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Given-that-the-sequence-a-n-is-defined-as-a-1-2-and-a-n-1-a-n-2n-1-for-all-n-1-Find-the-last-two-digits-of-a-100-

Question Number 115133 by ZiYangLee last updated on 23/Sep/20 $$\mathrm{Given}\:\mathrm{that}\:\mathrm{the}\:\mathrm{sequence}\:\left\{{a}_{{n}} \right\}\:\mathrm{is}\:\mathrm{defined} \\ $$$$\mathrm{as}\:{a}_{\mathrm{1}} =\mathrm{2},\:\mathrm{and}\:{a}_{{n}+\mathrm{1}} ={a}_{{n}} +\left(\mathrm{2}{n}−\mathrm{1}\right)\:\mathrm{for}\:\mathrm{all}\:{n}\geqslant\mathrm{1}. \\ $$$$\mathrm{Find}\:\mathrm{the}\:\mathrm{last}\:\mathrm{two}\:\mathrm{digits}\:\mathrm{of}\:{a}_{\mathrm{100}} . \\ $$ Answered by Olaf last…

there-are-40-people-teachers-students-and-workers-in-a-school-and-there-are-40-apples-on-the-table-one-teacher-can-eat-4-apples-and-one-student-can-eat-2-apples-4-workers-can-eat-one-apple

Question Number 180648 by lazyboy last updated on 15/Nov/22 $${there}\:{are}\:\mathrm{40}\:{people} \\ $$$$\:\left({teachers}\:{students}\:{and}\:{workers}\right) \\ $$$$\:{in}\:{a}\:{school}.{and}\:{there}\:{are}\:\mathrm{40}\:{apples} \\ $$$$\:{on}\:{the}\:{table}.{one}\:{teacher}\:{can}\:{eat} \\ $$$$\:\mathrm{4}\:{apples}.{and}\:{one}\:{student}\:{can}\:{eat} \\ $$$$\:\:\mathrm{2}\:{apples}.\:\mathrm{4}\:{workers}\:{can}\:{eat}\:{one}\: \\ $$$$\:\:{apple}.{find}\:{the}\:{numbers}\:{of}\:{teacher} \\ $$$$\:\:\:{students}\:\:{and}\:{workers} \\…

Question-115095

Question Number 115095 by aurpeyz last updated on 23/Sep/20 Answered by Dwaipayan Shikari last updated on 23/Sep/20 $${Term}\:{nth}=\mathrm{6}{n}−\mathrm{1} \\ $$$$\underset{{n}=\mathrm{1}} {\overset{{n}} {\sum}}\mathrm{6}{n}−\mathrm{1}=\mathrm{3}{n}\left({n}+\mathrm{1}\right)−{n} \\ $$$$\mathrm{3}{n}\left({n}+\mathrm{1}\right)−{n}>\mathrm{1000} \\…

Question-49553

Question Number 49553 by ggny last updated on 07/Dec/18 Commented by mr W last updated on 07/Dec/18 $$\angle\mathrm{1}=\angle\mathrm{3} \\ $$$$\angle\mathrm{1}+\angle\mathrm{3}=\mathrm{90}° \\ $$$$\Rightarrow\mathrm{2}\angle\mathrm{1}=\mathrm{90}° \\ $$$$\Rightarrow\angle\mathrm{1}=\mathrm{45}° \\…

Question-115085

Question Number 115085 by Khalmohmmad last updated on 23/Sep/20 Commented by mohammad17 last updated on 23/Sep/20 $${x}={vy}\Rightarrow\frac{{dx}}{{dy}}={v}+{y}\frac{{dv}}{{dy}} \\ $$$$ \\ $$$${when}:\frac{{dx}}{{dy}}=\frac{\mathrm{2}{e}^{\frac{{x}}{{y}}} −\mathrm{2}{e}^{\frac{{x}}{{y}}} \frac{{x}}{{y}}}{−\mathrm{1}−\mathrm{2}{e}^{\frac{{x}}{{y}}} } \\…