzz} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 49796 by ggny last updated on 10/Dec/18 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 49790 by ggny last updated on 10/Dec/18 $$\mathrm{thank}\:\mathrm{you}\:\mathrm{very}\:\mathrm{much}\:\mathrm{Sir} \\ $$ Commented by afachri last updated on 10/Dec/18 $$\mathrm{ur}\:\mathrm{wellcome}.\:\mathrm{By}\:\mathrm{the}\:\mathrm{way}\:\mathrm{please}\:\mathrm{put} \\ $$$$\mathrm{comment}\:\mathrm{in}\:\mathrm{comment}\:\mathrm{option},\:\mathrm{not}\:\mathrm{is}\:\mathrm{question} \\ $$$$\left.\mathrm{post},\:\mathrm{Sir}\::\right) \\…