Menu Close

Category: None

Question-114212

Question Number 114212 by mathdave last updated on 17/Sep/20 Answered by mr W last updated on 18/Sep/20 $$\mathrm{1}+\mathrm{2}+\mathrm{3}+\mathrm{4}+\mathrm{5}=\mathrm{15}\:× \\ $$$$\mathrm{0}+\mathrm{2}+\mathrm{3}+\mathrm{4}+\mathrm{5}=\mathrm{14}\:\checkmark \\ $$$$\mathrm{0}+\mathrm{1}+\mathrm{3}+\mathrm{4}+\mathrm{5}=\mathrm{13}\:× \\ $$$$\mathrm{0}+\mathrm{1}+\mathrm{2}+\mathrm{4}+\mathrm{5}=\mathrm{12}\:\checkmark \\…

pls-suggest-to-me-a-meaningful-nickname-in-physics-

Question Number 114202 by aurpeyz last updated on 17/Sep/20 $${pls}\:{suggest}\:{to}\:{me}\:{a}\:{meaningful}\:{nickname}\:{in} \\ $$$${physics}. \\ $$ Commented by Dwaipayan Shikari last updated on 17/Sep/20 $${Physics}\:{is}\:{nature}'{s}\:{law}\:.\:{It}\:{cannot}\:{be}\:{created}\:{or}\:{destroyed}.\:{In}\:\mathrm{15}{th}\:{century}\:{modern}\:{Thinkers}\: \\ $$$${started}\:{to}\:{think}\:{something}\:{about}\:{realistic}\:{concepts}.\:{They}\:{refrained}\:{social}\:{backwardness}\:{and}\:…

For-a-positive-integer-k-we-write-1-x-1-2x-1-3x-1-kx-a-0-a-1-x-a-2-x-2-a-k-x-k-Let-N-a-0-a-1-a-2-a-k-if-N-is-divisible-by-2019-find-the-smallest-possible-value-of-k-

Question Number 114192 by ZiYangLee last updated on 17/Sep/20 $$\mathrm{For}\:\mathrm{a}\:\mathrm{positive}\:\mathrm{integer}\:{k},\:\mathrm{we}\:\mathrm{write}\: \\ $$$$\left(\mathrm{1}+{x}\right)\left(\mathrm{1}+\mathrm{2}{x}\right)\left(\mathrm{1}+\mathrm{3}{x}\right)…\left(\mathrm{1}+{kx}\right)={a}_{\mathrm{0}} +{a}_{\mathrm{1}} {x}+{a}_{\mathrm{2}} {x}^{\mathrm{2}} +…{a}_{{k}} {x}^{{k}} \\ $$$$\mathrm{Let}\:{N}={a}_{\mathrm{0}} +{a}_{\mathrm{1}} +{a}_{\mathrm{2}} +…{a}_{{k}} \:, \\ $$$$\mathrm{if}\:{N}\:\mathrm{is}\:\mathrm{divisible}\:\mathrm{by}\:\mathrm{2019},\:\mathrm{find}\:\mathrm{the}\:…

Question-114185

Question Number 114185 by mohammad17 last updated on 17/Sep/20 Answered by Dwaipayan Shikari last updated on 17/Sep/20 $${f}\left({x}\right)=\underset{{n}\rightarrow\infty} {\mathrm{lim}}\:\underset{{k}=\mathrm{0}} {\overset{{n}} {\sum}}\frac{{f}^{\left({k}\right)} \left(\mathrm{0}\right)}{{k}!}{x}^{{k}} \\ $$$${f}\left({x}\right)={e}^{−\mathrm{7}{x}} \\…

if-f-x-x-2-x-R-then-1-the-function-is-one-to-one-2-the-function-is-not-one-to-one-chose-1-or-2-

Question Number 114167 by mohammad17 last updated on 17/Sep/20 $${if}\:{f}\left({x}\right)={x}^{\mathrm{2}} \:\:\:,\forall{x}\in{R} \\ $$$${then}\: \\ $$$$\left(\mathrm{1}\right)\:{the}\:{function}\:{is}\left(\:{one}\:−{to}−{one}\right) \\ $$$$ \\ $$$$\left(\mathrm{2}\right)\:{the}\:{function}\:{is}\:{not}\:\left({one}−{to}−{one}\right) \\ $$$$ \\ $$$${chose}\:\left(\mathrm{1}\right)\:{or}\:\left(\mathrm{2}\right) \\ $$…

if-u-5x-2-1-y-u-3-then-dy-dx-1-dy-du-du-dx-2-dy-du-du-dx-chose-1-or-2-

Question Number 114166 by mohammad17 last updated on 17/Sep/20 $${if}\:{u}=\mathrm{5}{x}^{\mathrm{2}} +\mathrm{1}\:,\:{y}={u}^{\mathrm{3}} \:{then}\:\frac{{dy}}{{dx}}=? \\ $$$$\left(\mathrm{1}\right)\:\frac{{dy}}{{du}}.\frac{{du}}{{dx}}\:\:\:\:\:\left(\mathrm{2}\right)\frac{{dy}}{{du}}/\frac{{du}}{{dx}} \\ $$$$ \\ $$$${chose}\:\left(\mathrm{1}\right)\:{or}\:\left(\mathrm{2}\right) \\ $$ Commented by bobhans last updated…