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Given-that-N-1-2-3-500-is-the-product-of-the-positive-integers-from-1-to-500-If-N-is-divisible-by-6-k-find-the-largest-possible-value-of-k-

Question Number 115294 by ZiYangLee last updated on 24/Sep/20 $$\mathrm{Given}\:\mathrm{that}\:{N}=\mathrm{1}×\mathrm{2}×\mathrm{3}×…×\mathrm{500}\:\mathrm{is}\:\mathrm{the} \\ $$$$\mathrm{product}\:\mathrm{of}\:\mathrm{the}\:\mathrm{positive}\:\mathrm{integers}\:\mathrm{from}\:\mathrm{1}\:\mathrm{to}\:\mathrm{500}. \\ $$$$ \\ $$$$\mathrm{If}\:{N}\:\mathrm{is}\:\mathrm{divisible}\:\mathrm{by}\:\mathrm{6}^{{k}} ,\:\mathrm{find}\:\mathrm{the}\:\mathrm{largest}\:\mathrm{possible} \\ $$$$\mathrm{value}\:\mathrm{of}\:{k}. \\ $$ Answered by Olaf last…

which-is-not-range-of-f-x-2x-1-x-2-1-2-2-3-3-10-4-2-3-

Question Number 180827 by sciencestudent last updated on 17/Nov/22 $${which}\:{is}\:{not}\:{range}\:{of}\:{f}\left({x}\right)=\frac{\mathrm{2}{x}+\mathrm{1}}{{x}−\mathrm{2}}? \\ $$$$\left.\mathrm{1}\left.\right)\left.\:\left.\mathrm{2}\:\:\:\:\:\:\:\:\mathrm{2}\right)\:\mathrm{3}\:\:\:\:\:\:\:\:\:\mathrm{3}\right)\mathrm{10}\:\:\:\:\:\:\:\mathrm{4}\right)\:\frac{\mathrm{2}}{\mathrm{3}} \\ $$ Commented by kaivan.ahmadi last updated on 17/Nov/22 $${we}\:{know}\:{that}\:{R}_{{f}} ={D}_{{f}^{−\mathrm{1}} } \\…

If-mr-Fosu-sells-the-car-after-covering-a-mileage-of-128km-find-the-i-value-of-the-car-if-the-rate-of-depreciation-is-0-03-per-km-ii-the-range-of-values-for-which-Mr-Fosu-could-sell-the-car-so

Question Number 115250 by otchereabdullai@gmail.com last updated on 24/Sep/20 $$\mathrm{If}\:\mathrm{mr}\:\mathrm{Fosu}\:\mathrm{sells}\:\mathrm{the}\:\mathrm{car}\:\mathrm{after}\:\mathrm{covering}\: \\ $$$$\mathrm{a}\:\mathrm{mileage}\:\mathrm{of}\:\mathrm{128km}.\:\mathrm{find}\:\mathrm{the}\: \\ $$$$\mathrm{i}.\:\mathrm{value}\:\mathrm{of}\:\mathrm{the}\:\mathrm{car}\:\mathrm{if}\:\mathrm{the}\:\mathrm{rate}\:\mathrm{of}\: \\ $$$$\mathrm{depreciation}\:\mathrm{is}\:\$\:\mathrm{0}.\mathrm{03}\:\mathrm{per}\:\mathrm{km} \\ $$$$\mathrm{ii}.\:\mathrm{the}\:\mathrm{range}\:\mathrm{of}\:\mathrm{values}\:\mathrm{for}\:\mathrm{which}\:\mathrm{Mr} \\ $$$$\mathrm{Fosu}\:\mathrm{could}\:\mathrm{sell}\:\mathrm{the}\:\mathrm{car}\:\mathrm{so}\:\mathrm{that}\:\mathrm{he}\:\mathrm{does} \\ $$$$\mathrm{not}\:\mathrm{lose}\:\mathrm{more}\:\mathrm{than}\:\$,\mathrm{2000}\:\mathrm{or}\:\mathrm{gain}\:\mathrm{more}\:\mathrm{tban}\: \\ $$$$\$\mathrm{3},\mathrm{000}\:\mathrm{on}\:\mathrm{the}\:\mathrm{depreciated}\:\mathrm{value}. \\…

Question-115224

Question Number 115224 by mohammad17 last updated on 24/Sep/20 Answered by Dwaipayan Shikari last updated on 24/Sep/20 $$\mathrm{S}=\mathrm{1}−\frac{\mathrm{1}}{\mathrm{3}}+\frac{\mathrm{1}}{\mathrm{9}}−\frac{\mathrm{1}}{\mathrm{27}}+….=\frac{\mathrm{1}}{\mathrm{1}+\frac{\mathrm{1}}{\mathrm{3}}}=\frac{\mathrm{3}}{\mathrm{4}} \\ $$$$\mathrm{S}_{\mathrm{n}} =\underset{\mathrm{n}=\mathrm{0}} {\overset{\infty} {\sum}}\left(−\mathrm{1}\right)^{\mathrm{n}+\mathrm{2}} .\frac{\mathrm{1}}{\mathrm{3}^{\mathrm{n}} }…